Echo data from mysql base to page - php

Question

I have this query:
$query = "SELECT ads.*,
trafficsource.name AS trafficsource,
placement.name AS placement,
advertiser.name AS advertiser,
country.name AS country
FROM ads
JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
JOIN placement ON ads.placementId = placement.id
JOIN advertiser ON ads.advertiserId = advertiser.id
JOIN country ON ads.countryId = country.id
WHERE advertiserId = '$advertiser_id'";
and ads table
ads Table
ad_id PK
size
price
trafficsourceId FK
placementId FK
advertiserId FK
countryId FK
For getting data I'm using
$result = mysql_query($query) or die('Invalid query: ' . mysql_error());
while ($row = mysql_fetch_assoc($result)) {
}
I cant figure out how I need to print page so that it's not looking like rows but also need id's of for example trafficsource name. I want to make something like that:
EDITED:
<div id="adscontent">
<h1>Advertiser:</h1> Advertiser name
<h2>Traffic Sources:</h2> Company1, Company2, Company 3
<h2>Placements:</h2> Like: Newspaper, radio, website, bla bla
</div>
Thanks

Answer 1

You will need to play around with the printout but I think something like this will work:
$results = array();
while ($row = mysql_fetch_assoc($result)) {
$results[$row['advertiser']]['countries'][] = $row['country'];
$results[$row['advertiser']]['trafficsources'][] = $row['trafficsource'];
$results[$row['advertiser']]['placements'][] = $row['placement'];
}
// And now print the data
foreach ($results as $arvertiser => $data)
{
echo "<h1>{$advertiser}</h1>";
// Print Placements
echo "Placements: " . implode(", ", $data['placements']) . '<br />;
// Print Countries
echo "Countries: " . implode(", ", $data['countries']) . '<br />;
// Print Placements
echo "Traffic Sources: " . implode(", ", $data['trafficsources']) . '<br />;
}
EDIT: If you need to add the IDs you will need to change your select to:
$query = "SELECT ads.*,
trafficsource.name AS trafficsource,
trafficsource.id AS trafficsourse_id,
placement.name AS placement,
placement.id AS placement_id,
advertiser.name AS advertiser,
advertiser.id AS advertiser_id,
country.name AS country
country.id AS country_id
FROM ads
JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
JOIN placement ON ads.placementId = placement.id
JOIN advertiser ON ads.advertiserId = advertiser.id
JOIN country ON ads.countryId = country.id
WHERE advertiserId = '$advertiser_id'";
From then on you can include this information in the $results array like so:
$results[$row['advertiser']['countries'] = array(
'id' => $row['country_id'],
'value' => $row['country')
);
and print out whatever you need from there.