This question already has answers here:
Get content between two strings PHP
(7 answers)
Closed 4 years ago.
I am trying to replace the content between two words using php. The content between the two words is different so I can't use tradition str_replace. I want to replace the content between two words for example:
I would like to replace **some string of text** between two words
change to:
I would like to replace between two words
You can see that I removed all the wording between "some" and "text". Again I cannot use regular str_replace because the text between the two words may differ. For example it may say:
I would like to replace **some words of text** between two words
change to:
I would like to replace between two words
The regex is simple: /some .*? text/
Just replace it with the empty string.
According to your question, only the inner part of your string changes. If that is the case it's rather trivial, because you already have the solution: You do not need to replace it, but you just need to not take it over:
$result = substr($string, 0, $startlen) . substr($string, -$endlen);
Probably this helps you to find some more "resolution angles" for such problems.
Related
This question already has answers here:
What does the $1$2$4 mean in this preg_replace?
(3 answers)
Closed 4 years ago.
I want to loop through an array converting specific key/value pairs that contain markup to HTML.
So an example value for $comment['comment_text'] would be:
This has *bolded* text
And should become:
This has <strong>bolded</strong> text
Here's what I've tried:
$pattern = "/\*\b.*?\b\*/i";
$newComment = preg_replace($pattern, "<strong>$&</strong>",
$comment['comment_text']);
And what I get:
This has $& text
I realize I'm mashing up Javascript with PHP, but reading about back references in PHP hasn't made things any clearer.
My strings may have multiple bolded (in markup) instances...
Any help appreciated.
UPDATE:
Apologies - I didn't realize that Stackoverflow was converting asterisks to italics. I converted the example to code.
Also, my confusion came down to the use of $0 vs. $1. Which I still don't fully understand. I thought the numbers referred to the matches in the string...so if you had 5 instances you could refer to them by $0 through $4.
If you use $0 you get:
This has <strong>*bolded*</strong> text
But if you use $1 you get the desired result.
Do this.
$pattern = "/\*\b(.*?)\b\*/";
$newComment = preg_replace($pattern, "<strong>$1</strong>", $comment['comment_text']);
Here $1 refers to the group 1 match. Here I'm supposing that you want to make text between ** bolded.
This question already has answers here:
How do I replace tabs with spaces within variables in PHP?
(9 answers)
Replace all occurences of char inside quotes on PHP
(5 answers)
Closed 5 years ago.
I know what needs to be done, but have been unsuccessful with the correct regex.
What is the regular expression I should use in preg_replace() to find tabs inside all quoted strings and replace with a single space?
any help would be much appreciated.
Example:
$string = '"Foo\tMan\tChoo"'
preg_replace($expression_string, ' ',$string);
echo $string;//desired result---->'"Foo Man Choo"'
I think this question is not a duplicate
answer : you will need to repeat preg_replace as many time as the max of \t you expect in a field (never could be bothered comming up with a more generic solution : it is usually possible to use this one)
also make sure every line ends with a tab (otherwise the last field will not be processed)
then you need to repeat replacement starting with the max possible number of \t (2 in the example)
$string = '"Foo'."\t".'Man'."\t".'Choo"'."\t".'boo'."\t".'"Foo'."\t".'Man"'."\t";
$string = preg_replace('/"([^"]*)'."\t".'([^"]*)'."\t".'([^"]*)"'."\t".'/','"$1_$2_$3"'."\t",$string);
$string = preg_replace('/"([^"]*)'."\t".'([^"]*)"'."\t".'/','"$1_$2"'."\t",$string);
echo $string;
This question already has answers here:
Make all words lowercase and the first letter of each word uppercase
(3 answers)
Closed 1 year ago.
I have been really trying to do some pretty basic work in PHP as I am beginner to PHP but I wasn't really able to achieve my goal.
What I want to do is that I have strings like..!
Mixed Types :
THIS IS A SENTENCE
tHis Is a SEnTenCe
I really tried with ucwords function in php but that didn't gave the exact result as ucwords focus just on first alphabets of every word and do not focus on other remaining characters in word..What I want really is to get some sort of this fixed type of strings from each and every mixed type of strings..!
Like :
This Is A Sentence
Or May be I didn't check it properly..So if anyone can guide me in the right path.That would be great.!
Convert to lowercase first:
$string = ucwords(strtolower($string));
<?php
$l = 'tHis Is a SEnTenCe';
echo ucwords(strtolower($l));
?>
Result
This Is A Sentence
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Highlight keywords in a paragraph
Here is another question for you. I have a small problem in php and I thought before find an extra-ordinary solution by myself there maybe an easier and faster way to solve the problem.
Assuming I have a string which contains HTML paragraph tags like:
$string="<p>Hello this is nick</p>
<p>i need some help over here</p>
<p></p><p>Does anyone know a solution</p>"
And an array of stings which contains some "clue" words:
$array=("Hello","nick", "help", "anyone", "solution")
I now would like to do the following:
Output the $string in a browser but the "clue" words should have a special format e.g. being bold or highlighted.
What makes me find this a bit difficult is that I want to keep the paragraphs as there are. In other words I want the final output to look exactly as the original (including new lines/new paragraphs) but with some words bold
I thought I could use strip_tags to remove <p> and </p> tags and then split the returned string by spaces. So as to get an array of words. Then I would output each word individually by checking if that word is contained in the $array. If yes, then it would be outputted with a bold style.
In this way I clearly lose the notion of new paragraphs and all the paragraphs will be merged in a single one.
Is there an easy way to fix that ? For example a way to have the knowledge that e.g. word "Hello" starts in a new paragraph? Or is there something else I can do?
Just replace the words with formatted versions of themselves. The regex below maintains the case and replaces full words only (so that for example in the word "snicker" the word "nick" inside it isn't replaced).
preg_replace( '/\b('.implode( '|', $array ).')\b/i', '<em>$1</em>', $string );
Why not just replace your clue words directly ?
$string = str_ireplace(array('hello', 'nick'), array('<strong>hello</strong>', '<strong>nick</strong>'), $string);
(of course the second array passed to the function would be generated beforehand)
use str_replace and replace the words with bold tags around them
This question already has answers here:
PHP Preg-Replace more than one underscore
(7 answers)
Closed 1 year ago.
this following code will replaces spaces correctly:
$string = preg_replace("/[[:blank:]]+/", "", $string);
but how can I make it so that it will only replace it if there is more than 2 blank spaces? Because right now it replaces all spaces, I only need it to replace more than one space. I searched on here and see people use totally different preg_replace codes, but it also removes newlines so if the code I posted can just be simply modified to allow more than one blank, that would be great. I remember a while back reading a tutorial where it used something like {2+} in the preg area to match anything with more than two or something but not sure how to make it work correctly.
/[[:blank:]]{2,}/
That will make it replace sequences of two or more.
The php manual has a chapter about repetition/quantifiers.
$string = preg_replace("/[[:blank:]]+/", " ", $string);
Same as yours but replaces all occurrences of spaces with one space.