Why Logic in __destruct - php

I found the following code. Is this a specific pattern or what could be the reason to structure code like that - or is it just bogus?
class ExportCSV extends Export
{
// some private and public vars
public function __construct($arg)
{
// [...]
new CustomerReport($this);
}
public function procCallback($proc)
{
switch($proc){
case "customer":
new InvoiceReport($this);
break;
case "invoice":
new PrepaymentReport($this);
break;
case "prepayment":
new RefundReport($this);
break;
case "refund":
$this->sendMail();
break;
}
}
}
class CustomerReport extends Foobar
{
private $inst;
public function __construct($inst)
{
$this->inst = $inst;
$this->exportCustomers($inst->from, $inst->to);
}
public function __destruct()
{
$this->inst->procCallback("customer");
}
}

As raina77ow said, is an implementation of a pattern. Besides, you must to consider what do you want to do once the object is destroyed in you application life cycle. Let's consider the following example (please, it is just an example!)
Let's suppose you are trying to implement an MVC pattern and you are the guy who should make the "View part". So what do you need? you need grab all the variables generated in the request and once they're ready to be used in the response (thru the controllers and Models) they should be rendered into the views. One approach (among others, of course) is the implementation of this pattern (Observer) through the magic method __destruct(). For example something like this:
// your code here
public function __destruct() {
$this->grabAllTheVarsAndRenderThem();
// or you can include the views file
extract($this->viewParams);
include_once('my_file_view.php');
}
This is just an example, and btw, is very verbosed (as you can see in the method name). But the idea behind the example is, bind some behavior before the object is destroyed.
Of course there are a lot of situations where you can -and you should- implement this pattern, this is just an example to explain the sense to use this magic method.
Hope it helps!

I wouldn't call the shown code 'Logic' in destructor: it's actually an implementation of Observer pattern.
I assume here it works like that: first, when a CustomerReport object is created, its constructor will register some observing objects (probably with $this->exportCustomers method, which body is not shown here for some reasons) in its $inst field. Then these observing objects will be notified each time this object's state is changed. And, of course, destruction of this object can be viewed as changing of its state too. )

It could be that the original developer of this part of the code doesn't trust the users (that could be the same person too (-: ) of these libraries and want to make sure that every CustomerReport created will do call the collaborator objects (they could be releasing some lock or other critical resource).

Related

optional dependencies within a class

I'm looking for some direction regarding the following, I'm new to OOP and getting there but think either my lack of understanding is causing me to get stuck in a rabbit hole or I'm just over thinking things too much and being anal.
basically i have a main class called "CurlRequest" which sole purpose is to perform curl requests, providing a url and params it returns me some html. This class works and functions as intended and I'm happy with that.
I use this class for a few projects but for one I then wanted to track the performance of my requests made. attempted, failed, passed etc, so i created a static class for this which manages all my counters. I place counter references like the following at different areas in my CurlRequest class.
PerformanceTracker::Increment('CurlRequest.Attempted');
PerformanceTracker::Increment('CurlRequest.Passed');
PerformanceTracker::Increment('CurlRequest.Failed');
I have around 10 or so of these with my class tracking all kinds of things during the curl request and i also use my PerformanceTracker class in other classes i made.
However like mentioned i only wanted to do this for one of my projects, so find my self in the situation of having my original CurlRequest class and an altered one with performance counters in it.
My question is, is their a way i can use the same class for any project and choose to use the PerformanceTracker class or not. The obvious way i thought of was to pass an $option argument into the class and then have if statements around all the counters, but can't help think its messy.
if ($this->options['perfCounter'] == true ) {
PerformanceTracker::Increment($this->owner . '.CurlRequest.Failed');
}
this also adds a lot of extra code to the class.
I suggest placing the if statement in a separate method
private function handlePerformanceTracker($q)
{
if ($this->options['perfCounter'] == true ) {
PerformanceTracker::Increment($q);
}
}
And call this method instead of your calls to
PerformanceTracker::Increment(...);
Also if you find that you want to track performance differently between your projects it might be useful to change your constructor to accept a callable argument, this way you externalize the actual implementation from the CurlRequest class itself.
public function __construct(..., callable performanceHandler)
Then when you instantiate your class:
$curlRequest = new CurlRequest(..., function($outcome) {
//your implementation
});
You can use inheritance and create a subclass that performs the logging before delegating to the parents methods:
class PerformanceTracker
{
static function Increment($s)
{
echo $s;
}
}
class CurlRequest
{
function get($url){
//preform curl request, save html to variable etc
//dummy vars used here so working example code
$html = 'html here';
$curlError = false;
if($curlError){
$this->error($curlError);
}
return $this->success($html);
}
protected function success($html)
{
return $html;
}
protected function error($curlError)
{
throw new Exception($curlError);
}
}
class LoggingCurlRequest extends CurlRequest
{
function get($url)
{
PerformanceTracker::Increment('CurlRequest.Attempted');
return parent::get($url);
}
function success($html)
{
PerformanceTracker::Increment('CurlRequest.Passed');
return parent::success($html);
}
function error($curlError)
{
PerformanceTracker::Increment('CurlRequest.Failed');
parent::error($curlError);
}
}
$lcr = new LoggingCurlRequest();
$lcr->get('unused in example');
As i have used dummy classes with minimal code to demo the technique the benefit might not be obvious, but in you real code, the methods in the CurlRequest class will be more complex, but the methods in the logging class will remain as two liners, with the log function and the call to the parent method.
Using this technique you can modify the parent class without effecting the derived classes (provided the method signatures dont change), can create other derived classes (how about a CachingCurlRequest) etc.
For the full benefits of OOP you should look into dependency injection and interfaces
From an OOP perspective you could use the 'Null' object pattern. This just means that the dependency used by the CurlRequest class is abstract (possibly an interface?). You would then have Two concrete implementations of PerformanceTracker: the one you have today and one that does nothing (it does not have any behavior). In this way for the one project when you instantiate the CurlRequest class it would use the concrete implementation that has behavior and for all the other projects it would use the concrete implementation with no behavior. All of the code in CurlRequest would look the same but it would have different behavior depending on which concrete implementation it was using

How to create an object using Factory method, instead of supplying alternative object constructor

I am having some trouble applying Factory Pattern.
I have a class that I usually call as Product($modelNumber, $wheelCount). But in a part of legacy code that I am refactoring, I do not have $modelNumber, and only have $productID, where the link between {$modelNumber, $productID} is in the database (or in my case I can hardcode it, as I only have a select few products at the moment).
I need to be able to create my class using $productId, but how?
Using Procedural ways I would have a function that does the lookup, and I would put that function in a file, and include that file anywhere where I need to do the lookup. Thus do this:
$modelNumber = modelLookup($productId)
Product($modelNumber, $wheelCount);
But how do I do it using Object Oriented way?
Note: I have posted a more detailed situation here: https://softwareengineering.stackexchange.com/q/233518/119333 and this is where Factory pattern (and other patterns, like interfaces and function pointer passing) were suggested conceptually, but I hit a wall when trying to implement them in PHP. It kind of seems like a simple question, but I think there are several ways to do it and I am a bit lost as to how. And so I need some help.
I provided a conceptual answer to your SRP problem on Programmers Exchange but I think I can demonstrate it here.
What you basically want is some other object that will do the work to get you the model number of given product ID.
class ProductModelNumberProvider {
public function findByProductId($productId) {
// The lookup logic...
}
}
Your factory should provide a setter constructor so it can make use of this object internally to lookup the model number if needed. So basically you will end up with a ProductFactory similar to this.
class ProductFactory {
private $productModelNumberProvider;
public function __construct(ProductModelNumberProvider $productModelNumberProvider) {
$this->productModelNumberProvider = $productModelNumberProvider;
}
public function getProductByIdAndWheels($productId, $wheels) {
$modelNumber = $this->productModelNumberProvider($productId);
return $this->getProductByModelNumberAndWheels($modelNumber, $wheels);
}
public function getProductByModelNumberAndWheels($modelNumber, $wheels) {
// Do your magic here...
return $product;
}
}
EDIT
On second thought the setter is not the best approach since having a ProductModelNumberProvider instance is mandatory. That is why I moved it to have it injected through the constructor instead.
I can think of something like this:
$factory = new ProductBuilder();
$factory->buildFromProductId($productId, $wheelCount); //uses modelLookup() internally
$factory->buildFromModelNumber($modelNumber, $wheelCount); //just returns Product()
It is basically creating a class on top of the procedural function, but it does separate the logic of creating the class separately from looking up the mapping.

Intercepting method progression based on condition checked by parent class

This is a very basic architectural question and it is thus very hypothetical.
Imagine this simple setup:
I have a class representing a web object, with only one method that renders the object. However, this class extends a parent class which requires certain conditions to be met, so that the method is actually executed (so that the object is being rendered).
Example
class webObject__adminBase {
protected function shouldRender(){
return access::isAdmin();
}
}
class webObject__adminPanel extends webObject__adminBase {
public function invoke(){
if(!parent::shouldRender())
return;
// if still here, render the object
}
}
$panel = new webObject__adminPanel();
$panel->invoke();
The code above serves both: an example plus a practical explanatory approach to the problem.
The issue is: i would like to get around this problem without actually having to call a method in my parent class in the child's rendering method.
I would like to achieve a class design that assures that all i need to do is to extend the parent class webObject__adminBase. Any calls to any methods in my child class should be checked against certain conditions (as in this example systemAccess::isAdmin()) and only render if these conditions are met.
I hope my description is clear.
Since someone actually requested to close this question as "too broad", i decided to rephrase my actual question with a more direct reference to the question title:
Is there a way to intercept the progression (or even execution) of a child's method based on a condition checked for by its parent class (without calling a method on that parent class) ?
Here is one method of doing it, albeit quite simple. I'm sure there are better methods but this one tries to keep to your original methodology.
https://ideone.com/D5hA3H
Render Class
abstract class Render
{
abstract public function main();
public function __construct()
{
}
final public function render()
{
if (!$this->canRender()) return '';
return $this->main();
}
final public function canRender()
{
// Logic here
return true;
}
}
Admin Panel Class
class AdminPanel extends Render
{
public function main()
{
return "Admin Panel";
}
}
Execution
$panel = new AdminPanel();
echo $panel->render();
PeeHaa is right about the naming conventions, it is in the best interest to try and follow a popular coding style which allows you yourself to read code easier and vice versa. You might want to take a look at the PHP-FIG PSR one and two standards which helps in creating consistent code.
PHP The Right Way is also a great website that will help you out the most, it provides information about dependency injection and coding practices amongst other things.

Is my factory an anti-pattern?

I saw this code on a different question - 2nd answer link and the first comment was that it is a static factory anti-pattern and that it violates SRP:
class User {
public static function create($userid) {
// get user from the database
// set $isPartner to true or false
// set $isClient to true or false
// set $isModerator to true or false
if ($isPartner) {
return new Partner($userid);
} elseif ($isClient) {
return new Client($userid);
} elseif ($isModerator) {
return new Moderator($userid);
} else {
return new User($userid);
}
}
}
$person = User::create($userid);
Now I can understand why it violates SRP - because it deals with connecting to the database as well as building the new class, but besides that I'm not sure if I understand why it is an anti-pattern.
I wanted to write a bit of code that seemed quite similar to this so I am now wondering whether to avoid it, this is my code (in pseudo-code):
class DatabaseClass()
{
...deals with getting a result from the database...
}
abstract class User()
{
...base class for all users...
}
class AdminUser extends User(){}
class StaffUser extends User(){}
class BasicUser extends User(){}
class UserFactory()
{
function createUser($privilege)
{
if($privilege=="high")
return new AdminUser($privilege);
else if($privilege=="med")
return new StaffUser($privilege);
else
return new BasicUser($privilege);
}
$db=new DatabaseClass($username,$password);
$result=$db->getUser();
$userfactory=new UserFactory();
$user=$userfactory->createUser($result);
Now at the moment I am not using a static method but would my oop still be considered an anti-pattern?
Especially since I don't really see any difference in then doing something like this instead and it being pretty much the same thing:
$result=DatabaseClass::getUser($username,$password);
$user=UserFactory::createUser($result);
No, it's not an anti-pattern. Personally, I take the term "anti-pattern" with a grain of salt whenever I see it. It's far too easily tossed around by people who don't like your code but can't really articulate why.
The problem with a static factory is that any class which uses the factory must explicitly depend on it. That violates the principle that we should depend on abstractions rather than concretions (the 'D' in SOLID). This makes code using the factory harder to re-use and unit test. But keep in mind that the approach has benefits too. It's easier to write and easier to understand.
Your code is equivalent to a static factory method. The problem in both cases is that the caller must know the concrete class of the factory.
Your factory is not the issue, is the conection to the db i guess.
Other than that, you're using the factory method well.
Upon seen the edit, its for the best that you separate the data access from the factory.
It's not so much an "anti-pattern" as a bad idea from the maintenance perspective.
I would still be ok (not so good but still ok) if you had your data access code inside the factory as long as that code was in a separate class (that is reused across the application for data access) and you just call it to get something you need. In that case it'd be a combination of two patterns, a factory and a facade.
What i'd really pay attenntion to is to find out if the data isn't going to change during the session, if so just go one time to the db an keep the results. If you only create the User (or derived classes) once, make damm sure you only do it once.
That i think is more important that respecting patterns blindly.
PHP has functionality of dynamical class instantiation where class name that should be instantiated could be a variable. The following code works fine:
$classname='User';
$Object=new $classname; //instantiates new User()
This code instantiates that class whose name is stored in $classname variable.
I'm not so well with the Factory Pattern, however, if you want to have some benefit, it could abstract the creation based on persistence variation, e.g. if it's adapting the database for users or not.
class DatabaseUserFactory implements UserFactory
{
private $dbClass;
function __construct(DatabaseClass $dbClass)
{
$this->dbClass = $dbClass;
}
/**
* #return user
*/
function createUser()
{
$result = $db->getUser();
return $this->createUserByPrivilege($result->getPrivilege());
}
private function createUserByPrivilege($privilege)
{
if ($privilege == "high")
return new AdminUser($privilege);
else if ($privilege == "med")
return new StaffUser($privilege);
else
return new BasicUser($privilege);
}
}
$db = new DatabaseClass($username, $password);
$userfactory = new DatabaseUserFactory($db);
// ...
$user = $userfactory->createUser();

unit test a method that creates an object

I'm trying to get my head round Unit Testing and there's one more piece of the jigsaw I need to find.
What I'm trying to do is write tests for the following code. In this case, I've got a really simple Front Controller (written in PHP).
class frontController
{
public function routeRequest($oRequest)
{
$sClassname = $oRequest->getController();
$sMethod = $oRequest->getAction();
$oController = new $sClassname();
$oResponse = $oController->{$sMethod}($oRequest);
return $oResponse;
}
}
The problem I have is because the code creates new objects. I can easily mock the request object so that I can tightly control what it will actually do within my test case. I'm not sure the best way to actually replace the controller with a test double.
This article from IBM suggests having a factory method for creating my controller and then overriding this with a specific class used for testing:
class frontController
{
public function routeRequest($oRequest)
{
$sMethod = $oRequest->getAction();
$oController = $this->createController($oRequest);
$oResponse = $oController->{$sMethod}($oRequest);
return $oResponse;
}
protected function createController($oRequest)
{
$sClassname = $oRequest->getController();
return new $sClassname();
}
}
and then for testing perhaps something like this:
class testFrontController extends frontController
{
public function setMockController($oMockController)
{
$this->oMc = $oMockController;
}
protected function createController($oRequest)
{
return $this->oMockController;
}
}
(note this isn't quite what the article says, but I'm thinking it would be most useful to me if it did this)
Another solution could be to have another class that creates the controller. This would then be a dependent class of the frontController. This way I can replace the factory/creation class during testing with a test double. Something like this:
class frontController
{
public function routeRequest($oRequest, $oControllerFactory)
{
$sMethod = $oRequest->getAction();
$oController = $oControllerFactory->create($oRequest);
$oResponse = $oController->{$sMethod}($oRequest);
return $oResponse;
}
}
class controllerFactory
{
public function create($oRequest)
{
$sClassname = $oRequest->getController();
return new $sClassname();
}
}
I guess the dependency injection could be taken care of in the front controller constructor or via a setter instead of a parameter to the actual "route" method.
I think I prefer option 2.
Is either of these two methods the right way of going about testing this kind of thing?
(perhaps "good way" would be better word here!)
Any thoughts or suggestions on option 1 vs option 2 appreciated or indeed any alternatives. Remember - the key thing is about how to test an object that itself creates other objects as part of its execution.
Thanks!
You might find this article handy.
It discusses how object creation should be separated from the actual running of the application.
I generally find factories to be a good thing to use for this scenario. In addition to the swappability aspect, it means that additional parameters, data, or dependencies required by the object being created can be stored by the factory, and so the object which actually requests the new object doesn't have to know anything about them...
You do not want to use the real controller but a mock, right ?
It seems to me the simplest way to achieve this would be to subclass the request so that it returns the name of a MockController.
I assume you have thought through your assertions so as to define the goal of what exactly you are testing. Keep in mind that unit tests are going to be testing the returns from your methods, which, in this case, is $oResponse (whatever this may be). As a result, your test assertions will be based on this return value. Since I don't know what that return value is from your code snippets, I can only demonstrate an example that you can complete.
I would recommend PHPUnit for your testing as it seems to be the most complete package for PHP imho (many are fans of SimpleTest, as well ... to each their own).
It would look something like this (Please note that I have left out includes for brevity. Read the PHPUnit documentation for more information):
class AimTest extends PHPUnit_Framework_TestCase{
private $_controller = null;
private $_request = null;
public function setUp(){
$this->_controller = new frontController();
//what does this object's type?
$this->_request = new requestObject();
}
public function testObjectCreation(){
/*
* note, that this is only one of several assertions that could
* be made depending on the return value
*/
$return = $this->_controller->routeRequest($this->_request);
//tailor to what you expect your output to be
$this->assertTrue($return == "my expected output");
}
Hope I didn't miss the mark completely on your stated purpose. Moral of the story is that you can only test what your methods return. If you want to test object instantiation from a method, use the instanceof PHP function against a method that returns that object after instantiation.

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