PHP string words to array [closed] - php

Question

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Closed 10 years ago.
I need to take only full words from a string i mean full words = words with more then 4 chars.
Example of a string:
"hey hello man are you going to write some code"
I need to return to:
"hello going write some code"
Also i need to trim all of these words and put them into a simple array.
Is it possible?

Answer 1

You could use a regular expression to do it.
preg_replace("/\b\S{1,3}\b/", "", $str);
You could then put them into an array with preg_split().
preg_split("/\s+/", $str);

Answer 2

Use str_word_count() http://php.net/manual/fr/function.str-word-count.php
str_word_count($str, 1)
Will return you a list of words, then count the ones with more than n letters using strlen()
The big advantage of using str_word_count() over other solutions such as preg_match or explode is that it will account for the punctuation and discard it from the final list of words.

Answer 3

Depending on your full requirements and if you need the string array unmodified too, you could use explode for this, something like this would get your words into an array:
$str = "hey hello man are you going to write some code";
$str_arr = explode(' ', $str);
Then you can use array_filter to remove the words you don't want, like so:
function min4char($word) {
return strlen($word) >= 4;
}
$final_str_array = array_filter($str_arr, 'min4char');
Otherwise if you don't need the unmodified array, you can use a regular expression to get all matches that are above a certain length using preg_match_all, or replace out the ones that are using preg_replace.
One final option would be to do it the basic way, use explode to get your array as per the first code example, and then loop over everything using unset to remove the entry from the array. But then, you'd also need to reindex (depending on your subsequent usage of the 'fixed' array), which could be inefficient depending on how large your array is.
EDIT: Not sure why there are claims that it does not work, see below for output of var_dump($final_str_array):
array(5) { [1]=> string(5) "hello" [5]=> string(5) "going" [7]=> string(5) "write" [8]=> string(4) "some" [9]=> string(4) "code" }
#OP, to convert this back to your string, you can simply call implode(' ', $final_str_array) to get this output:
hello going write some code

Answer 4

First, put them into an an array:
$myArr = explode(' ', $myString);
Then, loop through and assign only those with a length of 4 or greater to a new array:
$finalArr = array();
foreach ($myArr as $val) {
if (strlen($val) > 3) {
$finalArr[] = $val;
}
}
Obviously, if you have commas and other special characters in your string, it gets trickier, but for a basic design, I think this gets you moving in the right direction.

Answer 5

$strarray = explode(' ', $str);
$new_str = '';
foreach($strarray as $word){
if(strlen($word) >= 4)
$new_str .= ' '.$word;
}
echo $new_str;
Code Output

Answer 6

No loops required, no nested function calls, no temporary arrays. Just 1 function call and a very simple regex.
$string = "hey hello man are you going to write some code";
preg_match_all('/\S{4,}/', $string, $matches);
//Printing Values
print_r($matches[0]);
See it working

Answer 7

<?php
$word = "hey hello man are you going to write some code";
$words = explode(' ', $word);
$new_word;
foreach($words as $ws)
{
if(strlen($ws) > 4)
{
$new_word[] = $ws;
}
}
echo "<pre>"; print_r($new_word);
?>

Answer 8

You can use explode() and array_filter() with trim() + strlen() to achieve this. Try it and post your code if you're stuck.