PHP AJAX Image Upload Example Not Uploading - php

Question

My code produces no errors on the console. When I click the upload button, nothing happens. There is a post sent to itself, as instructed in the tutorial I used but the image is not uploaded to my folder and it is not displayed on my page. Barring the fact I know I should use jquery (I will make the transition once I get it to upload to the folder) what is wrong with my code?
<?php
if (!empty($_FILES)) {
$name = $_FILES['file']['name'];
if ($_FILES['file']['error'] == 0) {move_uploaded_file($_FILES['file']
['tmp_name'], "post_images/" . $name))}
}
?>
<script type="text/javascript">
var handleUpload = function (event) {
event.preventDefault();
event.stopPropagation();
var fileInput = document.getElementById('file');
var data = new FormData();
data.append('file', fileInput.files[1]);
var request = new XMLHttpRequest();
request.upload.addEventListener('progress', function(event){
if (event.lengthComputable)
{
var percent = event.loaded / event.total;
var progress = document.getElementById('upload_progress');
while(progress.hasChildNodes()) {
progress.removeChild(progress.firstChild);
}
progress.appendChild(document.createTextNode(Math.round(percent * 100) +
'%'));
}
});
request.upload.addEventListener('load',function(event) {
document.getElementById('upload_progress').style.display = 'none';
});
request.upload.addEventListener('error', function(event) {
alert('Upload failed');
});
request.open('POST', 'upload.php');
request.setRequestHeader('Cache-Control', 'no-cache');
document.getElementById('upload_progress').style.display = 'block';
request.send(data);
};
window.addEventListener('load', function(event) {
var submit = document.getElementById('submit');
submit.addEventListener('click', handleUpload);
});
</script>
<div id="uploaded">
<?php
if (!empty($name)) {
echo '<img src="post_images/' . $name . '" width="100" height="100" />';
}
?>
</div>
<div id="upload_progress"></div>
<div>
<form action="" method="post" enctype="multipart/form-data">
<div>
<input type="file" id="file" name="file" />
<input type="submit" id="submit" value="upload" />
</div>
</form>
</div>

Answer 1

There is only one file in a non- multiple file input element, fileInput.files[1] attempts to use the second file.
data.append('file', fileInput.files[0]);