I use Hazel to organize downloaded files on my Mac. I see i can make it run applescripts every time it triggers a rule.
I was wondering if it is possible to make it send something like:
http://my.server.com?type=Show&name=Big+Bang+Theory
Then i could create a small page that logs all downloads.
Sure, the command line utility curl is one way. Applescripts can use command line utilities with the "do shell script" command. So try this...
set theURL to "http://my.server.com?type=Show&name=Big+Bang+Theory"
do shell script "curl " & quoted form of theURL
The above will return the page results to applescript. Maybe you'd rather just open the link in your default browser...
set theURL to "http://my.server.com?type=Show&name=Big+Bang+Theory"
open location theURL
So take your pick!
Related
Opencart generates its sitemap on the fly and this is a problem in a big catalogs over 10.000 products. So I have modified the function to generate a static sitemap in an XML file.
When I access to my http://localhost/index.php?route=extension/feed/google_sitemap I generate a sitemap-google.xml file without problems and with a unlimited execution time.
I tried to add it in a cron in the development server each 4 hours
0 0,4,8,12,16,20 /usr/bin/php /path/to/index.php?route=extension/feed/google_sitemap
But I'm receiving a "command not found".
Can I execute on cli the "?params/etc"?
You cannot do that, as the URL parameters are only evaluated this way when calling the script over a server. But a quick solution could be to use wget: keep a copy of that sitemap script anywhere under some kind of "secret URL", call it using wget and put the result on your disk.
If you cannot use wget, you could use a PHP script containing file_get_contents. In the same way, it could request the data over a HTTP request and save it in the cached sitemap file.
As a note: if you know which logic should be present to generate that sitemap, you could also write all that logic directly to a PHP script. Running it from shell helps to avoid a blocked server thread, but might be more work
https://stackoverflow.com/a/62145786/4843247
You can use following command to generate sitemap.xml:
cd /PATH_TO_YOUR_WWW_ROOT && QUERY_STRING="route=extension/feed/google_sitemap" php -r 'parse_str($_SERVER["QUERY_STRING"],$_GET);include "index.php";' >sitemap.xml.new && mv sitemap.xml.new sitemap.xml
I want to open a vm through following php code:
<?php
$output = shell_exec("virt-viewer --connect qemu:///system 1 2>&1");
echo "<pre>$output</pre>";
?>
I already set the permission of a file with read,write and execute.
I am getting the following error:
(virt-viewer:15162): Gtk-WARNING **: 22:45:33.686: cannot open display:
please help if i am missing something or doing something wrong.
Thanks
How web page works:
Browser makes request to web server, web server delivers html and optionally other asset files (css, js..), but generally, html is loaded first and it stays as it is - content is not changed (except if it's changed by JS, which is not the case here).
Your call will execute some shell command it will return some response (some text) and you'll get it inside some var. If you display that static text as part of your page how do you expect that it will act as GUI?!?
That's just not possible. Imaging that you are calling from shell_exec() exe file of some video game? Will the game then run in the browser?!?
You can call shell commands in order to trigger some action on server (i.e. rescale some image, process some video) or to collect some response (i.e. free disk space or something). But expecting that if you call something form shell will appear in browser is just not realistic.
I have 2 websites, hosted on 2 different servers. They are kind of interlinked. Sometimes I just do stuff on Website-1 and run a script on Website-2. Like I edited something on Website-1 and now I want to run a script on Website-2 to update accordingly on it's server.
Till now I am using following code on website 1.
$file = file_get_contents('Website-2/update.php');
But the problem with this is that my Website-1 server script stops running and wait for the file to return some data. And I don't wanna do anything with that data. I just wanted to run the script.
Is there a way where I can do this in a better way or tell PHP to move to next line of code.
If you want to call the second site without making your user wait for a response,
I would recommend using a message queue.
Site 1 request would put a message to the queue.
Cron job to check queue and run update on site 2 when message exists.
Common queues apps to look at:
[https://aws.amazon.com/sqs/?nc2=h_m1][1]
[https://beanstalkd.github.io/][2]
[https://www.iron.io/mq][3]
[1]: https://aws.amazon.com/sqs/?nc2=h_m1
[2]: https://beanstalkd.github.io/
[3]: https://www.iron.io/mq
What you're trying to achieve is called a web hook and should be implemented with proper authentication, so that not anybody can execute your scripts at any time and overload your server.
On server 2 you need to execute your script asynchronously via workers, threads, message queues or similar.
You can also run the asynchronous command on your server 1. There are many ways to achieve this. Here are some links with more on this.
(Async curl request in PHP)
(https://segment.com/blog/how-to-make-async-requests-in-php/)
Call your remote server as normal. But, In the PHP script you normally call, Take all the functionality and put it in a third script. Then from the old script call the new one with (on Linux)
exec('php -f "{path to new script}.php" $args > /dev/null &');
The & at the end makes this a background or non-blocking call. Because you call it from the remote sever you don't have to change anything on the calling server. The php -f runs a php file. The > /dev/null sends the output from that file to the garbage.
On windows you can use COM and WScript.Shell to do the same thing
$WshShell = new \COM('WScript.Shell');
$oExec = $WshShell->Run('cmd /C php {path to new script}.php', 0, false);
You may want to use escapeshellarg on the filename and any arguments supplied.
So it will look like this
Server1 calls Server2
Script that was called (on Server2) runs exec and kicks off a background job (Server2) then exits
Server1 continues as normal
Server2 continues the background process
So using your example instead of calling:
file_get_contents('Website-2/update.php');
You will call
file_get_contents('Website-2/update_kickstart.php');
In update_kickstart.php put this code
<?php
exec('php -f "{path}update.php" > /dev/null &');
Which will run update.php as a separate background (non-blocking) call. Because it's non-blocking update_kickstart.php will finish and return to searver1 which can go about it's business and update.php will run on server2 independantly
Simple...
The last note is that file_get_contents is a poor choice. I would use SSH and probably PHPSecLib2.0 to connect to server2 and run the exec command directly with a user that has access only to that file(Chroot it or something similar). As it is anyone can call that file and run it. With it behind a SSH login it's protected, with it Chrooted that "special" user can only run that one file.
I'm making a Minecraft control panel, but are sort of confused on how to send a command to each screen. I understand how to execute a command to a screen, but I don't understand to read the output.
Ex. I have screen A and screen B. I want to execute something in screen A, and get the output, and then exit the screen.
Here's an easier solution:
Use Websend bukkit plugin (Download&info) in both servers. PHP can simply execute commands and receive outputs when plugin is installed and php classes setted up, also this can be more complex than bash screen, and much easier to setup and use.
Here's an example use of this:
<?php
include_once 'Websend.php';
//Replace with bukkit server IP. To use a different port, change the constructor to new Websend(ip, port)
$ws = new Websend($ServerIP, $ServerPort);
//Replace with password specified in Websend config file
$ws->connect("password");
$ws->doCommandAsConsole("give ".$PlayerName." 64 1");
$ws->disconnect();
?>
In this example the script item to a variable-definied player.
You can execute a custom variable command with replacing $ws->doCommandAsConsole("give ".$PlayerName." 64 1");' to$ws->doCommandAsConsole("$_REQUEST['customCMD']"); where customCMD is a field in a GET or POST form.`
Don't actually need a plugin, but keep in mind using shell_exec could open a massive world of pain for you when it comes to security.
However, I was having a similar issue with implementing a control panel in drupal, I managed to run commands to a screen using the following code.
shell_exec("screen -S ScreenName -X stuff \"echo hello world\"'\n'");
You're welcome.
Let's say I have a local webpage, that when a button is pressed, executes a program in C. I already can do that. The problem is that this program outputs logs and needs input from the user. My question is: how can I display bash-like window and run this program through it, so that output and input is seen through the screen?
Perhaps you could use ajaxterm, and specify the program that you want to run as the shell:
ajaxterm.py --command=/your/command --port=yourfavoriteport
You could redirect the user to the specified port, or display the terminal via an iframe.
I develop plugin for jquery "Terminal Emulator" you can check this out. If you write your C program as JSON-RPC you can create your terminal with one line of javascript.
The other solution is to not use PHP at all, and creating your code as CGI written in C or even in Bash.
Update: You can modify your program to be CGI script
int main() {
printf("Content-Type: text/plain\n\n");
// code of your program here
}
and put it in cgi-bin directory and run it through browser http://yourserver.com/cgi-bin/program it display the output in browser