how to pass multiple values to a function in jquery to - php

Question

I have this list of comments that i want to remove from database using AJAX, and fadeout from current view with Javascript.
I call this function removeComment() which sends ID of div to be removed to server ( ID is also row id in database )
The problem i have is, after i run the function first time, it stops working.
jquery code
function removeComment(PostId) {
var commentid = 'com' + PostId;
$(document).ready(function() {
$(commentid).fadeToggle('slow');
// send to php script
$.ajax({
type: 'POST',
cache: false,
url: 'actions/adminProcessor.php',
data: 'action=removeComment' + '&PostId=' + PostId,
success: function(done) {
alert(done);
}
});
}); // <-- Sorry, was missing a '}'
}
and below is the html of the comment list and how the functionis called
<div class="comments" id="com3">
<label><admin>UD</admin></label>Remove
<span>17/09/12</span>
<p>adfadfadfadf</p>
</div>
<div class="comments" id="com3">
<label><admin>UD</admin></label>Remove
<span>17/09/12</span>
<p>adfadfadfadf</p>
</div>
please i would like to know where i got it wrong
below is the php script
if($action == "removeComment"){
extract($_POST) ;
$query = "DELETE FROM comments WHERE id = '$cId'" ;
$result = mysql_query($query);
}

Answer 1

You should not wrap your behavior into a $(document).ready function. You should read more about what $(document).ready means. This code should work now:
function removeComment(PostId) {
var commentid = 'com' + cid;
var coms = document.getElementById(commentid);
$(coms).fadeToggle('slow');
$.ajax({
type: 'POST',
cache: false,
url: 'actions/adminProcessor.php',
data: 'action=removeComment' + '&PostId=' + PostId,
success: function (done) {
alert(done);
}
});
}