I'm new to regex and I am really bad at it.
I've been trying to solve this problem but still can't get the result. So, I'm hoping that someone is able to assist me. thanks!
$str = "/tqrfq_58533_13";
preg_match_all('/\d+(?>=_)*/', $str, $matches);
print_r($matches); // gets 58533, 13
but I only want '58533' and not both numbers. So I want the array of $matches to return '58533' as the only number
Use /(?<=_)(\d+)(?=_)/ as pattern in preg_match() that match digits between _
$str = "/tqrfq_58533_13";
preg_match('/(?<=_)(\d+)(?=_)/', $str, $matches);
echo $matches[0];
// 58533
Check result in demo
Also you can use preg_replace() if you don't want to get array as result
echo preg_replace('/.*?_(\d+)_.*/', "$1", $str);
// 58533
preg_match_all('/\d+(?=_)/', $str, $matches);
If you want to get only one number, remove * part since it means the result will be more than one. AFAIK, there is no such things like (?>=_). I use (?=_) to indicate that _ immediately follow the number.
You can see this link for more clarification.
Can someone help me to optimize my regex pattern, so I don't have to go through each regexes below. So it matches all of the string like the example I provided.
$pattern = "/__\(\"(.*)\"/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
$pattern = "/__\(\"(.*)\",/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
$pattern = "/__\(\'(.*)\'/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
$pattern = "/__\(\'(.*)\',/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
$pattern = "/_e\(\"(.*)\"/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
$pattern = "/_e\(\"(.*)\",/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
$pattern = "/_e\(\'(.*)\'/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
$pattern = "/_e\(\'(.*)\',/";
preg_match_all($pattern, $content, $matches, PREG_SET_ORDER);
Example:
_e('string');
_e("string");
_e('string', 'string2');
_e("string", 'string2');
__('string');
__("string");
__('string', 'string2');
__("string", 'string2');
Also if it possible, to match also these string below.
"string"|trans
'string'|trans
"string"|trans({}, "string2")
'string'|trans({}, 'string2')
'string'|trans({}, "string2")
"string"|trans({}, 'string2')
If it is possible to get the value string2 too. In the worst case, in the file, there are also mixed single and double quote.
Like you see on my preg_match_all code now, I go with 8 patterns for the first and also 8 patterns for the second one to get the first string.
Note:
I just only run this script on console command, not in PHP application. So I don't pay any attention to the performance and it doesn't matter too.
Thank you for your help!
Edited
Thank you for the response. I tried both your regex, almost there. My question might confusing. I am not english speaker. I copy paste from regex101. It might be easier to understand, what I am trying to achieve.
https://regex101.com/r/uX5nqR/2
and this one too
https://regex101.com/r/Fxs7yY/1
Please check this out. I tried to extract translations from wordpress project and also twig file which using "trans" filter. I know there are mo po Editor, but the editor don't recognize the file extension I used.
I took the liberty of writing this in JavaScript, but the regex will work the same.
My complete code looks like this:
const r = /^_[e_]\((\"(.*)\"|\'(.*)\')(, (\"(.*)\"|\'(.*)\'))?\);$/;
const xs = [
"_e('string');",
"_e(\"string\");",
"_e('string', 'string2');",
"_e(\"string\", 'string2');",
"__('string');",
"__(\"string\");",
"__('string', 'string2');",
"__(\"string\", 'string2');",
];
xs.forEach((x) => {
const matches = x.match(r);
if(matches){
console.log('matches are:\n ', matches.filter(m => m !== undefined).join('\n '));
}else{
console.log('no matches for', x);
}
});
Now let me explain how the regex works and how I arrived at it:
First I noticed that all your strings start with _ and end with );,
so I knew the regex had to look something like ^…\);$.
Here ^ and $ mark the beginning and end of the string, and you should leave them out if they're not required.
After the initial _ you've got either another _ or a e, so we put these into a group followed by the opening parenthesis: [e_]\(.
Now we have a string that is either in " or in ', and we put it down as alternatives: (\"(.*)\"|\'(.*)\').
This string is repeated, but optionally, with a leading , in front.
So we get (, …)? for the optional part, and (\"(.*)\"|\'(.*)\') for the whole second portion.
For the second portion of your problem you can use the same strategy:
"string"|trans
'string'|trans
"string"|trans({}, "string2")
'string'|trans({}, 'string2')
'string'|trans({}, "string2")
"string"|trans({}, 'string2')
Start building up your regex from the similarities. We've got the same string pattern as before used twice, and the optional second part now looks like (\(\{\}, (\"(.*)\"|\'(.*)\')\))?.
This way we can end up with a regex like this:
^(\"(.*)\"|\'(.*)\')\|trans\(\{\}, (\"(.*)\"|\'(.*)\')\))?$
Please note that this regex is not tested, but just a guess from my side.
Upon further discussion it became apparent that we're looking at several matches in a larger bunch of text. To adapt to this we need to exclude the ' and " characters from the innermost groups, which leaves us with these regexes:
_[e_]\(("([^"]*)"|\'([^']*)\')(, ("([^"]*)"|\'([^']*)\'))?\);
(\"(.*)\"|\'(.*)\')\|trans(\(\{\}, (\"(.*)\"|\'(.*)\')\))?
I've also noted that my second regex apparently had an unmatched parenthesis in it.
I tried to understand the purpose of these regexes - here's what I think. (Let me omit the slashes on both sides, also the string quotes belonging to the language instead of the regex itself.)
(__|_e)\(\"(.*)\"
(__|_e)\(\'(.*)\'
This way you get all the hits of your 8 regexes above; but that's probably not what you were trying to achieve.
As far as I understand, you want to list the I18N refs in your code, with one or more arguments between the brackets. I think the best way to do it is run a preg_match_all with the simplest form of the pattern:
(__|_e)\(.*\)
or maybe this one is better:
(__|_e)\([^\)]+\) // works for multiple calls in one line, ignores empties
...and then iterate the results one by one and split them by comma:
foreach($matches as $m) {
$args = explode(",",$m[1]); // [1] = second subpattern
;
; // now you have the arguments of this function call
;
}
If this answer is not helping, let's refine the question :)
The first question is this:
I am using http://www.phpliveregex.com/ to check my regex is right and it finds more than one matching lines.
I am doing this regex:
$lines = explode('\n', $text);
foreach($lines as $line) {
$matches = [];
preg_match("/[0-9]+[A-Z][a-z]+ [A-Z][a-z]+S[0-9]+\-[0-9]+T[0-9]+/uim", $line, $matches);
print_r($matches);
}
on the $text which looks like this: http://pastebin.com/9UQ5wNRu
The problem is that printed matches is only one match:
Array
(
[0] => 3Bajus StanislavS2415079249-2615T01
)
Why is it doing to me? any ideas what could fix the problem?
The second question
Maybe you've noticed not regular alphabetic characters of slovak language inside the text (from pastebin). How to match those characters and select the users which have this format:
{number}{first_name}{space}{last_name}{id_number}
how to do that?
Ok first issue is fixed. Thank you #chris85 . I should have used preg_match_all and do it on the whole text. Now I get an array of all students which have non-slovak (english) letters in the name.
preg_match is for one match. You need to use preg_match_all for a global search.
[A-Z] does not include an characters outside that range. Since you are using the i modifier that character class actual is [A-Za-z] which may or may not be what you want. You can use \p{L} in place of that for characters from any language.
Demo: https://regex101.com/r/L5g3C9/1
So your PHP code just be:
preg_match_all("/^[0-9]+\p{L}+ \p{L}+S[0-9]+\-[0-9]+T[0-9]+$/uim", $text, $matches);
print_r($matches);
You can also use T-Regx library:
pattern("^[0-9]+\p{L}+ \p{L}+S[0-9]+\-[0-9]+T[0-9]+$", 'uim')->match($text)->all();
my string can be
new-york-10036
or
chicago-55036
the desired result is
new-york
chicago
and i basically want to remove all the string that come after the first dash - followed by a number
seems easy but i don't know how
You can use Negative Lookahead, like so:
(.+)(?=\-\d)
The regex reads: "get me everything that is not followed by exactly one dash and exactly one number after that".
Given the input new-york-10036 the regex is going to capture only new-york. In PHP you can get the matched string with:
$string = 'new-york-10036';
$regex = '/(.+)(?=\-\d)/';
preg_match($regex, $string, $return);
echo $return[0] . "\n";
It outputs new-york.
See the regex working here.
I'm a regex-noobie, so sorry for this "simple" question:
I've got an URL like following:
http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx
what I'm going to archieve is getting the number-sequence (aka Job-ID) right before the ".aspx" with preg_replace.
I've already figured out that the regex for finding it could be
(?!.*-).*(?=\.)
Now preg_replace needs the opposite of that regular expression. How can I archieve that? Also worth mentioning:
The URL can have multiple numbers in it. I only need the sequence right before ".aspx". Also, there could be some php attributes behind the ".aspx" like "&mobile=true"
Thank you for your answers!
You can use:
$re = '/[^-.]+(?=\.aspx)/i';
preg_match($re, $input, $matches);
//=> 146370543
This will match text not a hyphen and not a dot and that is followed by .aspx using a lookahead (?=\.aspx).
RegEx Demo
You can just use preg_match (you don't need preg_replace, as you don't want to change the original string) and capture the number before the .aspx, which is always at the end, so the simplest way, I could think of is:
<?php
$string = "http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx";
$regex = '/([0-9]+)\.aspx$/';
preg_match($regex, $string, $results);
print $results[1];
?>
A short explanation:
$result contains an array of results; as the whole string, that is searched for is the complete regex, the first element contains this match, so it would be 146370543.aspx in this example. The second element contains the group captured by using the parentheeses around [0-9]+.
You can get the opposite by using this regex:
(\D*)\d+(.*)
Working demo
MATCH 1
1. [0-100] `http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-`
2. [109-114] `.aspx`
Even if you just want the number for that url you can use this regex:
(\d+)