What's the simple way to remove more than 1 decimal number from source number .
for example source numbers are :
1st source number is : 56.48216585224
2nd source number is: 93
Output must be :
1st output : 56.4
2nd output: 93
numbers are not static
what's the simple way ?
If you don't want rounding, then:
$number = 56.48216585224;
echo substr($number, 0, strpos($number, '.')+2); // output: 56.4
Otherwise:
Use php round() or number_format()
http://php.net/manual/en/function.round.php
http://php.net/manual/en/function.number-format.php
Examples:
$number = 56.48216585224;
echo number_format($number, 1, '.', ''); // Output: 56.5
echo round($number, 1); // Output: 56.5
I will suggest this PHP code for your requirement:
$n = 56.48216585224;
$m = floor($n * 10) / 10; // $m = 56.4 now
You can try the following
print(quickFormat("56.48216585224"));
print(quickFormat("93"));
function quickFormat($number) {
$number = explode(".", $number);
if (isset($number[1])) {
return $number[0] . "." . $number[1]{0};
} else {
return $number[0] ;
}
}
Output
56.4
93
Related
#if($user->dettagli->facebook_follower >= 1000 && $user->dettagli->facebook_follower <= 999999)
<?php
echo(round($user->dettagli->facebook_follower, 5,PHP_ROUND_HALF_DOWN) . "K");
?>
{{$user->dettagli->facebook_follower / 1000}} K
#endif
Hi could someone please help me. I am using Laravel and trying to display a users Facebook follower count, but I got a little stuck with something. I am taking their int at for example 1589 followers and trying to return in the blade "1.5k". On screen I return either 1589k with this php call or 1.589k. How do I get that number to one decimal place and become only 1.5k??
thank you!
As per the docs
Returns the rounded value of val to specified precision (number of digits after the decimal point). precision can also be negative or zero (default).
You are specifying a precision of 5. You should change this to 1.
Change your function call to:
echo(round($user->dettagli->facebook_follower, 1, PHP_ROUND_HALF_DOWN) . "K");
EDIT: I mis-read the question. This is a function that should handle numbers into the millions.
You would need to use laravel-twigbridge to make the function available in your templates though.
function pretty_number(int $n): string {
$prettyN = $n;
$suffix = '';
$len = strlen((string) $n);
$suffixes = ['K', 'M'];
foreach ($suffixes as $s) {
if ($n < 1000) {
break;
}
$suffix = $s;
$n = $n / 1000;
$prettyN = number_format($n, 1);
}
return $prettyN . $suffix;
}
echo pretty_number(100); // 100
echo pretty_number(999); // 99
echo pretty_number(1589); // 1.6K
echo pretty_number(1600); // 1.6K
echo pretty_number(1589300); // 1.6M
You can use the NumberFormatter. This can be defined in a global place so you only need to use the third line in your blade view.
$a = new \NumberFormatter("en-US", \NumberFormatter::DECIMAL);
$a->setAttribute(\NumberFormatter::MAX_FRACTION_DIGITS, 1);
echo $a->format($user->dettagli->facebook_follower);
I know the following code will remove the numbers are the point.
round($number);
I want to round the numbers as follows
if number is 20.123
I want result 20,
If number is 20.567
I want result 21
Means if value is below .5 , it should remove that value.
If value if .5 or above it should round up.
How ?
Anyone help ?
round($number) will do what you want:
round(20.156); // 20
round(20.651); // 21
Live example
I am sure it's working well.
<?php
$var = 22.443;
$var = number_format($var, 0, '.', '');
echo $var;
?>
function get_decimal_num($number){
$num = explode('.', $number);
return $num[1];
}
$num = 10.5 ; // for example
$val = get_decimal_num($num);
if($val >= 5)
{
$value = (int) $num;
echo $value = $value + 1;
}
if($val < 5)
{
echo $num;
}
Plese check it...
Try this:
use the ceil, floor, explode and substr function to achieve you value.
$num = "20.123";
$arr = explode(".", $num);
if(substr($arr[1], 0, 1) >= 5){
$num = ceil($num);
}else{
$num = floor($num);
}
echo $num;
Result:
20
Also you can use the round function.
round(20.156); // 20
round(20.651); // 21
How to get the number before dot symbol, i try using round() but sometimes give me wrong number for what i need, i have the following calculation, lets say
$Calc = 10/3;
$Calc = 3.333333333333333;
I'm trying to use round() php function
$Calc = 10/3;
$Calc = round(3.333333333333333);
$Calc = 3;
but for example if my result is 3.51+
$Calc = round(3.51);
$Calc = 4;
BUT i just need the 3, not the rest , how can i get that?
you could try with intval() function
echo intval(3.51); // output will be 3
echo intval(10/3); // output will be 3
Use this code:
$Calc = 10/3;
$pos = strpos($Calc, '.');
$Calc = substr($Calc, 0, $pos);
This will give the all the digits before the decimal.
Use floor:
echo floor(3.99); // 3
echo floor(3.023);// 3
echo floor(4.4); // 4
echo floor(9.0); // 9
I have the following numbers:
000000006375 and I want to output 63.75
000000004500 and I want to output just 45
Basically, if the last two numbers are not zero, I wanted to make it a float value wherein a decimal point will be added. But if the last 2 numbers are zeros I just want to output a whole number which in the example is just 45.
I was thinking of casting the numbers to int first but I do not know how to convert it to a float number if there last 2 digits are non-zeros.
You can use this code:
$s = '000000006375';
$i = (int) $s /100; // 63.75
echo "000000006375" / 100;
echo '<br />';
echo "000000004500" / 100;
// Output: 63.75<br />45
For your use case you might just cast it into an integer and divide with 100, like this:
$t1 = "000000006375";
$t2 = "000000004500";
var_dump(myfunc($t1), myfunc($t2));
function myfunc($in) {
$out = (int) $in / 100;
return $out;
}
The output will be something like...
float(63.75)
int(45)
print round('000000006375'/100,2);
print '<br/>';
print round('000000004500'/100,2);
$int = (int)'000000004500';
echo round((substr($int, 0, -2) . '.' . substr($int, -2)),2);
This is one way to do it :)
I hold decimals in a database using DECIMAL(10,5)
I would like to format these numbers according to a few rules:
A zero decimal should display as 0
Show a long decimal (no trailing zero's) with all of it's numbers
When possible, I would like to only show up to 2 decimal places (when there are trailing zeros)
Here are some examples:
The left side corresponds to how the number is stored in database.
The right number is how I would like to display the number in my application.
0.00000 => 0
0.51231 => 0.51231
0.12000 => 0.12
0.40000 => 0.40
0.67800 => 0.678
12.10000 => 12.10
This will work for you:
function format($x){
if(!(int)substr_replace($x, '', $dpos = strpos($x, '.'), 1))
return 0;
else
return str_pad((rtrim($x, '0')), $dpos + 3, '0');
}
Example
I would utilize the number_format function in php to actually do the formatting after you determine the amount of decimal places to the number has.
Source:
http://php.net/manual/en/function.number-format.php
Example Usage:
$number = 1234.56;
// english notation (default)
$english_format_number = number_format($number);
// 1,235
// French notation
$nombre_format_francais = number_format($number, 2, ',', ' ');
// 1 234,56
$number = 1234.5678;
// english notation without thousands separator
$english_format_number = number_format($number, 2, '.', '');
// 1234.57
Well here's one way (I haven't tested it yet so there may be minor errors):
$pattern = '/([0-9]+)\\.{0,1}([0-9]*?)0*$/';
$subject = 12.10000;
$matches = array();
$result = preg_match ($pattern, $subject, $matches);
$number = $matches[1];
if ($matches[2] != 0) {
$number .= '.'.$matches[2];
if ($matches[2] < 10) {
$number .= '0';
}
}
echo $number;
And here's another way (probably a little faster):
$x = 1.000;
$result = (int)$x;
$trimmed = rtrim($x, 0);
if ($trimmed[strlen($trimmed) - 1] != '.') {
if ($trimmed[strlen($trimmed) - 2] == '.') {
$result = $trimmed.'0';
} else {
$result = $trimmed;
}
}
echo $result;
I haven't used it myself, but theres the NumberFormatter class: http://php.net/manual/class.numberformatter.php as part of the Internationalization Functions for this stuff. Using that is a little more involved i think though.
I know this is an old question, but the following quick function I wrote for my own project might help someone looking for this.
function number_format_least_dp($number, $decimal_point = '.', $thousand_seperator = ','){
if (floatval($number) == (int)$number){
$number = number_format($number, 0, $decimal_point, $thousand_seperator);
} else {
$number = rtrim($number, '.0');
$number = number_format($number, strlen(substr(strrchr($number, '.'), 1)), $decimal_point, $thousand_seperator);
}
return $number;
}