Is it possible to run PHP include() inside an echo? - php

Is this possible to include an external file inside an echo?
This is what I am trying:
echo 'stuff'.(include($_SERVER["DOCUMENT_ROOT"].'/theme/button.php')).'morestuff';
I could simply write 3 lines but I wanted to know for simplification purposes.

You should just use include.
<div>
<?php include $_SERVER["DOCUMENT_ROOT"].'/theme/snippets/follow-button.php'; ?>
</div>

I tested this and it works... I only put HTML code in the 'button.php' file...
echo 'stuff'; include($_SERVER["DOCUMENT_ROOT"].'/theme/button.php'); echo 'morestuff';

No. echo implicity calls __toString() on whatever is contained within the statement to be echo'd.
What you should do is include the file and have the HTML in the included file. No need to echo.

You certainly can. If the included file is returning anything, that will be printed. Includes basically evaluate the file and can be used as a normal function.

It would probably be cleaner for the include file to define a function that returns the value you want. Then you would do:
include($_SERVER["DOCUMENT_ROOT"].'/theme/button.php');
echo echo 'stuff'.button_func().'morestuff';

There's no need to do this. Just break the echo. Example below...
<?php
echo "
$value1 <div id='1'></div>
$value2 <div id='2'></div>
// I want my include here
$value3 <div id='3'></div>
";
?>
Change above to;
<?php
echo "
$value1 <div id='1'></div>
$value2 <div id='2'></div>
";
include 'some_file.php';
echo "
$value3 <div id='3'></div>
";
?>

Related

Echo php with echoed html php

I currently have a php which echo my html template.
However in that HTML template there is another echo which calls from another php script.
Just wondering how do I do that? Because once I echo my html template the other it doesn't seems to echo my content from the other php script.
HTML TEMPLATE
<php? $html = '<span>name:<?php echo $name; ?></span><span>email:<?php echo $email; ?></span>' ?>
CONTACT TEMPLATE
<php? $name = "hello world"; $email = "hello#world.com"; ?>
I can see what you're trying to do, and it's a simple error. You can't escape php like that whilst inside setting a variable.
Also, I must add that you are declaring php incorrectly.
This is preferred
<?php
not
<php?
So make sure for your contact template you use the correct tag.
Also to include a file you have to call it/require it.
Back to the original question - Here is your method
<php? $html = '<span>name:<?php echo $name; ?></span><span>email:<?php echo $email; ?></span>' ?>
Here is the correct method
<?php
require('contact.php');
$html = '<span>name:'.$name.'</span><span>email:'.$email.'</span>';
echo $html;
?>
First I created the variable. And when doing so I insert the existing variables by escaping the php. Only once this final variable is created do I echo it.
Hope this helps you on your way.
Try to use include. The include statement includes and evaluates the specified file, in this case - your template.
Just Concatenation
<?
$html = '<span>name:'.$name.'</span><span>email:'.$email.'</span>';
?>
Change the tags from <php? ?> to <?php ?> in your script

Forcing file_get_contents() not to render php codes as plain text

How can I get expected output from example below?
Note: I'm using $content = file_get_contents('content.php'); to use content where and when possible so it is not a direct output on screen. include() breaks the pages.
content.php
<p>Hello <?php echo 'World!'; ?></p>
reader.php
<b>Message from another file:</b> <?php echo file_get_contents('content.php'); ?>
Output of code above is:
Message from another file: Hello <?php echo 'World!'; ?>
Instead of (expected):
Message from another file: Hello World!
I think you are looking for <?php include('content.php');
file_get_contents — Reads entire file into a string
PHP.net file_get_contents - manual
The include statement includes and evaluates the specified file.
PHP.net include - manual
Try making content.php into a file that has a function that returns the content you want (you may want to have parameters). Simply require the file then call the function and save the output.
Example:
content.php
function get_content($world){
return '<p>Hello ' . $world . '</p>';
}
reader.php
<?php
require('content.php');
$content = get_content('world');
?>
<b>Message from another file:</b> <?php echo $content; ?>
Since you cannot use include (though I don't understand fully why), but want the file to be parsed and executed as PHP code, you can use eval
<b>Message from another file:</b> <?php eval(file_get_contents('content.php')); ?>
But the file content.php should not contain <?php and ?> tags, as stated at http://php.net/eval.

$string is not showing in common.php

Let's say I've got 2 files. 1 is common which loads all the design and stuff and one is index.
What I want to do is set a $ in index like this:
<?
$SubId3 = 'test';
include "../../common.php";
?>
Then in common I want to have something like
<?=$SubId3; if (empty($SubId3)) { echo 'homepage'; } ?>
I cannot seem to get this working. Meaning if I set it up this way. The index will never show "test".
What am i doing wrong here?
I want to do this since only certain files will contain the string $SubId3, to test some things on certain pages and not others (by adding $SubId3 = 'test'; to that particular file)
Note that <?= is short-hand to output something (think of <?= as <?php echo) and not to execute any other sort of logic or code.
However, it is possible to use the ternary operator this way:
<?= empty($SubId3) ? 'homepage' : $SubId3; ?>
This is basically equivalent to this:
<?php
if (empty($SubId3)) {
echo 'homepage';
}
else {
echo $SubId3;
}
?>
So the <?= short-hand should only be used to pass one simple variable or a ternary expression to it; everything else should use the common <?php tag.
Here's a test case for Alex (in the comments) because I can run the above code just fine with PHP 5.4.12, but he seems not to be able to.
common.php
<?= empty($SubId3) ? 'homepage' : $SubId3; ?>
index.php (visit this file then)
<?php
$SubId3 = 'test'; // <-- Comment this out for the "homepage" output
include 'common.php';
i think this
<?=$SubId3; if (empty($SubId3)) { echo 'homepage'; } ?>
should be
<?php $SubId3; if (empty($SubId3)) { echo 'homepage'; } ?>
<?=?> is short for <?php echo?>
This wont work:
<?=$SubId3; if (empty($SubId3)) { echo 'homepage'; } ?>
If you want to print some stuff, you have to use only the variable, in one block and the IF on another.
<?=$SubId3?>
And:
<?php if(empty($SubId3)) { echo 'homepage'; } ?>
Hope this helps...
Try
<?php
/* echo $SubId3; */
if (empty($SubId3)) {
echo 'homepage';
} else {
echo $SubId3;
}
?>
Consider using different style of coding.
In PHP you have generally three variants:
PHP code only
HTML files with just some echoes
Intermixed PHP and HTML
In first you use echo to output every single bit of the HTML.
Second means you include a PHP script at the top of your HTML file and call appropriate functions / insert text into the template. Just so you can edit your HTML separately from your PHP.
Third makes for sometimes unreadable and complex code, but is fast to write.
<?php if($something) {
while($otherthing) { ?>
<B>text=<?=$index ?></B>
<?php }} ?>
Just a food for thought.
I found the answer guys, thanks for all the help.
I needed to set it in the PrintHeader like this:
<?
include "../../common.php";
printHeader('BlogNr1', 'BlogNr2', 'BlogNr3');
?>
And the index had to look like this:
<?
include "../../common.php";
printHeader('BlogNr1', 'BlogNr2', 'BlogNr3');
?>
Somebody on skype helped me. thanks anyways guys!

Using php variables in included html

I'm looking for something much like the Using PHP variables inside HTML tags? question, but a little different.
In my case, I'd like to use code ore like this:
$somevar = 'a test';
include("file.html");
and file.html would contain
<b>hello, this is {$somevar}</b>
The problem is that it just prints hello, this is {$somevar}.
How can I make the HTML read the vars in the included file?
echo "<b>hello, this is {$somevar}</b>";
or
<b>hello, this is <?=$somevar?></b>
or
<b>hello, this is <?php echo $somevar; ?></b>
or
<b>hello, this is <?php print $somevar; ?></b>
You need to include the variable defining program, in the other program wanting to access it.
Example:
Say test.html has $somevar.
in file.html you do,
<?php
include('test.html');
echo "<b>hello, this is $somevar</b>";
?>
<?php
include "stuff.php";
$somevar = "test";
?>
<html>
<body><p><?php echo($somevar); ?></p></body>
</html>

PHP Include with a twist

I have an include
include ('myfile.php');
Now, I am using wordpress and to get the template path I use:
<?php echo get_template_directory_uri(); ?>
My question is:
How can I use both together?
Like:
<?php
include('<?php echo get_template_directory_uri(); ?>/myfile.php');
?>
Thanks
include(get_template_directory_uri() . "/myfile.php");
The include() function just takes a string parameter. Nothing special about it.
You can use the result of the function in the include, but not by echo:ing it. Just use it directly.
<?php
include(get_template_directory_uri() . '/myfile.php');

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