I would like to retrive a TODAY'S data from the database, but I don't know how to do it. I would actually want to get the data from NOT the past 24 hours, I just want today's data (so based on the actual server time).
I would also like to get data which was yesterday. Can anyone help me how to do it?
Sample code:
"SELECT id FROM folk WHERE time = ???"
Thank you in advance!
I think you are looking for this:
"SELECT id FROM folk WHERE DATE(time) = CURDATE()"
time must be a field in you table that holds a reference to the row.
update
To get yesterdays additions:
"SELECT id FROM folk WHERE DATE(time) = CURDATE() - 1"
update 2
To get all additions this month:
"SELECT id FROM folk
WHERE MONTH(time) = MONTH(NOW()) AND YEAR(time) = YEAR(NOW())"
reference: http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html
SELECT id FROM folk WHERE DATE(time) = DATE(NOW());
SELECT id FROM folk WHERE DATE(time) = DATE(DATE_SUB(NOW(), INTERVAL 1 DAY));
provided that 'time' has a proper date-time type
Try something like this>>
SELECT id from folk WHERE DAY( date ) = EXTRACT(DAY from (NOW() - inTERVAL
1 DAY ) )
Refer this link
http://www.webmasterworld.com/forum112/278.htm
As you are using timestamp:
"SELECT id FROM folk WHERE time >= ".mktime(0, 0, 0)
That will select all data since beginning today.
If you want to get all date not for today, you would do
"SELECT id FROM folk WHERE time < ".mktime(0, 0, 0)
To select data from yesterday, you would do:
"SELECT id FROM folk WHERE time < ".mktime(0, 0, 0)." AND time >= ".mktime(0, 0, 0, date('m'), date('d')-1, date('Y'))
If you were to use DATETIME, just for reference, it would be something like:
"SELECT id FROM folk WHERE time >= '".date('Y-m-d').' 00:00:00."'"
Get current date by using something like following query
SELECT *
FROM your_table_name
WHERE DAY('.$colum_name.') = DAY("2018-05-02")';
Related
I have a mysql table orders in that I have a column order_date which is current time stamp(2016-08-17 00:00:00.000000). now I want to select or count the data's entered this month and the previous month, after this I can find the difference between these two months I am using this code and it is not working.
$sql="SELECT * FROM order WHERE order_date > DATE_SUB(NOW(), INTERVAL 1 MONTH)";
$result = $this->db->query($sql);
return $result;
this is not working an mysql error is produced.
Try
$sql="SELECT * FROM order WHERE DATE(order_date) LIKE DATE_SUB(CURDATE(), INTERVAL 1 MONTH)";
$result = $this->db->query($sql);
return $result;
i think this Link[http://sqlhints.com/2015/07/10/how-to-get-difference-between-two-dates-in-years-months-and-days-in-sql-server/] will help you
Use this. Hope it helps what you want. Thanks
$todayDate = date('Y-m-d');
$todayMonth = date("m", strtotime($todayDate ));
$previousMonth = $todayMonth - 1;
$sql = "SELECT * FROM order WHERE MONTH(order_date) BETWEEN '$todayMonth' AND '$previousMonth'";
First, the following is the correct logic to get all values from the current month and all of the previous month:
select *
from orders o
where order_date >= date_sub(date_sub(curdate(), interval day(curdate) - 1 day), interval 1 month);
Then, use conditional aggregation for comparison. Here is an easy way:
select sum(month(order_date) = month(curdate())) as cur_month,
sum(month(order_date) <> month(curdate())) as prev_month,
(sum(month(order_date) = month(curdate())) -
sum(month(order_date) <> month(curdate()))
) as diff
from orders o
where order_date >= date_sub(date_sub(curdate(), interval day(curdate) - 1 day), interval 1 month);
Note: I don't fully see the utility of comparing a partial month (this month) to a full month (last month), but that is what you seem to be asking for. If you are asking for something different, then ask another question with sample data and desired results.
I try to get a list of all records that are older than 1year ago from my database, the field for expired_contract has next information.
expired_contract DATE NOT NULL
So it takes the DATE in the next format: YEAR-MM-DD, next i have the sql that i cant get it working sadly.
$sql = "SELECT *
FROM My_Contracte
WHERE expired_contract >= DATE_SUB(NOW(),INTERVAL 1 YEAR)
ORDER BY id_contract DESC";
I tried a lot of "WHERE" commands but none worked as i expected. Can you help me get this working? I'm looking on this for about 5hours i need exact command to get it worked.
The $sql gets me something but takes it wrong, i get dates like: 2015-10-01, 2016-10-01 and date like 2014-09-30 doesn't show up.
Basically i want to show dates like:
If today is 2015-10-01 i want to see dates older than 1year ago so from 2014-09-30 and not showing dates like 2015-10-01, 2016-10-01.
Maybe do i have to edit something in database?
Looking for your help, thank you!
You have to use lower than instead of greater or equals:
$sql = "SELECT * FROM My_Contracte WHERE expired_contract < DATE_SUB(NOW(),INTERVAL 1 YEAR)
SELECT SUM(impressions) AS impressions FROM My_Contracte where DATE(expired_contract) BETWEEN DATE_SUB( CURDATE( ) ,INTERVAL 1 YEAR ) AND CURDATE( )
SELECT * FROM My_Contracte WHERE (expired_contract NOT BETWEEN DATE_SUB(CURDATE(),INTERVAL 1 YEAR) AND CURDATE()) and expired_contract<=NOW() ;
I am trying to grab the newest records from my table. I want all of the records that happened in the past 7 days. Here is what I have so far to start with.
$query = "SELECT * FROM mlg_logattempts AS a WHERE a.ts = (SELECT MAX(ts) FROM mlg_logattempts AS b WHERE b.ts > NOW() - INTERVAL 5 MINUTE AND b.name = a.name)";
I have used intervals in the past but an unsure how to make this work now. Can someone show me the proper way to request the past 7 days records? I do have a timestamp field.
UPDATE
Unfortunately I realized the command I shared with you. I do not have any of the above fields. The only date field I have is "date". no a or ts.
You could use mysql date_diff() for dates
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_datediff
but since you use timestamps, the interval is a good solution:
b.ts > unix_timestamp(CURDATE()-INTERVAL 7 DAY)
Supposing that the date of login attempt is b.ts and it's formatted like 2013-08-20 03:08:
$past7days = date("Y-m-d H:i:s",strtotime("-7day"));
$query = "SELECT * FROM mlg_logattempts AS a WHERE a.ts = (SELECT MAX(ts) FROM mlg_logattempts AS b WHERE date >= '$past7days' AND b.name = a.name)";
How can i get one day old record from database from server . i have use datetime to insert record. below is how record is look like.
2013-01-15 23:44:02
i have use strtotime('-1 day') but it returns local system time.i want to get one day old record and do some stuff in condition..
Thanx in advance..
where date(date_column) = DATE_sub(NOW(), INTERVAL 1 DAY);
use DATE_ADD
SELECT *
FROM tablename
WHERE DATE(dateCol) = DATE_ADD(CURDATE(),INTERVAL -1 DAY)
DATE_ADD()
SELECT * from table WHERE datefield < DATE_SUB(NOW(), INTERVAL 1 DAY)
You will be archiving this with sql query.
SELECT * FROM tablename WHERE DATE(datefield)=DATE_ADD(CURDATE(),INTERVAL 1 DAY)
CURDATE() will return the current Mysql Server time.
You can use this function DATE_SUB(date,INTERVAL expr type)
http://www.w3schools.com/sql/func_date_sub.asp
Example provided in W3schools
Assume we have the following "Orders" table:
Columns: OrderId, ProductName, OrderDate
Values: 1, Jarlsberg Cheese, 2008-11-11 13:23:44.657
Now we want to subtract 5 days from the "OrderDate" date.
We use the following SELECT statement:
SELECT OrderId,DATE_SUB(OrderDate,INTERVAL 5 DAY) AS SubtractDate
FROM Orders
$yesterday = strtotime('Y-m-d h:i:s','yesterday');
SELECT * FROM tablename WHERE datefield = '$yesterday'
Using PHP/MySQL
I'm trying to create a select statement that gets the data from the least day of the current week (I'm using it to show data on a certain player 'this week'). The week starts on Sunday. Sundays's data may not always exist therefore if the Sunday data isn't found then it would use the next earliest day found, Monday, Tuesday, etc.
My date column is named 'theDate' and the datatype is 'DATE'
The query would need to be something like:
SELECT *
FROM table_name
WHERE name = '$username'
AND [...theDate = earliest day of data found for the current week week]
LIMIT 1
It would return a single row of data.
This is a query I tried for getting the 'this week' data, It doesn't seem to work correctly on Sunday's it shows nothing:
SELECT *
FROM table_name
WHERE playerName = '$username'
AND YEARWEEK(theDate) = YEARWEEK(CURRENT_DATE)
ORDER BY theDate;
This is the query that I'm using to get 'this months' data and it works even if the first day of the months data is not found, it will use the earliest date of data found in the current month/year (this query works perfect for me):
SELECT *
FROM table_name
WHERE playerName = '$username'
AND theDate >= CAST( DATE_FORMAT( NOW(),'%Y-%m-01') AS DATE)
ORDER BY theDate
LIMIT 1
Without trying this, you probably need an inner query:
select *
from table_name tn
where tn.the_date =
(select min(the_date)
from table_name
where WEEKOFYEAR(the_date) = WEEKOFYEAR(CURDATE())
and YEAR(the_date) = YEAR(CURDATE()))
viz, give me the row(s) in the table with a date equal to the earliest date in the table in the current week and year.
Try this
SELECT * FROM table_name WHERE name = '$username'
AND your_data IS NOT NULL
AND WEEK(the_date,0 = WEEK(NOW(),0))
ORDER BY DATE_FORMAT(the_date,'%w') ASC
Try the following, replace YOUR_DATE with the date from the column you want (theDate):
SELECT ADDDATE(YOUR_DATE, INTERVAL 1-DAYOFWEEK(YOUR_DATE) DAY)
FirstDay from dual
Did you try:
SELECT ADDDATE(theDate , INTERVAL 1-DAYOFWEEK(theDate ) DAY) FirstDay
FROM table_name
WHERE playerName = '$username'
ORDER BY theDate DESC
LIMIT 1