Mysql Array Not Working - php

Question

I am trying to echo out all of the user rows in my database as a select in a form.
It is only showing a blank space. Nothing else.
Here is my code.
<?php
session_start();
require('../../config.php');
$user = $_SESSION['user'];
$qry=("SELECT `rank`, `uname` FROM users WHERE `uname` = '$user'");
$result=mysql_query($qry);
$row = mysql_fetch_assoc($result);
$rank = $row['rank'];
$logged = $_SESSION['loggedin'];
if ($logged == true) {
if ($rank >= 3) {
echo "Succesful, $user.<br />
<form method='POST' action='delete.php'>
<select><option>Please select</option>";
while ($row = mysql_fetch_assoc($result)) {
$users = $row['uname'];
$lol = ucwords($users);
}
echo "<option>$lol</option>";
echo "</select>
</form>";
} else {
echo "Your not an admin. $user";
}
} else {
echo "Please login.";
}
?>

Answer 1

First, please stop using mysql_ functions as they are being deprecated. Look into mysqli_ or PDO. Be aware that your script is vulnerable to SQL injection.
The reason your script is not working is because it appears you are calling mysql_fetch_assoc twice. When calling it the second time, there won't be any output if your query only returns a single row.
$qry=("SELECT `rank`, `uname` FROM users WHERE `uname` = '$user'");
$result=mysql_query($qry);
$row = mysql_fetch_assoc($result);
$rank = $row['rank'];
You will need to resubmit a query (something like below) and call that result separately to populate the drop down, or store the result in an array.
$qry=("SELECT `uname` FROM users");
$result=mysql_query($qry);
while ($row = mysql_fetch_assoc($result)) {
echo '<option>' . ucwords($row['uname']) . '</option>';
}

Answer 2

It looks like your while loop is set up badly, I think you need to change
while ($row = mysql_fetch_assoc($result)) {
$users = $row['uname'];
$lol = ucwords($users);
}
echo "<option>$lol</option>";
to this
while ($row = mysql_fetch_assoc($result)) {
$users = $row['uname'];
$lol = ucwords($users);
echo "<option>$lol</option>";
}

Answer 3

UPDATE:
I reread your question and it seems that you want to display all unames from your table.
The original query was to check if the user is an admin.
Here's how it will look like. But it's just a duplicate of njk's answer.
<?php
session_start();
require('../../config.php');
$user = $_SESSION['user'];
$qry=("SELECT `rank`, `uname` FROM users WHERE `uname` = '$user'");
$result=mysql_query($qry);
$row = mysql_fetch_assoc($result);
$rank = $row['rank'];
$logged = $_SESSION['loggedin'];
if ($logged == true) {
if ($rank >= 3) {
echo "Succesful, $user.<br />
<form method='POST' action='delete.php'>
<select><option>Please select</option>";
// added these 2 lines
$qry=("SELECT `rank`, `uname` FROM users");
$result=mysql_query($qry);
while ($row = mysql_fetch_assoc($result)) {
$users = $row['uname'];
$lol = ucwords($users);
echo "<option>$lol</option>";
}
echo "</select>
</form>";
} else {
echo "Your not an admin. $user";
}
} else {
echo "Please login.";
}
?>

Answer 4

Are you sure your database has more than 1 row? You are calling the fetch 1 time so the second time it will try to fetch the second row.
Try also running the query directly into mysql and see if you get the rows you're expecting back, may be its not returning what you expected