Another PHP if/else not working as expected - php

Question

I haven't been able to find a solution to this issue and hope that a another set of eyes may pick up on something. The else $confirm = line is not executed when the first "if" is not true and I can't figure out why.
if($_POST['zip'] && $_POST['country']=='USA' && !empty($fax)){
$plus4 = substr($_POST["zip"],6,4);
if (empty($plus4)) {
$link = 'Zip + 4';
$msg = "Your Zip + 4 was not provided! We cannot fax your Representative without your Zip+4.<br/>Click here to find your ".$link ;
print "<p style=\"color: red;\"><b>$msg<br/><br/></b></p>";
}
if (empty($_POST['state']) || empty($_POST['zip'])) $statezip = false ; // Check for State & Zip Required
else $statezip = true ;
//if (empty($state) || empty($zip) || empty($plus4)) $statezip = false ; // Check for State & Zip Required
$confirm = !empty($_POST['name']) && !empty($_POST['from']) && !empty($_POST['address']) && !empty($_POST['city']) && !empty($_POST['country']) && $statezip == true ; // Verify required fields
}
else $confirm = !empty($_POST['name']) && !empty($_POST['from']) && !empty($address) && !empty($city) && !empty($country) && $statezip == true ; // Verify required fields

Answer 1

Your else statement will always return false for $confirm due to the last condition:
&& $statezip == true
You are setting that value in the if statement, so it is undefined in the else statement.

Answer 2

Add your curly braces to the ELSE statement. Since you use them in the defining IF, the parser is expecting them.
else {
$confirm = !empty($_POST['name']) && !empty($_POST['from']) && !empty($address) && !empty($city) && !empty($country) && $statezip == true ; // Verify required fields
}

Answer 3

use isset to check that variable exist,
function empty return true even if it contain 0 ,
when you are using else use brackets { too
else{do something}