I have a link that opens a modal when clicked, however that element also has a data-id="#id here" attribute that I need to grab so I can pass it to my php script for processing. How can I accomplish this?
My JS code:
$(document).ready(function() {
$('#edit_general').click(editModal);
});
function editModal(event)
{
var modal = $('#editModal');
modal.modal({
show: true
});
}
My html:
<li><a id="edit_general" href="#editModal" data-uid="<?php echo $u->id; ?>">Edit General</a></li>
I tried using the this keyword but it didn't work.
How can I accomplish this?
Try this: Demo http://jsfiddle.net/szS2J/1/ or http://jsfiddle.net/ug7ze/
$(this).data('uid')
Hope it fits the cause :)
like this:
$('#edit_general').click(editModal);
$(this).data('uid')
full
$(document).ready(function() {
$('#edit_general').click(editModal);
});
function editModal(event) {
alert($(this).data('uid'));
var modal = $('#editModal');
modal.modal({
show: true
});
}
You can get the value using the attr method: $(this).attr('data-uid')
Like this stored in data_id.
$(document).ready(function() {
$('#edit_general').click(function() {
var data_id = $(this).data('uid');
var modal = $('#editModal');
modal.modal({
show: true
});
});
});
Related
How do I make jQuery get value from while loop and display it in another div?
I know I should do it with PHP, But I want to display it with only jQuery.
<? while($commentresult = $commentdata->fetch_array(MYSQLI_ASSOC)) { ?>
<div class="show_url"></div>
<? } ?>
$(document).ready(function() {
var getUrl = $('.get_url_comments').attr('href');
$(".show_url").text("Click This" + getUrl);
});
To do this you can set the text() of the .show_url element based on the following .get_url_comments. Try this:
$(document).ready(function() {
$(".show_url").text(function() {
return $(this).next('.get_url_comments').attr('href');
});
});
You should note though that it would be a much better idea to do this directly in PHP:
<? while($commentresult = $commentdata->fetch_array(MYSQLI_ASSOC)) { ?>
<div class="show_url"><? echo $commentresult['comment']; ?></div>
<? } ?>
Try with this..
$(document).ready(function() {
$('.get_url_comments').map(function(guc){
var el = $(guc);
var url = el.attr('href');
el.prev().text("Click This" + url);
// or
el.prev().html("Click This" + url);
});
});
I am having name, email in content of a html page. i have to validate it on clicking continue button. and also the content in the content div has to change. how can i do both on clicking the continue button. help me with some suggestions. thanks.
am using the following code for changing div content.
<script>
$(document).ready(function () {
$("#button").click(function () {
$("#content").load("<?php echo base_url().'survey/categories' ?>");
});
});
$(document).ready(function () {
$("#button1").click(function () {
$("#content").load("<?php echo base_url().'survey/budget_overview' ?>");
});
});
</script>
As i understand your question, i think what you want is to do the two tasks at the same time on click of the button. So here's some sample code assuming this is what you want. If you have any doubts just ask. And i have added just sample Email Validation Using RegExp in JavaSript at the end of the code as a function.. Get the idea, Hope this helped you,,
//
$(document).ready(function() {
//Button1 Click
$("button").click(function(){
//initialize inputs here
var email =$("#email").val;
var input1=$("#input1").val;
//Validate Inputs Here
if(IsEmail(email)==true && input1!=""){
return true
}
else{
return false;
}
//Loading the first content after validating inputs
$("#content").load("<?php echo base_url().'survey/categories' ?>");
//To Trigger the other button
$('#button1').trigger('click');
});
//Button1 Trigger Will fire Click event
$("#button1").click(function () {
$("#content").load("<?php echo base_url().'survey/budget_overview' ?>");
});
});
//Email Validation In JavaScript
function IsEmail(email) {
var regex = /^([a-zA-Z0-9_\.\-\+])+\#(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/;
return regex.test(email);
}
I think the problem is with your syntax. You have to specify a file URL in the load method like this:
$(document).ready(function(){
$("form").submit(function(){
$("#content").load("myfile.php");
return false;
});
});
You can have a look on the load documentation.
Hi and thanks for taking some time to look at my question. I have a part of the page where content is dynamicly loaded into from another file. Reason for this is it needs to be live updated. Now I want to be able to apply jquery effects that are usually used for show/hiding content (slide, fade etc) to animate the difference between the current data and the new data. This is the code used to get the content and load it into the div:
function k() {
$.post("../includes/ajaxAgenda.php", {
limit : value
}, function(data) {
$('#tab-agenda').html(data);
});
};
$(document).ready(function() {
k();
$('#tab-agenda').scroll(function() {
loadMore();
});
});
var refreshId = setInterval(function() {
k();
}, 1000);
So I guess my question is how do I animate what gets loaded in so it doesn't just "pop" from one content to another?
edit: I tried using the .live instead of .scroll but it doesn't seem to work:
$(document).ready(function() {
$('#tab-agenda').live("scroll",function() {
alert("hi");
loadMore();
});
});
You need to use live function of jquery to bind the dynamically added elements.
Ref: http://api.jquery.com/live/
Try this :
$('#tab-agenda').live("scroll",function() {
loadMore();
});
I suggest you to add the ajax loader image with proper css over the content/ div as like below.
function loadmore(){
$("#loader").css('display','block');
//your
//code
//here
$("#loader").css('display','none');
}
html
<img id="loader" src="ajax-loader.gif" style="display:none" />
<div id="content">
your cont to display
</div>
I have the following information in my html
<div idd="8327" id="like" class="geen">Like</div>
<div idd="8329" id="like" class="geen">Like</div>
<div idd="8330" id="like" class="geen">Like</div>
<div idd="8331" id="like" class="geen">Like</div>
I want to send the ID to a specific php page to execute with .get.
it works. but it only works for the first div. The script is only executed when clicking the div with id 8327. When clicking another div, nothing happens :
What can be wrong ?
<script type="text/javascript">
$(document).ready(function() {
$("#like").click(function(event){
var code = $(this).attr("idd");
$.get("like.php", { code1: code, code2: "Kim" } );
alert("Thanks for clicking!");
});
});
</script>
when you use the id selector in Jquery you only select the first element so to get all elements use a class selector instead. So change:
$("#like").click(
To
$(".geen").click(
Switch your selector to use the class. jQuery assumes that # (id) is unique and will use the built in browser function document.getElementById().
$(".geen").click(function(event){
var code = $(this).attr("idd");
$.get("like.php", { code1: code, code2: "Kim" } );
alert("Thanks for clicking!");
});
use your class as selector because id can not be duplicate( which is in your case)
So through this
$(".geen").click(function(event){
var code = $(this).attr("idd");
$.get("like.php", { code1: code, code2: "Kim" } );
alert("Thanks for clicking!");
});
I have a form with number of submit type as images. Each image has a different title. I need to find out the title of the clicked image. But my click function inside form submit is not working.
My form is:
<form action='log.php' id='logForm' method='post' >
<?
for($j=1;$j<=5;$j++)
{
?>
<input type="image" src="<?=$img;?>" title="<?=$url;?> id="<?="image".$j?> class="images" />
<?
}
?>
</form>
Jquery:
$("#logForm").submit(function(e)
{
$(".advt_image").click(function(event) {
var href=event.target.title;
});
var Form = { };
Form['inputFree'] = $("#inputFree").val();
// if($("#freeTOS").is(":checked"))
Form['freeTOS'] = '1';
$(".active").hide().removeClass('active');
$("#paneLoading").show().addClass('active');
var url="http://"+href;
$.post('processFree.php', Form, function(data)
{
if(data == "Success")
{
$("#FreeErrors").html('').hide();
swapToPane('paneSuccess');
setTimeout( function() { location=url }, 2500 );
return;
}
swapToPane('paneFree');
$("#FreeErrors").html(data).show();
});
return false;
});
How can I get the title value of clicked image inside this $("#logForm").submit(function())?
How can I use the id of clicked image for that?
You can use event.target property
$("#logForm").submit(function(e)
alert($(e.target).attr('title'));
});
http://api.jquery.com/event.target/
[UPDATE]
I just realized it wouldn't work. I don't think there is a simple solution to this. You have to track the click event on the input and use it later.
jQuery submit, how can I know what submit button was pressed?
$(document).ready(function() {
var target = null;
$('#form :input[type="image"]').click(function() {
target = this;
alert(target);
});
$('#form').submit(function() {
alert($(target).attr('title'));
});
});
[Update 2] - .focus is not working, but .click is working
http://jsfiddle.net/gjSJh/1/
The way i see it, you have multiple submit buttons. Instead of calling the function on submit, call it on the click of these buttons so you can easily access the one the user chose:
$('input.images').click(function(e) {
e.preventDefault(); //stop the default submit from occuring
alert($(this).attr('title');
//do your other functions here.
});
// Runtime click event for all elements
$(document).on('vclick', '.control', function (e) { // .control is classname of the elements
var control = e.target;
alert(e.currentTarget[0].id);
});
if you are not getting proper message in alert, just debug using Firebug.
Check following code you can get the title of clicked image.
Single click
$(document).ready(function()
{
$('#logForm').submit(function(e){
$(".images").click(function(event) {
alert(event.target.title);
});
return false;
});
});
Double click
$(document).ready(function()
{
$('#logForm').submit(function(e){
$(".images").dblclick(function(event) {
alert(event.target.title);
});
return false;
});
});
add following ondomready in your rendering page
$(document).ready(function(){
$("form input[type=image]").click(function() {
$("input[type=image]", $(this).parents("form")).removeAttr("clicked");
$(this).attr("clicked", "true");
});
});
Now in your form's submitt action add follwing behaviour and yupeee!... you got it!....
$("#logForm").submit(function(e)
{
var title = $("input[type=image][clicked=true]",e.target).attr("title");
.....
.....
});