How to change input value dynamically - php

Question

I want to change an input value depending on a $_POST variable. Something like this:
<?php if ($_POST['yourname'] != "")
{
$('input[name=yourname]').attr('title', $_POST['yourname']);
} ?>
But it doesn't work. How can I do that?
Thanks!
EDIT: I have this input:
<input class="clearme" name="yourname" type="text" title="Insert your name" />

Answer 1

Add directly to html:
<input class="clearme" name="yourname" type="text" title="Insert your name" value="<?php echo isset($_POST['yourname']) ? $_POST['yourname'] : ''; ?>" />

Answer 2

You can't use javascript in PHP. PHP runs on the server, while javascript runs in the clients browser.
You need to do this in pure javascript, not PHP.

Answer 3

Try this in the one file, replacing 'name_of_cur_file.php' with the name of the current php file.:
<?php
if($_POST['yourname'] > ""){
$yourname = $_POST['yourname'];
}else{
$yourname = ""; // set to avoid errors
}
?>
<form action="name_of_cur_file.php" method="post">
<input type="text" value="<?php echo $yourname;?>" />
<input type="submit" value="go" />
</form>
WARNING!!! - Lacking any validation for this example!!!

Answer 4

If you want the code sent from the server to execute then:
<?php if ($_POST['yourname'] != "")
{
<script type="text/javascript">
$(document).ready(function () {
$('input[name=yourname]').attr('title', $_POST['yourname']);
});
</script>
} ?>

Answer 5

You have jquery code in php.You have complete first php tag then you have write your jquery code in script code like
<?php if ($_POST['yourname'] != "")
{
?>
<script>
$('input[name=yourname]').attr('title', $_POST['yourname']);
</script>
<?php
} ?>
You can also write php code only like
<?php
$title="Insert your name";
if ($_POST['yourname'] != "")
{
$title=$_POST['yourname'];
} ?>
<input class="clearme" name="yourname" type="text" title="<?php echo $title; ?>" />