Get first value from array - php

Question

I have an PHP array that has saved users steps:
array(
'step_1' => 1,
'step_2' => 1,
'step_3' => 0,
'step_4' => 0,
'step_5' => 0
);
So, my user do step_1, and step_2, but he don't do other steps.
Now, i want to get name of first step that he don't do, it's "step_3" in this example.
But if array looks that:
array(
'step_1' => 1,
'step_2' => 1,
'step_3' => 1,
'step_4' => 1,
'step_5' => 0
);
I want to get "step_5", than i know that user don't do step_5 and i can, for exapmle redirect them to specify page. How can i get it?

Answer 1

You could use array_search()
See In Action
<?php
$array = array(
'step_1' => 1,
'step_2' => 1,
'step_3' => 1,
'step_4' => 0,
'step_5' => 0
);
$key = array_search(0, $array); // $key = step_4;
echo $key;
?>

Answer 2

You can use reset($array);
http://php.net/manual/en/function.reset.php
Return Values
Returns the value of the first array element, or FALSE if the array is empty.
Edit:
You can use array_search(0,$array);
That will return you the key of first found var. (step_5) in your case.

Answer 3

You can try
$step = array(
'step_1' => 1,
'step_2' => 1,
'step_3' => 0,
'step_4' => 0,
'step_5' => 0
);
var_dump(__missing($step));
var_dump($step);
Output
string 'step_3' (length=6)
array
'step_1' => int 1
'step_2' => int 1
'step_3' => int 1
'step_4' => int 0
'step_5' => int 0
Example 2
$step = array(
'step_1' => 1,
'step_2' => 1,
'step_3' => 1,
'step_4' => 1,
'step_5' => 1
);
var_dump(__missing($step));
var_dump($step);
Output
string 'step_1' (length=6)
array
'step_1' => int 1
'step_2' => int 0
'step_3' => int 0
'step_4' => int 0
'step_5' => int 0
Function used
function __missing(&$array) {
$left = array_filter($array, function ($var) {
return ($var == 1) ? false : true;
});
if (! empty($left)) {
$key = key($left);
$array[$key] = 1;
return $key;
} else {
array_walk($array, function (&$var) {
return $var = 0;
});
$key = key($array);
$array[$key] = 1;
return $key;
}
}