I've created a regular expression: ^\\[(.*)\\]$
to find all strings [....] eg. [general]
and I need to replace it with ['general']
but it is not working
in Netbeans php also I need lowercase like general_offline
Thanks
I see two things that would probably make problems
You used the anchors ^ and $. they match the start and the end of the string, if you are searching inside a larger text it will not find them. If so, just remove them:
\\[(.*)\\]
.* is greedy. That means \\[(.*)\\] will match from the frist opening [ to the last closing ]. If so add a ? after the quantifier to change the matching behaviour to "lazy".
\\[(.*?)\\]
See it here on Regexr
Strange this one works: (\[.*]) almost because I need to find inside without [ ]
Related
I am looking for a pattern that matches everything until the first occurrence of a specific character, say a ";" - a semicolon.
I wrote this:
/^(.*);/
But it actually matches everything (including the semicolon) until the last occurrence of a semicolon.
You need
/^[^;]*/
The [^;] is a character class, it matches everything but a semicolon.
^ (start of line anchor) is added to the beginning of the regex so only the first match on each line is captured. This may or may not be required, depending on whether possible subsequent matches are desired.
To cite the perlre manpage:
You can specify a character class, by enclosing a list of characters in [] , which will match any character from the list. If the first character after the "[" is "^", the class matches any character not in the list.
This should work in most regex dialects.
Would;
/^(.*?);/
work?
The ? is a lazy operator, so the regex grabs as little as possible before matching the ;.
/^[^;]*/
The [^;] says match anything except a semicolon. The square brackets are a set matching operator, it's essentially, match any character in this set of characters, the ^ at the start makes it an inverse match, so match anything not in this set.
None of the proposed answers did work for me. (e.g. in notepad++)
But
^.*?(?=\;)
did.
Try /[^;]*/
Google regex character classes for details.
sample text:
"this is a test sentence; to prove this regex; that is g;iven below"
If for example we have the sample text above, the regex /(.*?\;)/ will give you everything until the first occurence of semicolon (;), including the semicolon: "this is a test sentence;"
Try /[^;]*/
That's a negating character class.
This was very helpful for me as I was trying to figure out how to match all the characters in an xml tag including attributes. I was running into the "matches everything to the end" problem with:
/<simpleChoice.*>/
but was able to resolve the issue with:
/<simpleChoice[^>]*>/
after reading this post. Thanks all.
this is not a regex solution, but something simple enough for your problem description. Just split your string and get the first item from your array.
$str = "match everything until first ; blah ; blah end ";
$s = explode(";",$str,2);
print $s[0];
output
$ php test.php
match everything until first
This will match up to the first occurrence only in each string and will ignore subsequent occurrences.
/^([^;]*);*/
"/^([^\/]*)\/$/" worked for me, to get only top "folders" from an array like:
a/ <- this
a/b/
c/ <- this
c/d/
/d/e/
f/ <- this
Really kinda sad that no one has given you the correct answer....
In regex, ? makes it non greedy. By default regex will match as much as it can (greedy)
Simply add a ? and it will be non-greedy and match as little as possible!
Good luck, hope that helps.
This works for getting the content from the beginning of a line till the first word,
/^.*?([^\s]+)/gm
I faced a similar problem including all the characters until the first comma after the word entity_id. The solution that worked was this in Bigquery:
SELECT regexp_extract(line_items,r'entity_id*[^,]*')
I'm trying to match
Some HTML content
Using preg_match
\<\!\-\- FOR (\d+) \-\-\>(.*)\<\!\-\- END FOR \-\-\>
Doesn't work since they are on different lines.
First you need to learn that < ! - > are not special characters. Escaping them with backslashes makes you look a bit silly.
Then learn about the /x and /s flags. One of them is what you need. The other is me trying to trick you into learning something unrelated.
Then test your regular expression with some HTML content that contains two or more of those FOR/END FORs and see what happens.
Also, you need to look into how to make your capturing conditions "greedy" or "non greedy". By default, matches will be greedy. So a condition such as "A(.)B" with the string "A1B A2B A3B" would find one match "1B A2B A3" - everything form the first "A" to the last "B". If you wanted to find all the values between each set of A/B, then you need make the match non-greedy - "A(.?)B"
Input:
http://foo/bar/baz/../../qux/
Desired Output:
http://foo/qux/
This can be achieved using regular expression (unless someone can suggest a more efficient alternative).
If it was a forward look-up, it would be as simple as:
/\.\.\/[^\/]+/
Though I am not familiar with with how to make a backward look up for the first "/" (ie. not doing /[a-z0-9-_]+\/\.\./).
One of the solutions I thought of is to use strrev then apply forward look up regex (first example) and then do strrev. Though I am sure there is a more efficient way.
Not the clearest question I've ever seen, but if I understand what you're asking, I think you only need to switch around what you have like this:
/[^\/]+/\.\./
...then replace that with a /
Do that until no replacements are made and you should have what you want
EDIT
Your attempt seems to try to match a forward slash / and two dots \.\. followed by a slash / (or \/ - they should both match the same thing), then one or more non-slash characters[^/]+, terminated by a slash /. Flipping it around, you want to find a slash followed by one or more non-slash characters and a terminating slash, then two dots and a final slash.
You may be confused into thinking that the regex engine parses and consumes things as it goes (so you wouldn't want to consume a directory name that is not followed by the correct number of dots), but that's not how it typically works - a regex engine matches the entire expression before it replaces or returns anything. So, you can have two dots followed by a directory name, or a directory name followed by two dots - it doesn't make a difference to the engine.
If your attempt is using the slash-enclosed Perl-style syntax, then you would of course need to use \/ for any slashes you're trying to match such as the middle one, but I would also recommend matching and replacing the enclosing slashes in the url as well: I think the PHP would be something like
preg_replace('/\/[^\/]+\/\.\.\//', '/', $input)
(??)
Technically what do you want is replace segments of '/path1/path2/../../' by '/' what is needed to do that is match 'pathx/'^n'../'^n that is definetly NOT a regular expression (Context Free Lenguaje) ... but most of Regex libraries supports some non regular lenguajes and can (with a lot of effort) manage those kind of lenguajes.
An easy way to solve it is stay in Regular Expressions and cycle several times, replacing '/[^./]+/../' by ''
if you still to do it in a single step, Lookahead and grouping is needed, but it will be hard to write it, (I'm not so used on, but I will try)
EDIT:
I've found the solution in only 1 REGEX... but should use PCRE Regex
([^/.]+/(?1)?\.\./)
I've based my solution on the folowing link:
Match a^n b^n c^n (e.g. "aaabbbccc") using regular expressions (PCRE)
(note that dots are "forbidden" in the first section, you cannot have path.1/path.2/ if you whant to is quite more complex because you should admit them but forbid '../' as valid in the first section
this sub expression is for admiting the path names like 'path1/'
[^/.]+/
this sub expression is for admiting the double dots.
\.\./
you can test the regexp in
https://www.debuggex.com/
(remember to set it in PCRE mode)
Here is a working copy:
https://eval.in/52675
I'm trying to write a (I think) pretty simple RegEx with PHP but it's not working.
Basically I have a block defined like this:
%%%%blockname%%%%
stuff goes here
%%%%/blockname%%%%
I'm not any good at RegEx, but this is what I tried:
preg_match_all('/^%%%%(.*?)%%%%(.*?)%%%%\/(.*?)%%%%$/i',$input,$matches);
It returns an array with 4 empty entries.
I guess it also, apart from actually working, needs some sort of pointer for the third match because it should be equal to the first one?
Please enlighten me :)
You need to allow the dot to match newlines, and to allow ^ and $ to match at the start and end of lines (not just the entire string):
preg_match_all('/^%%%%(.*?)%%%%(.*?)%%%%\/(.*?)%%%%$/sm',$input,$matches);
The s (single-line) option makes the dot match any character including newlines.
The m (multi-line) option allows ^ and $ to match at the start and end of lines.
The i option is unnecessary in your regex since there are no case-sensitive characters in it.
Then, to answer the second part of your question: If blockname is the same in both cases, then you can make that explicit by using a backreference to the first capturing group:
preg_match_all('/^%%%%(.*?)%%%%(.*?)%%%%\/\1%%%%$/sm',$input,$matches);
I'm pretty sure you can't since these operations would need to save a variable and you can't in regex. You should try to do this using PHP's built-in token parser. http://php.net/manual/en/function.token-get-all.php
I'm working on a registration script for my client's product sales website.
I'm currently working on a reference ID input area, and I want to make sure that the reference ID is within the correct parameters of the payment method
The Reference ID will look something like this: XXXXX-XXXXX-XXXXX
I'm trying to use this RegEx pattern to match it: /(\w+){5}-(\w+){5}-(\w+){5}/
This matches it perfectly, but it also matches XXXXX-XXXXX-XXXXXXXXXX
Or at least it finds a match in there. I want it to make sure the entire string matches. I'm not too familiar with RegEx
How can I do this?
You need to use start and finish anchors. Alternatively, if you don't need to capture those groups, you can omit the parenthesis.
Also, the +{5} means match more than once exactly 5 times. I believe you didn't want that so I dropped the +.
/^\w{5}-\w{5}-\w{5}\z/
Also, I used \z so your string doesn't match "abcde-12345-edcba\n".
Use ^ and $ to match the start and end of the input string, respectively.
Also note that your use of + was superfluous, as (\w+){5} means "a word character, at least once, times five" which means it can match at least five times. You probably meant (\w){5} (or just \w{5} if you don't need the backreference; I'll assume in my example that you do).
/^(\w){5}-(\w){5}-(\w){5}$/
put the regular expression in between ^ and $ to match the whole string and check if it matches anything
example:
/^(\w+){5}-(\w+){5}-(\w+){5}$/
Try
/^([\w]{5,5})-([\w]{5,5})-([\w]{5,5})$/i
There are several online regex tester out there, I work with this one before I code.
Enclose it in "^" and "$" thus:
/^(\w+){5}-(\w+){5}-(\w+){5}$/
You need ^ to match the start of the string and $ to match the end:
/^\w{5}-\w{5}-\w{5}$/
Note that (\w+){5} is incorrect because that means five repetitions of \w+, but that in turn means "one or more word characters".
/^(\w){5}-(\w){5}-(\w){5}$/
You need to explicitly say that you want the pattern to start at the beginning of the string and end at it's ending.
You can improve it: /^((\w){5}-){2}(\w){5}$/ ; this way, you can easily modify the number of elements your serial number might have.
Use ^ and $ to mark the start and end of the regex string:
/^\w{5}-\w{5}-\w{5}$/
http://www.regular-expressions.info/anchors.html
In preg, \b marks word boundaries. So you could try with something like
/\b(\w+){5}-(\w+){5}-(\w+){5}\b/