I don't understand Gaufrette and symfony2.
This seems to me like it's only working for textfiles/textcontent.
I can create a file but can't copy from a local source (i.e. a path).
What i would like to do is something like this:
$adapter = new LocalAdapter($realpath);
$filesystem = new Filesystem($adapter);
$filesystem->fromUploadedFile($tempPathOfUploadedFile,$idForGaufrette);
How do I store an image and how do I handle it's output when requested by the user?
Update:
How can I access the temp filename of an uploaded file in symfony"?
How can I access the existing, private attribute $path that exists in the Symfony\Component\HttpFoundation\File\UploadedFile Object in Symfony2?
The method copy(x, y) is not implemented but if you want storing a file you can move it using the method
rename($key, $new)
defined in the Filesystem Class.
For handle the output when requested by the user, all you need is a link to the image path (probaly in the database). So you don't need the filesystem (you can check if the file exists with the has($key) method).
In all cases use the adapter Local to work in local.
If you need a stream wrapper like "ftp://mydomain/myPicture" i recently send a PR to configures the stream wrapper in the config.yml, and register filiesystems that you want and their domain.
To get the tmp filename:
$file->getPathName(); // /tmp/filename
where $file is a Symfony\Component\HttpFoundation\File\UploadedFile Object.
Related
I'm trying to create and store some HTML code from a textarea into a file
fopen method in PHP will create a file if that file doesn't exist already but it is not working in Laravel 5.7
Here is my demo code
$plugin_html_file_nm = "plugin_html".time().".html";
$html_plugin = fopen("/public/plugin_html_storage/".$plugin_html_file_nm,"w");
fwrite($html_plugin,$request->input('plugin_html'));
$plugin->plugin_html = $plugin_html_file_nm;
This error is given fopen(/public/plugin_html_storage/plugin_html1546535810.html): failed to open stream: No such file or directory
Can anyone help me?
Laravel provides a helper public_path()
The public_path function returns the fully qualified path to the
public directory. You may also use the public_path function to
generate a fully qualified path to a given file within the public
directory
Maybe you need to add the full path. So:
$html_plugin = fopen(public_path("plugin_html_storage/.$plugin_html_file_nm"),"w");
Also, make sure you have writing privilegies. As the PHP documentation states:
The file must be accessible to PHP, so you need to ensure that the file access permissions allow this access.
Your laravel app by default is served from the public directory.
So in order to achieve what you're trying to do, replace
$html_plugin = fopen("/public/plugin_html_storage/".$plugin_html_file_nm,"w");
with:
$html_plugin = fopen("./plugin_html_storage/".$plugin_html_file_nm, "w");
Note: The plugin_html_storage directory should be created in the public directory so the operation doesn't fail.
You just need to add the relative path.
$html_plugin = fopen("../public/plugin_html_storage/".$plugin_html_file_nm,"w");
file_put_contents(public_path()."plugin_html".time().".html",
$request->input('plugin_html'));
I've been experimenting using the new Flysystem integration with Laravel 5. I am storing 'localised' paths to the DB, and getting the Storage facade to complete the path. For example I store screenshots/1.jpg and using
Storage::disk('local')->get('screenshots/1.jpg')
or
Storage::disk('s3')->get('screenshots/1.jpg')
I can retrieve the same file on different disks.
get retrieves the file contents, but I am hoping to use it in my views like this:
<img src="{{ Storage::path('screenshots/1.jpg') }}" />
but path, or anything able to retrieve the full path is not available (as far as I can see). So how can I return the full path? Or, I'm wondering if this is by design? If so, why am I not supposed to be able to get the full path? Or, am I going about this completely the wrong way?
The Path to your Storage disk would be :
$storagePath = Storage::disk('local')->getDriver()->getAdapter()->getPathPrefix()
I don't know any shorter solutions to that...
You could share the $storagePath to your Views and then just call
$storagePath."/myImg.jpg";
This method exists since Laravel 5.4, you can get it by:
$path = Storage::disk('public')->path($filename);
Edit: Solution for L5.2+
There's a better and more straightforward solution.
Use Storage::url($filename) to get the full path/URL of a given file. Note that you need to set S3 as your storage filesystem in config/filesystems.php: 'default' => 's3'
Of course, you can also do Storage::disk('s3')->url($filename) in the same way.
As you can see in config/filesystems.php there's also a parameter 'cloud' => 's3' defined, that refers to the Cloud filesystem. In case you want to mantain the storage folder in the local server but retrieve/store some files in the cloud use Storage::cloud(), which also has the same filesystem methods, i.e. Storage::cloud()->url($filename).
The Laravel documentation doesn't mention this method, but if you want to know more about it you can check its source code here.
This is how I got it to work - switching between s3 and local directory paths with an environment variable, passing the path to all views.
In .env:
APP_FILESYSTEM=local or s3
S3_BUCKET=BucketID
In config/filesystems.php:
'default' => env('APP_FILESYSTEM'),
In app/Providers/AppServiceProvider:
public function boot()
{
view()->share('dynamic_storage', $this->storagePath());
}
protected function storagePath()
{
if (Storage::getDefaultDriver() == 's3') {
return Storage::getDriver()
->getAdapter()
->getClient()
->getObjectUrl(env('S3_BUCKET'), '');
}
return URL::to('/');
}
If you just want to display storage (disk) path use this:
Storage::disk('local')->url('screenshots/1.jpg'); // storage/screenshots/1.jpg
Storage::disk('local')->url(''): // storage
Also, if you are interested, I created a package (https://github.com/fsasvari/laravel-uploadify) just for Laravel so you can use all those fields on Eloquent model fields:
$car = Car::first();
$car->upload_cover_image->url();
$car->upload_cover_image->name();
$car->upload_cover_image->basename();
$car->upload_cover_image->extension();
$car->upload_cover_image->filesize();
If you need absolute URL of the file, use below code:
$file_path = \Storage::url($filename);
$url = asset($file_path);
// Output: http://example.com/storage/filename.jpg
First get file url/link then path, as below:
$url = Storage::disk('public')->url($filename);
$path = public_path($url);
Well, weeks ago I made a very similiar question (Get CDN url from uploaded file via Storage): I wanted the CDN url to show the image in my view (as you are requiring ).
However, after review the package API I confirmed that there is no way do this task. So, my solution was avoid using flysystem. In my case, I needed to play with RackSpace. So, finally decide to create my use package and make my own storage package using The PHP SDK for OpenStack.
By this way, you have full access for functions that you need like getPublicUrl() in order to get the public URL from a cdn container:
/** #var DataObject $file */
$file = \OpenCloud::container('cdn')->getObject('screenshots/1.jpg');
// $url: https://d224d291-8316ade.ssl.cf1.rackcdn.com/screenshots/1.jpg
$url = (string) $file->getPublicUrl(UrlType::SSL);
In conclusion, if need to take storage service to another level, then flysystem is not enough. For local purposes, you can try #nXu's solution
this work for me in 2020 at laravel 7
$image_resize = Image::make($image->getRealPath());
$image_resize->resize(800,600);
$image_resize->save(Storage::disk('episodes')->path('') . $imgname);
so you can use it like this
echo Storage::disk('public')->path('');
Store method:
public function upload($img){
$filename = Carbon::now() . '-' . $img->getClientOriginalName();
return Storage::put($filename, File::get($img)) ? $filename : '';
}
Route:
Route::get('image/{filename}', [
'as' => 'product.image',
'uses' => 'ProductController#getImage',
]);
Controller:
public function getImage($filename)
{
$file = Storage::get($filename);
return new Response($file, 200);
}
View:
<img src="{{ route('product.image', ['filename' => $yourImageName]) }}" alt="your image"/>
Another solution I found is this:
Storage::disk('documents')->getDriver()->getConfig()->get('url')
Will return the url with the base path of the documents Storage
Take a look at this: How to use storage_path() to view an image in laravel 4 . The same applies to Laravel 5:
Storage is for the file system, and the most part of it is not accessible to the web server. The recommended solution is to store the images somewhere in the public folder (which is the document root), in the public/screenshots/ for example.
Then when you want to display them, use asset('screenshots/1.jpg').
In my case, i made separate method for local files, in this file:
src/Illuminate/Filesystem/FilesystemAdapter.php
/**
* Get the local path for the given filename.
* #param $path
* #return string
*/
public function localPath($path)
{
$adapter = $this->driver->getAdapter();
if ($adapter instanceof LocalAdapter) {
return $adapter->getPathPrefix().$path;
} else {
throw new RuntimeException('This driver does not support retrieving local path');
}
}
then, i create pull request to framework, but it still not merged into main core yet:
https://github.com/laravel/framework/pull/13605
May be someone merge this one))
$url = $filename->getMedia('media_name');
I am having troubles with Symfony Filesystem class. I am trying to delete a folder via remove method.
This is my method.
public function createArchive($source, $destination) {
$zipper = new Zipper();
$zipper->make('backup/'.$this->getBackupName().'.zip')->add('backup/'.$this->getBackupName().'/');
$fileSystem = new Filesystem();
$fileSystem->remove('backup/'.$this->getBackupName());
}
Zipper creates zip archive with folder i put in second argument. So for example i have a folder backup/2016_03_24_full it will create zip archive in backup/2016_03_24_full.zip.
Then i am trying to remove the backup/2016_03_24_full folder so only zip archives are there. But Filesystem remove method is deleting also my zip. It should delete only folder i put in argument, but something is going wrong..
What could be the problem?
Since you're passing a folder to the remove method, it first tries to delete the directory by calling rmdir(). This function expects the folder to be empty. Since your directory is not empty, a fallback comes into play which relies on PHP's FilesystemIterator.
My guess is that giving the name of the folder without the trailing slash (/) is picking the files from outside and inside the folder both and removing them.
You can see the concrete algorithm here.
I've been experimenting using the new Flysystem integration with Laravel 5. I am storing 'localised' paths to the DB, and getting the Storage facade to complete the path. For example I store screenshots/1.jpg and using
Storage::disk('local')->get('screenshots/1.jpg')
or
Storage::disk('s3')->get('screenshots/1.jpg')
I can retrieve the same file on different disks.
get retrieves the file contents, but I am hoping to use it in my views like this:
<img src="{{ Storage::path('screenshots/1.jpg') }}" />
but path, or anything able to retrieve the full path is not available (as far as I can see). So how can I return the full path? Or, I'm wondering if this is by design? If so, why am I not supposed to be able to get the full path? Or, am I going about this completely the wrong way?
The Path to your Storage disk would be :
$storagePath = Storage::disk('local')->getDriver()->getAdapter()->getPathPrefix()
I don't know any shorter solutions to that...
You could share the $storagePath to your Views and then just call
$storagePath."/myImg.jpg";
This method exists since Laravel 5.4, you can get it by:
$path = Storage::disk('public')->path($filename);
Edit: Solution for L5.2+
There's a better and more straightforward solution.
Use Storage::url($filename) to get the full path/URL of a given file. Note that you need to set S3 as your storage filesystem in config/filesystems.php: 'default' => 's3'
Of course, you can also do Storage::disk('s3')->url($filename) in the same way.
As you can see in config/filesystems.php there's also a parameter 'cloud' => 's3' defined, that refers to the Cloud filesystem. In case you want to mantain the storage folder in the local server but retrieve/store some files in the cloud use Storage::cloud(), which also has the same filesystem methods, i.e. Storage::cloud()->url($filename).
The Laravel documentation doesn't mention this method, but if you want to know more about it you can check its source code here.
This is how I got it to work - switching between s3 and local directory paths with an environment variable, passing the path to all views.
In .env:
APP_FILESYSTEM=local or s3
S3_BUCKET=BucketID
In config/filesystems.php:
'default' => env('APP_FILESYSTEM'),
In app/Providers/AppServiceProvider:
public function boot()
{
view()->share('dynamic_storage', $this->storagePath());
}
protected function storagePath()
{
if (Storage::getDefaultDriver() == 's3') {
return Storage::getDriver()
->getAdapter()
->getClient()
->getObjectUrl(env('S3_BUCKET'), '');
}
return URL::to('/');
}
If you just want to display storage (disk) path use this:
Storage::disk('local')->url('screenshots/1.jpg'); // storage/screenshots/1.jpg
Storage::disk('local')->url(''): // storage
Also, if you are interested, I created a package (https://github.com/fsasvari/laravel-uploadify) just for Laravel so you can use all those fields on Eloquent model fields:
$car = Car::first();
$car->upload_cover_image->url();
$car->upload_cover_image->name();
$car->upload_cover_image->basename();
$car->upload_cover_image->extension();
$car->upload_cover_image->filesize();
If you need absolute URL of the file, use below code:
$file_path = \Storage::url($filename);
$url = asset($file_path);
// Output: http://example.com/storage/filename.jpg
First get file url/link then path, as below:
$url = Storage::disk('public')->url($filename);
$path = public_path($url);
Well, weeks ago I made a very similiar question (Get CDN url from uploaded file via Storage): I wanted the CDN url to show the image in my view (as you are requiring ).
However, after review the package API I confirmed that there is no way do this task. So, my solution was avoid using flysystem. In my case, I needed to play with RackSpace. So, finally decide to create my use package and make my own storage package using The PHP SDK for OpenStack.
By this way, you have full access for functions that you need like getPublicUrl() in order to get the public URL from a cdn container:
/** #var DataObject $file */
$file = \OpenCloud::container('cdn')->getObject('screenshots/1.jpg');
// $url: https://d224d291-8316ade.ssl.cf1.rackcdn.com/screenshots/1.jpg
$url = (string) $file->getPublicUrl(UrlType::SSL);
In conclusion, if need to take storage service to another level, then flysystem is not enough. For local purposes, you can try #nXu's solution
this work for me in 2020 at laravel 7
$image_resize = Image::make($image->getRealPath());
$image_resize->resize(800,600);
$image_resize->save(Storage::disk('episodes')->path('') . $imgname);
so you can use it like this
echo Storage::disk('public')->path('');
Store method:
public function upload($img){
$filename = Carbon::now() . '-' . $img->getClientOriginalName();
return Storage::put($filename, File::get($img)) ? $filename : '';
}
Route:
Route::get('image/{filename}', [
'as' => 'product.image',
'uses' => 'ProductController#getImage',
]);
Controller:
public function getImage($filename)
{
$file = Storage::get($filename);
return new Response($file, 200);
}
View:
<img src="{{ route('product.image', ['filename' => $yourImageName]) }}" alt="your image"/>
Another solution I found is this:
Storage::disk('documents')->getDriver()->getConfig()->get('url')
Will return the url with the base path of the documents Storage
Take a look at this: How to use storage_path() to view an image in laravel 4 . The same applies to Laravel 5:
Storage is for the file system, and the most part of it is not accessible to the web server. The recommended solution is to store the images somewhere in the public folder (which is the document root), in the public/screenshots/ for example.
Then when you want to display them, use asset('screenshots/1.jpg').
In my case, i made separate method for local files, in this file:
src/Illuminate/Filesystem/FilesystemAdapter.php
/**
* Get the local path for the given filename.
* #param $path
* #return string
*/
public function localPath($path)
{
$adapter = $this->driver->getAdapter();
if ($adapter instanceof LocalAdapter) {
return $adapter->getPathPrefix().$path;
} else {
throw new RuntimeException('This driver does not support retrieving local path');
}
}
then, i create pull request to framework, but it still not merged into main core yet:
https://github.com/laravel/framework/pull/13605
May be someone merge this one))
$url = $filename->getMedia('media_name');
I'm trying to write a controller to accept file uploads from the Plupload plugin. As an added bit of fun, the uploads are coming from a different URL so I have to set the Access-Control-Allow-Origin header myself. So far I've done that like so:
/**
* #Route("/frontEnd/file/upload.{_format}")
*/
public function upload(Request $request) {
$response = new Response();
$response->setContent(json_encode(array('hello' => 'world')));
$response->setStatusCode(200);
$response->headers->set('Access-Control-Allow-Origin', '*');
$response->send();
}
which seems to work. When I submit the uploads using plupload I see the XHR requests hit Symfony and the JSON is returned. However, I have no idea how to handle the actual file and move it into a directory.
I did a var_dump() on $_POST and it only returned the following:
array(1) {
["name"]=>
string(21) "wallpaper-2873928.jpg"
}
The upload is definitely being sent as I can see the file's bytes being part of the request payload with developer tools. Do I need to use Symfony's own components to handle the upload? If so, how? The Symfony documentation only seems to cover uploading from a file upload form.
First of all, try to use the Symfony2 way of accessing request parameters. You can get more information in the book.
When uploading a file, Symfony2 automatically creates an instance of UploadedFile for you and puts it in a FileBag in the request object.
You can access the files in your controller like this:
$files = $request->files;
Like said previously, these are temporary files. To upload them in a user defined directory, use the move method on the object.
$directory = //...
foreach ($files as $uploadedFile) {
$name = //...
$file = $uploadedFile->move($directory, $name);
}
The variable $files now contains an instance of File.
On the other hand, you can also use a bundle that supports the Plupload uploader. I'd recommend the OneupUploaderBundle. (Note: I'm the main developer of this bundle, I guess this needs to be added).