How to change VAR? - php

Question

I've got a part of a PHP script, but it gives a T_CLASS error.
But i'm not sure how to convert the VAR element into a php5 compliant code...
Can somebody help me?
<?php // Defining the "calc" class
if (!class_exists('calc'))
class calc {
var $number1;
}
?>
p.s. this is just part of a bigger code, but it keeps saying: "PHP Syntax Check: Parse error: syntax error, unexpected T_CLASS in your code on line 3". So the error should be either in "class calc {" or in "var $number1;". Please help :P
I had to place the entire code. Just adding the brackets gave me a new error.
<?php // Defining the "calc" class
if (class_exists('calc')) {
class calc {
var $number1;
}
}
function boek($number1)
{
$result =$number1 * 2;
echo "Om een tekst van $number1 pagina's te redigeren, rekenen wij: <strong>€ $result,-*</strong></br>";
echo "<small>*Deze prijs is slechts een indicatie. Om een vrijblijvende offerte aan te vragen kunt u gebruikmaken van het contactformulier onderaan de pagina. <br/><span style=\"text-decoration: underline;\">Let op: studenten krijgen op vertoon van hun studentenpas 25% korting.</span></small>";
}
}
//Creating object of class
$calc = new calc();
?>
<style type="text/css">
.calcbutton {
Cursor: pointer;
display: block;
text-indent: -5000px;
width: 136px;
height: 44px;
border: none;
background-image: url('http://www.mijncreaties.com/wp-content/themes/GoedVerwoord/images/buttons.png');
background-repeat: no-repeat;
}
.calcbutton {background-position: top left;}
.calcbutton:hover {background-position: center left;}
.calcbutton:active {background-position: bottom left;}
</style>
<form name="calc" action="" method="POST">
<table>
<tr>
<td>Aantal pagina's: </td>
<td><input type="text" style="padding-left: 3px;" class="calc-form wpcf7-text" name="value1" value="0" onfocus="if (this.value == '0') {this.value = '';}" onblur="if (this.value == '') {this.value = '0';}"><br>
<input type="hidden" name="oper" value="boek">
</td>
</tr>
</table>
<input type="submit" value="Bereken prijs" name="submit" class="calcbutton">
</form>
<?
if($_POST['submit']){
$number1 = $_POST['value1'];
$oper = $_POST['oper'];
if(!$number1){
echo "<p><font color=\"red\">Vul a.u.b. een getal in.</font></p>";
}
if($oper == "boek"){
$calc->boek($number1);
}
}
?>

Answer 1

Try wrapping it in an extra set of braces:
<?php // Defining the "calc" class
if (!class_exists('calc')) {
class calc {
var $number1;
}
}
?>
Editted to add:
if (class_exists('calc')) {
class calc {
var $number1;
function boek($number1)
{
$result =$number1 * 2;
echo "Om een tekst van $number1 pagina's te redigeren, rekenen wij: <strong>€ $result,-*</strong></br>";
echo "<small>*Deze prijs is slechts een indicatie. Om een vrijblijvende offerte aan te vragen kunt u gebruikmaken van het contactformulier onderaan de pagina. <br/><span style=\"text-decoration: underline;\">Let op: studenten krijgen op vertoon van hun studentenpas 25% korting.</span></small>";
}
}
}
Your closing bracket was in the wrong place.

Answer 2

Wrap brackets around that if:
<?php
// Defining the "calc" class
if (!class_exists('calc')){
class calc {
var $number1;
}
}
?>
You will have the same issue when conditionally creating functions:
<?php
if (!function_exists('new_function')){
function new_function{
return 'awesome';
}
}
?>