i have upload script which does the job for uploading in usual way like browse the file from computer and upload but i want to convert the existing script to upload from url.for example if i paste the url which is direct link of video file it should be uploaded to my server. i can use php copy method and feof to do the job but i want to do with my existing script as several other data are related to my uploading script i tried with above both method but its not working.
converting this code to accept remote url upload
<form enctype="multipart/form-data" id="form1" method="post" action="">
<p><label>Upload videos</label>
<input type="file" name="video">
<span>Only mp4 is accepted</span>
<input type="submit" value="Submit" class="button"></p>
if (!eregi(".mp4$",$_FILES['video']['name'])) {
die("Unavailable mp4 format");
}
$uri = save_file($_FILES['video'],array('mp4'));
function save_file($file) {
$allowed_ext = array('mp4');
$ext = $file['name'];
if (in_array($ext, $allowed_ext)) {
die('Sorry, the file type is incorrect:'.$file['name']);
}
$fname = date("H_i",time()).'_'.get_rand(3);
$dir = date("Ym",time());
$folder = 'uploads/userfiles/'.$dir;
$uri = $folder.'/'.$fname.'.'.$ext;
if (!is_dir($folder))
mkdir($folder, 0777);
if (copy($file['tmp_name'],$uri))
return $uri;
else {
return false;}}
?>
If you're getting a URL, you aren't getting a file upload so you can't just use a file upload script and wish it would work. Just use the copy() function to get the file from the URL and save it to your server.
You should use "http_get" to download files from another server.
$response = http_get($url);
Related
I have a problem loading the file to the server in PHP and HTML using move_uploaded_file () when I put PHP files in this way http://mydomin.com/uploadfile.php succeed the process and if this way http://mydomin.com/uploadfiles/uploadfile.php The the process fails
code php
<?php
if (isset($_FILES['image'])) {
$idApp = uniqid();
$uploadDir = '../images/';
$uploadedFile = $uploadDir . $idApp . ".jpg";
if(move_uploaded_file($_FILES['image']['tmp_name'], $uploadedFile)) {
echo"Success: ".$_FILES['image']['tmp_name']. $uploadedFile;
} else {
echo"error 2";
}
} else {
echo"error 3";
}
?>
code html
<form action="add.php" method="POST" enctype="multipart/form-data">
<input type='file' name='image' id='image'>
<div align='center''><input type='submit' id='myButton' value='add'></div>";
</form>
check your upload path
$uploadDir = '../images/';
Try to use this path './images/' or best use absolute path.
check your script location by using
var_dump(__DIR__)
this will show you where is your .php file is ( also called as absolute path ). Thus simply you can see where you made a mistake to assign a folder for file uploading(image in your case ).
I'm trying to build a basic upload form to add multiple files to a folder, which is processed by PHP.
The HTML code I have is:
<form id="form" action="add-files-php.php" method="POST" enctype="multipart/form-data">
<div class="addSection">Files To Add:<br><input type="file" name="files[]" multiple /></div>
<div class="addSection"><input type="submit" name="submit" value="Add Files" /></div>
</form>
And the PHP to process is:
$file_path = "../a/files/article-files/$year/$month/";
foreach ($_FILES['files']['files'] as $file) {
move_uploaded_file($_FILES["file"]["name"],"$file_path");
}
I can run the PHP without any errors, but the files don't get added to the path folder.
Where am I going wrong with this?
I have a similar code actually in one of my projects. Try it.
foreach ($_FILES['files']['name'] as $f => $name) {
move_uploaded_file($_FILES["files"]["tmp_name"][$f], $file_path);
}
Look at the following page:
http://php.net/manual/en/function.move-uploaded-file.php
EDIT:
Nowhere in the code you provided, does it show that you actually give your file a filename, you simply refer to a path, rather than a path+filename+extension
move_uploaded_file($_FILES["files"]["tmp_name"][$f], $file_path . $name);
modifying my original code sample to be like the second one, should work.
Iterate the $_FILES['files']['error'] array and check if the files are actually uploaded to the server:
$dest_dir = "../a/files/article-files/$year/$month";
foreach ($_FILES["files"]["error"] as $key => $error) {
if ($error == UPLOAD_ERR_OK) {
// The temporary filename of the file stored on the server
$tmp_name = $_FILES["files"]["tmp_name"][$key];
$name = basename($_FILES["files"]["name"][$key]);
// Handle possible failure of the move_uploaded_file() function, too!
if (! move_uploaded_file($tmp_name, "$dest_dir/$name")) {
trigger_error("Failed to move $tmp_name to $dest_dir/$name",
E_USER_WARNING);
}
} else {
// Handle upload error
trigger_error("Upload failed, key: $key, error: $error",
E_USER_WARNING);
}
}
The biggest issue with your code is that you are trying to move $_FILES['files']['name'] instead of $_FILES['files']['tmp_name']. The latter is a file name of temporary file uploaded into the temporary directory used for storing files when doing file upload.
P.S.
Using relative paths is error-prone. Consider using absolute paths with the help of a constant containing path to the project root, e.g.:
config.php
<?php
define('MY_PROJECT_ROOT', __DIR__);
upload.php
<?php
require_once '../some/path/to/project/root/config.php';
$dest_dir = MY_PROJECT_ROOT . "/a/files/article-files/$year/$month";
I have a file: success.jpg
I would like to send this file over an HTTP POST request and have it land in a public directory on my server.
I have a simple HTML form and PHP processor that work if I'm uploading from the browser: php.net/manual/en/features.file-upload.post-method.php
I'm trying to drop the use of a form altogether and just pass data over POST to a URL (e.g. myimageserver.com/public/upload.php).
It seems that I can use the PHP function move_uploaded_file and it even talks about using POST here: http://php.net/manual/en/function.move-uploaded-file.php but it doesn't provide the code which can receive and store a file that has been uploaded with POST.
Has anyone ever done something similar?
If you want to upload using a mobile app for example, you have to send via POST the base64 content of the image with the mimetype or the file extension of it, and then use something like this:
Send the content base64 encoded and urlescaped.
Receive the content and do base64 decode and then urldecode.
Then in PHP just do:
<?php
$base64decodedString = base64_decode(urldecode($_POST['yourInputString']));
$fileName = $_POST['fileNameString'];
file_put_contents($fileName, $base64decodedString);
This will generate a file with the content
You couold read this example http://www.w3schools.com/php/php_file_upload.asp
which basically does something like this:
<?php
$target_dir = "uploads/";
$target_dir = $target_dir . basename( $_FILES["uploadFile"]["name"]);
$uploadOk=1;
if (move_uploaded_file($_FILES["uploadFile"]["tmp_name"], $target_dir)) {
echo "The file ". basename( $_FILES["uploadFile"]["name"]). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
The key is on the $_FILES global array.
To check if there were an error before appliying that example, you could use this example:
if ($_FILES['file']['uploadFile'] === UPLOAD_ERR_OK) {
/**
* Do the upload process mentioned above
**/
} else {
/**
* There were an error
**/
}
This is the basic HTML form to upload files
<form action="" method="POST" enctype="multipart/form-data">
<input type="file" name="myFile" />
<input type="submit" value="Send" />
</form>
How to upload your file?
<?php
$uploaddir = '/www/uploads/'; //physical address of uploads directory
$uploadfile = $uploaddir . basename($_FILES['myFile']['name']);
if(move_uploaded_file($_FILES['myFile']['tmp_name'], $uploadfile)){
echo "File was successfully uploaded.\n";
/* Your file is uploaded into your server and you can do what ever you want with */
}else{
echo "Possible file upload attack!\n";
}
?>
Some details
- How to get the physical address of uploads directory?
Just create an index file into your upload dir and run this code
<?php echo getcwd();?>
It's done, if you need more details, just feel free to ask.
AGAIN THIS IS THE BASIC WAY.
I am making an application on my server, where the user uploads an image through some HTML combined with javascript.
The user finds an image on the computer through
<form action="uploadimage.php" method="post"
enctype="multipart/form-data">
<label for="file">Filnavn:</label>
<input type="file" name="file" id="file" value="100000" />
Then the point behind the javascript, is to validate on the users image
if(picture_headline.value == "" || picture_uploaded.value == "" || !ischecked)
{
// Don't execute, stay on same site
}
else
{
// execute php and upload image
}
the php is an upload image php script
<?php
// The file is being uploaded into the folder "upload"
$target = "/navnesutten.eu/facebook/uploads/";
// add the original filename of our target path
$target = $target . basename( $_FILES['uploaded']['name']) ;
$ok=1;
// Moves the uploaded file into correct folder
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))
{
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded";
}
else {
echo "Sorry, there was a problem uploading your file.";
}
?>
I must say I am a bit confused here, since I have only been working with html, php and javascript for a few days now.
Am I totally off or what?
I found some "simple" examples online, which I put on my server through cuteFTP, but everytime i press upload, the website just sends me to the .php file and says the site doesn't exist.
Like Boann points out you're trying to access a non-existent file in your PHP code ("uploaded" and "uploadedfile" rather than "file" (which is what you named the field in your HTML form)).
But regarding "running PHP from JavaScript": You don't have to. The JavaScript should only return false if the form is invalid. If it's valid you don't need to do anything and the form will submit, in turn running your PHP script:
form.onsubmit = function () {
if (!formIsValid()) {
return false;
}
};
If the form is invalid it won't submit (the return false bit (you could use event.preventDefault() instead)), if it is valid nothing will happen and the form will do what it does (ie submit the data to the server).
Each array key in $_FILES corresponds with the name attribute of a file field in the form, so to match your form it should be 'file' rather than 'uploaded' or 'uploadedfile':
<?php
// The file is being uploaded into the folder "upload"
$target = "/navnesutten.eu/facebook/uploads/";
// add the original filename of our target path
$target = $target . basename( $_FILES['file']['name'] ) ;
$ok=1;
// Moves the uploaded file into correct folder
if(move_uploaded_file($_FILES['file']['tmp_name'], $target))
{
echo "The file ". basename( $_FILES['file']['name']). " has been uploaded";
}
else {
echo "Sorry, there was a problem uploading your file.";
}
Is there a way to upload a file to server using php and the filename in a parameter (instead using a submit form), something like this:
myserver/upload.php?file=c:\example.txt
Im using a local server, so i dont have problems with filesize limit or upload function, and i have a code to upload file using a form
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd">
<html>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" name="fileForm" enctype="multipart/form-data">
File to upload:
<table>
<tr><td><input name="upfile" type="file"></td></tr>
<tr><td><input type="submit" name="submitBtn" value="Upload"></td></tr>
</table>
</form>
<?php
if (isset($_POST['submitBtn'])){
// Define the upload location
$target_path = "c:\\";
// Create the file name with path
$target_path = $target_path . basename( $_FILES['upfile']['name']);
// Try to move the file from the temporay directory to the defined.
if(move_uploaded_file($_FILES['upfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['upfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
}
?>
</body>
Thanks for the help
Image Upload Via url:
//check
$url = "http://theonlytutorials.com/wp-content/uploads/2014/05/blog-logo1.png";
$name = basename($url);
try {
$files = file_get_contents($url);
if ($files) {
$stored_name = time() . $name;
file_put_contents("assets/images/product/$stored_name", $files);
}
}catch (Exception $e){
}
If you're doing this localy do you have the need to use "upload" mechanisms? otherwise if you're sending something externaly you could use cURL to upload the file, and run the PHP script on the CLI, quick google: http://dtbaker.com.au/random-bits/uploading-a-file-using-curl-in-php.html
if you want to use url to send the name of the file like below:
www.website.com/upload.php?hilton_plaza_party.jpg
There is a script to do that. Here: http://valums.com/ajax-upload/