Need input on a dynamic query output script - php

Question

I have a homepage that has a bunch of images as links to other pages that has info about that image.
Image Name: $varExampleNAME
Damage: $varExampleDMG
Health: $varExampleHP
Mana: $varExampleMP
So the only info that will change on this page will be the variables.
What I want is to run one query script so that depending on the $fileName of the $currentPage
it grabs that row from the table if the $fileName matches a certain row name.
This is the script to find out what my fileName is:
//include database connection file
include_once 'connect_to_db.php';
$currentFile = $_SERVER["SCRIPT_NAME"];
$img = array_pop(explode("/", $currentFile));
$fileName$ = basename($img, ".php").PHP_EOL;
I'm having problems with the actual query script. Can anyone shed some light on how this will be done?
My table name is image_Name
Columns include id, name, damage, health, mana.

Answer 1

You should design your tables in order to fit your needs, in this case to retrieve a row based on a parameter.
If the name field of the table is consistent with the script filenames, you should do [using PDO]:
// Create a connection handler - provide your credentials
$dbh = new PDO('mysql:host=localhost;dbname=yourDbNane','username','password');
// Prepare the query with a placeholder
$dbh->prepare('SELECT * FROM image_Name WHERE name = ?');
// Fill the placeholder with the filename
$dbh->execute( array($fileName) );
// Fetch the result, you are done!
$img = $dbh->fetch();