is there anyway to refresh the contents of this div when the value from the feed.php changes
this is my code for the news ticker:
<script type="text/javascript">
function bangingTicker(container,element) {
var tickContainer = $(container);
function tick(){
var tickElem = tickContainer.children(element);
tickElem.eq(1).siblings().animate({
opacity: 0
},400, function() {
tickContainer.stop(true,true).delay(10).animate({
'margin-right': 10
},0,function() {
tickContainer.delay(100).animate({
'margin-right': 20
},8000);
});
tickElem.first().appendTo(tickContainer);
tickElem.eq(1).delay(200).animate({
opacity: 1
},400);
});
}
setInterval(function(){ tick () }, 6000);
}
bangingTicker('#testi_ticker','li');
$(document).ready(function(){
bangingTicker('#testi_ticker','li');
setTimeout(function(){
$('#testi_ticker').fadeIn(1000);
},6400);
});
</script>
html script
<div id="anc">
<label style="float:left;color:red;font-size:15px;margin-left:30px;margin-top:20px;"><b>ANNOUNCEMENT : </b> </label>
<ul id="testi_ticker" style="display:none;float:left;font-size:15px;font-weight:bold;list-style:none;margin-top:20px;position:absolute;margin-left:180px;">
<?php echo $_SESSION['anc']; ?>
</ul>
</div>
feed.php
<?php
session_start();
$mes1 = "test1";
$mes2 = "test2";
$mes3 = "test3";
$body = " <li>{$mes1} </li>
<li>{$mes2} </li>
<li>{$mes3} </li>
";
$_SESSION['anc'] = $body;
?>
is there anyway to update the output value on the html page , so that when i edit the "feed.php" the value on the html page will also be updated automatically?
You will have to use JavaScript/Ajax. You can simply check call an Ajax-Request every few seconds or you use a technique called "Long Polling", here's a great video-tutorial for that:
http://www.screenr.com/SNH
Related
I'm trying to create a 'print' button to open a new window and display a PHP Variable in it.
The code below is looped through the PHP script as many times as there are tickets, however I can't seem to get the correct number to display when the window opens (the number that displays in the print link is correct - but when the new window is opened it's incorrect).
<script type='text/javascript'>
jQuery(function($) {
$('a.new-window').click(function(){
var recipe = window.open('','PrintWindow','width=600,height=600');
var html = '<html><head><title>Print Your Ticket</title></head><body><div id="myprintticket">' + $('<div />').append($('#ticket').clone()).html() + '</div></body></html>';
recipe.document.open();
recipe.document.write(html);
recipe.document.close();
return false;
});
});
</script>
Print <?php echo $EM_Booking->get_spaces() ?>
<div style="display:none;">
<div id="ticket"><?php echo $EM_Booking->get_spaces() ?>
</div>
</div>
why not try something like this:
<a href="#" class="new-window">Print <?php echo $EM_Booking->get_spaces() ?>
<div class="ticket" style="display:none">
<?php echo $EM_Booking->get_spaces() ?>
</div>
</a>
<script>
jQuery(function ($) {
$('a.new-window').click(function () {
var btn = $(this),
ticket = btn.find('.ticket').html(),
recipe = window.open('','PrintWindow','width=600,height=600'),
html = '<html><head><title>Print Your Ticket</title></head><body><div id="myprintticket">' + ticket + '</div></body></html>';
recipe.document.open();
recipe.document.write(html);
recipe.document.close();
return false;
});
});
</script>
But much better solution would be to give a button a unique ID, and onclick open an existing (php-generated) page from the server passing that ID, e.g. /getBooking.php?id=123 and that page would output whatever's needed.
I have managed to load the new page into the div (thanks to everyone for your help) but it looks pretty bad (got menu bar and logo, but I only wanted the content), so instead I need to load only a div from the new page. I tried a new script but got redirected to the new page. Please help.
<script>
jQuery(document).ready(function() {
jQuery('.stil_link_img a').click(function(){
var x = $(this).attr("href") + "#content_eco";
jQuery("#new_page").load(x);
return false;
});
});
</script>
<div id="pachete">
<?php
$result=mysql_query("SELECT* FROM imagini");
while($data=mysql_fetch_row($result)){
if( ($data[3]==1)&&($data[2]==2) ){ ?>
<div class="stil_link_img">
<img src="upload/<?php echo $data[1];?>">
</div>
<?php }
}?>
</div>
<div id="new_page">
//some content which should be replaced with my loaded page
</div>
jQuery(document).ready(function() {
jQuery('.stil_link_img a').click(function(){
var $pageContent = jQuery('<div/>').load($(this).attr("href"));
jQuery("#new_page").html(jQuery("#content_eco",$pageContent).html());
return false;
});
});
I assume #content_eco is the divisions ID in the new page(the url from href attribute).
or you can load just the content from the url and avoid the link postback as
<script>
jQuery(document).ready(function() {
jQuery('.stil_link_img a').click(function(){
var x = $(this).attr("rel") + " #content_eco";
jQuery("#new_page").load(x);
return false;
});
});
</script>
<div id="pachete">
<?php
$result=mysql_query("SELECT* FROM imagini");
while($data=mysql_fetch_row($result)){
if( ($data[3]==1)&&($data[2]==2) ){ ?>
<div class="stil_link_img">
<img src="upload/<?php echo $data[1];?>">
</div>
<?php }
}?>
</div>
<div id="new_page">
//some content which should be replaced with my loaded page
</div>
Hope this helps you.
I have a PHP page which has a div, the div has a PHP includes which includes this file:
<?php
include('mySql.php');
include('Classes.php');
$targetPage = "blogOutput.php";
$noOfPosts = getNumberOfPosts();
$adjacents = 3;
?>
<link rel="stylesheet" type="text/css" href="Styles/Miniblog.css" />
<script src="Scripts/jQuery.js"></script>
<script type="text/javascript">
var page = 1;
$(".Button").click(onClick());
$(document).ready(onClick());
function onClick() {
alert('called');
$("#posts").load("miniBlog.php", function(response, status, xhr) {
if (status == "error") {
var msg = "Error!: ";
alert(msg);
}
});
page++;
}
</script>
<div class="PostTitle">
<h2>What's New!?</h2>
</div>
<div id="posts">
</div>
<a class="BlogButton" href="">Next</a>
I need the function "onclick" to be called without refreshing the page and resetting the "page" variable in javascript. So far, all I've been able to do is make it run the script once. I think that's wrong too, because it's not loading any content. Here's the page:
<?php
echo "I'm here!";
if (isset($_POST['offset'])) {
$offset = $_POST['offset'];
$posts = getPosts($offset);
}
?>
<div class="BlogPost">
<h3><?php echo $posts[0]->Title; ?></h3>
<p><?php echo $posts[0]->Body; ?></p>
<p class="Date"><?php echo $posts[0]->Date; ?></p>
</div>
<div id="divider"></div>
<div class="BlogPost">
<h3><?php echo $posts[1]->Title; ?></h3>
<p><?php echo $posts[1]->Body; ?></p>
<p class="Date"><?php echo $posts[1]->Date; ?></p>
</div>
So, to clarify: I'm not sure why my ajax call isn't working, and I don't know how to load just the div content and not refresh the entire page. Thanks!
You are not able to see content loaded by AJAX because the page is reloading as soon as you click the anchor. Disable the anchor event by using preventDefault() and this should fix it.
<script type="text/javascript">
var page = 1;
$(document).on('click','.BlogButton',function(e){
// stop page from reloading
e.preventDefault();
$("#posts").load("miniBlog.php", function(response, status, xhr) {
if (status == "error") {
var msg = "Error!: ";
alert(msg);
}
});
page++;
});
</script>
Don't call the function in the click method parameter. You have to put the reference to the handler function.
var handler = function onClick () {...}
$("whatever").click(handler);
Change your code to
var page = 1;
$(document).ready(function(){
$(".Button").click(onClick);
onClick();
};
Use this instead of your code
var page = 1;
$(document).on('click','.Button',function(){
$("#posts").load("miniBlog.php", function(response, status, xhr) {
if (status == "error") {
var msg = "Error!: ";
alert(msg);
}
});
page++;
});
Content dose not look too huge.Can't you just hide div (with content already present in it)& show it onclick.
i am new to ajax . i want to submit a data with the help of ajax and then get the new data replacing the old one in the same div as of which the old data was .
here is the jquery for sliding tab
$(document).ready(function() {
// Vertical Sliding Tabs
$('div#st_vertical').slideTabs({
// Options
contentAnim: 'slideH',
contentAnimTime: 600,
contentEasing: 'easeInOutExpo',
orientation: 'vertical',
tabsAnimTime: 300
});
});
ajax
function addhubs()
{
var group =$('#customhubs').val();
var user=$('#loginuser').val();
$.ajax({
type:"GET",
url: 'mfrnds.php?val='+group+'&& loguser='+user,
success: function(html){
}
});
}
the div i want to replace data
<div id="st_vertical" class="st_vertical">
<div class="st_tabs_container">
<div class="st_slide_container">
<ul class="st_tabs">
<?php $sql=mysql_query("select * from groups");
while($ab=mysql_fetch_array($sql))
{
$gpID[]=$ab['group_id'];
$gp=$ab['group_id'];
$gpName=$ab['group_name'];
?>
<li><?php echo $gpName;?></li>
<?php
}
?> </ul>
</div> <!-- /.st_slide_container -->
</div> <!-- /.st_tabs_container -->
and the mfrnds.php of the ajax call file contains query to update the new data.
$user=$_GET['loguser'];
$group=$_GET['val'];
$sql=mysql_query("insert into groups (group_name) values ('$group')");
how can i update the div in the above . plz help me .m stuck badly luking for solution from 4 days. thanks
Note that in your addhubs function you should only add one & in your url and concatenate everything without spaces in between such as below.
When the ajax call has finished it returns the contents of the page you requested (mfrnds.php) in the html variable. So you can simply select the div you want and enter the html as you can see below. So here we go...:
Your Page
<html>
<body>
<script>
$(document).ready(function() {
setupTabs();
});
function setupTabs() {
// Vertical Sliding Tabs
$('div#st_vertical').slideTabs({
// Options
contentAnim: 'slideH',
contentAnimTime: 600,
contentEasing: 'easeInOutExpo',
orientation: 'vertical',
tabsAnimTime: 300
});
}
function addhubs() {
var group = $('#customhubs').val();
var user = $('#loginuser').val();
$.ajax({
type:"GET",
url: 'mfrnds.php?val=' + group + '&loguser=' + user,
success: function(html) {
//Get div and display the data in there
$('div.st_slide_container).html(html);
//As your slide effect is gone after you updated this HTML, redo your slide effect:
setupTabs();
}
});
}
</script>
<!-- Vertical div -->
<div id="st_vertical" class="st_vertical">
<div class="st_tabs_container">
<div class="st_slide_container">
<ul class="st_tabs">
<?php
$sql = mysql_query("select * from groups");
while($ab = mysql_fetch_assoc($sql)) {
$gp = $ab['group_id'];
$gpName = $ab['group_name']; ?>
<li>
<a href="#stv_content_<?=$gp?>" rel="v_tab_<?=$gp?>" class="st_tab ">
<?php echo $gpName;?>
</a>
</li>
<?php
}
?>
</ul>
</div> <!-- /st_slide_container -->
</div> <!-- /st_tabs_container -->
</div> <!-- /st_vertical -->
</body>
</html>
So in your mfrnds.php you should have a PHP script that uses the val and loguser GET variables and updates the database. After the database has been updated you should return the updated HTML like the following:
*mfrnds.php
<?php
$user = $_GET['loguser'];
$group = $_GET['val'];
$sql = mysql_query("insert into groups (group_name) values ('$group')"); ?>
<ul class="st_tabs">
<?php
$sql = mysql_query("select * from groups");
while($ab = mysql_fetch_assoc($sql)) {
$gp = $ab['group_id'];
$gpName = $ab['group_name']; ?>
<li>
<a href="#stv_content_<?=$gp?>" rel="v_tab_<?=$gp?>" class="st_tab ">
<?php echo $gpName;?>
</a>
</li>
<?php
}
?>
</ul>
Note though that this code is basically meant as an example, I don't know what you want to do exactly in mfrnds.php etc, but I hope this gives you a good idea!
It looks like you are almost there.
In your mfrnds.php file add a line to grab the updated rows
use:
PSEUDOCODE
"SELECT * FROM groups"
for each row in groups
echo "<div> groups.name groups.category </div"
and then in your callback function
success: function(html){
$('.st_tabs').html(html); //replace the html of the sttabs div with the html echoed out from mfrnds.php
}
hi i am building a php mysql database pagination page, so i have a list of records 2 rows long at the bottom of the record i want a div which opens up when the span above it is clicked, how do i set up the jquery to make it so that it takes the id of the <p> and expands it in jquery
<span id="button1">Toggle</span>
<p id="p1">
hello<br/>hello
</p>
<script>
$("#button1").click(function () {
$("#p1").slideToggle("slow");
});
</script>
when i output it in php mysql the button will all have a different id and the p will have different ids as well
//Jquery Code which calls toggle_visibility function
$(".pOne").click(function(){
toggle_visibility('partsIdThree');
})
.toggle( function() {
$(this).children("span").text("[-]");
}, function() {
$(this).children("span").text("[+]");
});
//HTML Code
<div id="parts_toogle_one">
<p class="pOne">Add Records <span>[+]</span></p>
<div id="msg_body_one">
<tr><td></td></tr>
</div>
</div>
// Javascript code
function toggle_visibility(id) {
var e = document.getElementById(id);
if(e.style.display == "inline") {
e.style.display = 'none';
}
else if(e.style.display == "none") {
e.style.display = "inline";
}
}
Something like this..
You can use a dynamic id retrieving, so you don't have to worry about the number of results..
For example:
<?php $i = 0;?>
<?php foreach($resultset as $result) : ;?>
<span class="activator" id="result<?php echo $i;?>">CLICK HERE</span>
<div id="panel_result<?php echo $i;?>">SLIDER DIV</div>
<!-- Do the rest of you processing of $result here; it just doesn't matter, for here you only need some identification, I used a number for convenience. -->
<?php ++$i;?>
<?php endforeach;?>
Your jquery:
$('.activator').click(function(){
var the_id = $(this).attr('id');
var the_panel = $('#panel_' + the_id);
$(the_panel).slideToggle('slow');
});
So you don't have to write a jQuery command for each line you print in php, use just this snippet and it will work out by itself which panel to slide, according to which span is clicked.