Javascript prompt() output to PHP function - php

Question

I've been trying to get user input from a Javascript prompt into a PHP function and have run into a lot a walls doing so. I am at a loss trying jQuery's $.post method- as the PHP simply does not want to execute, not sure why.
Anyways, here is a gist of what I am doing at the moment:
1 A project and its data are loaded from a database- this info is displayed in a table.
2 All data in the table is editable via Javascript prompt(), the code I am using for this is below:
<div id="lvl3"><?php echo $fetchdata['name']; ?></div>
The above work as such: lvl3 is a tag for font styling; blank href to make it act as a link; popupprompt is the prompt function I made, it takes one argument, the 'type' or what is being edited (1 for project name, 2 for project description, ect); return false so the page doesn't reload; php echo to display project data in the table.
3 Once the user clicks the object above- it executes a javascript function called popupprompt taking an argument of 'type', or what project info is being changed. the code for this function is below:
function popupprompt(type) {
switch(type)
{
case 1:
var name = prompt("Project Name:", "");
if (name != null && name != "")
{
//Change Project Name
var getname = name;
var gettype = type;
$.post("edit.php", { type: gettype, name: getname });
} else if (name == "") {
senderror("Please enter a valid Project Name");
} else {
//Prompt canceled
sendnotification('Canceled my ass!');
}
break;
case 2:
//Description?
case 3:
//Version?
case 4:
//Release?
default:
alert("There was an error processing your request.");
break;
} }
Th issue I am having in this function is that nothing in edit.php is executed- and i haven't the slightest clue why. Also, i've had to change the brackets around so it shows properly in the code box- so don't mind those.
4 Anyways, now user input is posted to edit.php- which doesn't work, but i'll post it anyways:
<?php
$type = $_POST['type'];
$name = $_POST['name'];
switch($type) {
case 1:
dbconnect();
$urlext = geturlext();
$authenticated = isauthenticated();
if ($authenticated == false)
{
echo("<script>senderror('Access denied');</script>");
} else {
//Escape and trim input
$input = trim($input);
$input = mysql_real_escape_string($input);
$update = "UPDATE 'projects' SET 'name' = '$input' WHERE 'name' = '$urlext'";
$updatequery = mysql_query($update) or die(mysql_error());
echo("<script>sendnotification('Project Name updated');</script>");
}
break;
default:
break;
}
?>
Again had to move some brackets around. But anyways- this function is supposed to update the data in the database- however, it instead does nothing. I've placed alerts in the beginning and they are never called.
Anyways, long story short- if you know what i'm doing wrong please enlighten me, also, if there is a better way to do this- please let me know!
I appreciate all help,
Thanks

Answer 1

Figured it out after a good week of setting it aside. Took a long look at it in firebug, rooted out a typo that was causing most of my issues and also a MySQL syntax error.
I don't know why, but my custom error reporting system does not work when called from a file in this manner. It might be another thing i'm overlooking but firebug sure helped.
Thanks to those who tried to help <3