For example:
$string="<aa>xyz<bb>123<ccc>";
I want to get the substring 'xyz' from $string.Is it possible?
Simply you can use strip_tags to get xyz
<?php
echo strip_tags('<aa>xyz<bb>');
?>
strip_tags is only striping tags. Use it only if this meets your requirement.
You can also use a regex to explode the string into an array. this would give you the substring you want in $arr[0]
This will work regardless what the tags are, and allow you to easily which ever substring you want.
<?php
$string="<aa>xyz<bb>123<ccc>";
$arr = preg_split("/<[^>]+>/", $string, 0, PREG_SPLIT_NO_EMPTY);
var_export($arr);
yes it is possible
$string="<aa>xyz<bb>";
echo substr($string,4,4);
you can also do this by strip_tags() it Strip HTML and PHP tags from a string
Use preg_match with <aa>(.*?)</bb> , it will be the first match.
With regular expressions you will also be able to get other matches in your string also ..
Related
I'm a regex-noobie, so sorry for this "simple" question:
I've got an URL like following:
http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx
what I'm going to archieve is getting the number-sequence (aka Job-ID) right before the ".aspx" with preg_replace.
I've already figured out that the regex for finding it could be
(?!.*-).*(?=\.)
Now preg_replace needs the opposite of that regular expression. How can I archieve that? Also worth mentioning:
The URL can have multiple numbers in it. I only need the sequence right before ".aspx". Also, there could be some php attributes behind the ".aspx" like "&mobile=true"
Thank you for your answers!
You can use:
$re = '/[^-.]+(?=\.aspx)/i';
preg_match($re, $input, $matches);
//=> 146370543
This will match text not a hyphen and not a dot and that is followed by .aspx using a lookahead (?=\.aspx).
RegEx Demo
You can just use preg_match (you don't need preg_replace, as you don't want to change the original string) and capture the number before the .aspx, which is always at the end, so the simplest way, I could think of is:
<?php
$string = "http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx";
$regex = '/([0-9]+)\.aspx$/';
preg_match($regex, $string, $results);
print $results[1];
?>
A short explanation:
$result contains an array of results; as the whole string, that is searched for is the complete regex, the first element contains this match, so it would be 146370543.aspx in this example. The second element contains the group captured by using the parentheeses around [0-9]+.
You can get the opposite by using this regex:
(\D*)\d+(.*)
Working demo
MATCH 1
1. [0-100] `http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-`
2. [109-114] `.aspx`
Even if you just want the number for that url you can use this regex:
(\d+)
I'm trying to write a very simple markup language in PHP that contains tags like [x=123], and I need to be able to match that tag and extract only the value of x.
I'm assuming the answer involves regex but maybe I'm wrong.
So if we had a string:
$str = "F9F[x=]]^$^$[x=123]#3j3E]]#J";
And a regular expression to match:
/^\[x=.+\]$/
How would we get only the ".+" portion of the matching string into a variable?
You can use preg_match to search a string for a regular expression.
Check out the documentation here: http://www.php.net/manual/en/function.preg-match.php for more information on how to use it (as well as some examples). You might also want to take a look at preg_grep.
Following code should work for you:
$str = "F9F[x=]]^$^$[x=123]#3j3E]]#J";
if (preg_match('~\[x=(?<valX>\d+)\]~', $str, $match))
echo $match['valX'] . "\n";
OUTPUT:
123
so there's a string,
<?php
$string = <<<STR
/\!##$%^&*()?.,djasijdiwqpk,=-c./zcxzo123154897kp02ldz.,world90iops02&&&8ks
STR;
I want to replace everything to NULL, except word "world" and number 1 and 3,
I just want to get "world13" or "world31" from that string USING regular expressions
I have already implemented basic solution,
via strpos() and substr() and this is works as excepted. But I need to do this via RegExp
The question is:
Is it possible to extract that word using RegEx?
~(world(?:(31|13))~i. The 'i' makes the regex case insensitive. The ?: is there so it doesn't put it in the matches array in a separate result. Wouldn't say it's very complex, by the way :) If you want every 1 and 3 in there, you can use ~(world|1|3)~i.
Is it possible to extract that word using RegEx?
Yes. You can use this regular expression:
(world)
I know, that, But I can't extract world13 or world31
Ah, I understand! You can use:
$string = preg_replace('/.*/s', 'world13', $string);
A simple solution is to find things you need and then join them to a string.
preg_match_all('/world|[13]/', $string, $matches);
$ret = join($matches[0]);
i'v got such string <>1 <>2 <>3
i want remove all '<>' and symbols after '<>' i want replace with such expression like www.test.com/1.jpg, www.test.com/2.jpg, www.test.com/3.jpg
is it possible to do with regex? i only know to find '/<>.?/'
preg_replace('/<>(\d+)/g', 'www.test.com/bla/$1.jpg', $input);
(assuming your replaced elements are just numbers. If they are more general, you'll need to replace '\d+' by something else).
str_replace('<>', 'www.test.com/', $input);
// pseudo code
pre_replace_all('~<>([0-9]+)~', 'www.test.com/$1.jpg', $input);
$string = '<>1 <>2 <>3';
$temp = explode(' ',preg_replace('/<>(\d)/','www.test.com/\1.jpg',$string));
$newString = implode(', ',$temp);
echo $newString;
Based on your example, I don’t think you need regex at all.
$str = '<>1 <>2 <>3';
print_r(str_replace('<>', 'www.test.com/', $str));
Regex's allow you to manipulate a string in any fashion you desire, to modify the string in the fashion you desire you would use the following regex:
<>(\d)
and you would use regex back referencing to keep the values you have captured in your grouping brackets, in this case a single digit. The back reference is typically signified by the $ symbol and then the number of the group you are referencing. As follows:
www.test.com/$1
this would be used in a regex replace scenario which would be implemented in different ways depending on the language you are implementing your regex replace method in.
I have a feeling that I might be missing something very basic. Anyways heres the scenario:
I'm using preg_replace to convert ===inputA===inputB=== to inputA
This is what I'm using
$new = preg_replace('/===(.*?)===(.*?)===/', '$1', $old);
Its working fine alright, but I also need to further restrict inputB so its like this
preg_replace('/[^\w]/', '', every Link or inputB);
So basically, in the first code, where you see $2 over there I need to perform operations on that $2 so that it only contains \w as you can see in the second code. So the final result should be like this:
Convert ===The link===link's page=== to The link
I have no idea how to do this, what should I do?
Although there already is an accepted answer: this is what the /e modifier or preg_replace_callback() are for:
echo preg_replace(
'/===(.*?)===(.*?)===/e',
'"$1"',
'===inputA===in^^putB===');
//Output: inputA
Or:
function _my_url_func($vars){
return ''.$vars[2].'';
}
echo preg_replace_callback(
'/===(.*?)===(.*?)===/',
'_my_url_func',
'===inputA===inputB===');
//Output: inputB
Try preg_match on the first one to get the 2 matches into variables, and then use preg_replace() on the one you want further checks on?
Why don't you do extract the matches from the first regex (preg_match) and treat thoses results and then put them back in a HTML form ?