PHP Get Experience by Level - php

Question

I have this piece of code that loops 1 through 99 and is a formula.
function getExperienceByLevel ($maxLevel)
{
$levels = array ();
$current = 0;
for ($i = 1; $i <= $maxLevel; $i++)
{
$levels[$i - 1] = floor ($current / 4);
$current += floor($i+300*pow(2, ($i/9.75)));
}
return $levels;
}
First you initiate it like so $aLevels = getExperienceByLevel(99); then to see how much EXP you need to get to level 6 you do this echo $aLevels[5]; since it's an array.
Now I'm trying to do reverse. Get Level by EXP.
function getLevelByExp($exp)
{
$myLevel = 0;
$aLevels = getExperienceByLevel(99);
for ($i = 1; $i < 100; $i++)
{
if ($exp > $aLevels[$i-1])
{
return $myLevel;
}
}
}
When called upon getLevelByExp(1124); or any number inside, it seems to return a zero. But it seems to work when you put echos inside that statement.
Like instead of return $myLevel do echo "You are up to level $i<br />"; and it will go all the way up to the current level you've gained EXP for.
But still.. doesn't work when I want to simply return a number.

Answer 1

This seems to work better than your function:
function getLevelByExp($exp)
{
$aLevels = getExperienceByLevel(99);
for ($i = 0; $i <= 99; ++$i)
{
//echo "cmp $exp >= aLevels[$i]={$aLevels[$i]}\n";
if ($exp <= $aLevels[$i])
return $i - 1;
}
return -1;
}
It needs improvement for the edge cases, such as when $exp is zero.

Answer 2

Return $i instead because it always '0'
if ($exp > $aLevels[$i-1]) {
return $i;
}

Answer 3

You never change $myLevel, so it will always stay at 0.
Try returning $i instead of $myLevel, as $i is actually changing:
function getLevelByExp($exp) {
$aLevels = getExperienceByLevel(99);
for ($i = 1; $i < 100; $i++) {
if ($exp > $aLevels[$i-1]) {
return $i;
}
}
}