i want use ajax for sent to saveKrs and save to database. i'm use codeigniter, when i click submit button, there's no event. please help me
form_checkbox('checkKrs[]',$row->id, FALSE, 'id=checkKrs')
<script type="text/javascript">
$('#save_krs').click(function(){
var id_student= $('#id_student').val();
var id_semester = $('#id_semester').val();
var checkKrs = new Array();
$("input:checked").each(function() {
data['checkKrs[]'].push($(this).val());
})
var data = {
checkKrs:checkKrs,
id_semester:id_semester,
id_mahasiswa:id_mahasiswa,
is_ajax: '1'
};
$.ajax({
url: "saveKrs",
type: 'POST',
data: data,
beforeSend : fnLoadStart,
complete : fnLoadStop,
success: function(msg) {
//$('#form_data').hide();
$('#form_data').html(msg);
//$('#report').show();
}
});
alert('Pengisian KRS tidak boleh kosong');
return false;
});
</script>
Make you sure that you have the right controler and if you form match it.
Related
Hello overflowers!
I can't seem to manage to send my ajax data over to my php page correctly, it has worked perfectly fine before but now it is not working.
I'm getting the correct data via console.log but on my php page i'm getting Undefined index error.
Jquery
var task_takers_pre = [];
var task_takers = [];
var i = 1;
$(".new-task-takers ul.select_takers li").on('click', function(){
$(this).each(function(){
$(this).toggleClass("active");
if($(this).find('.fa').length > 0){
$(this).find('.fa').remove();
i -= 1;
var removeItem = $(this).data("id");
task_takers_pre.remove(removeItem);
console.log(task_takers_pre);
}else{
$('<i class="fa fa-check" aria-hidden="true"></i>').insertBefore($(this).find("div"));
i += 1;
task_takers_pre[i] = $(this).data("id");
console.log(task_takers_pre);
}
$.each(task_takers_pre, function (index, value) {
if ($.inArray(value, task_takers) == -1) {
task_takers.push(index, value);
}
});
});
});
$("#new-task").on('submit', function(){
console.log(task_takers_pre);
$.ajax({
type: 'POST',
url: '',
cache: false,
data: {task_takers_pre : task_takers_pre },
success: function(data) {
//console.log(data)
}
});
});
PHP
if(isset($_POST['task_submit'])){
$task_takers = $_POST['task_takers_pre'][0];
var_dump($task_takers);
}
EDIT
jQuery
var task_takers_pre = [];
var task_takers = [];
var i = 1;
$(".new-task-takers ul.select_takers li").on('click', function(){
$(this).each(function(){
$(this).toggleClass("active");
if($(this).find('.fa').length > 0){
$(this).find('.fa').remove();
i -= 1;
var removeItem = $(this).data("id");
task_takers_pre.remove(removeItem);
console.log(task_takers_pre);
}else{
$('<i class="fa fa-check" aria-hidden="true"></i>').insertBefore($(this).find("div"));
i += 1;
task_takers_pre[i] = $(this).data("id");
console.log(task_takers_pre);
}
$.each(task_takers_pre, function (index, value) {
if ($.inArray(value, task_takers) == -1) {
task_takers.push(index, value);
}
});
});
});
$(".assign").on('click', function(){
console.log(task_takers_pre);
$.ajax({
type: 'POST',
url: './core/includes/new_task.php',
cache: false,
data: {task_takers_pre : task_takers_pre},
success: function(data) {
//console.log(data)
}
});
$.ajax({
type: 'POST',
url: '',
cache: false,
data: {'task_takers_pre' : task_takers_pre},
success: function(data) {
//console.log(data)
}
});
});
PHP
if(isset($_POST['task_takers_pre'][0])){
$task_takers = $_POST['task_takers_pre'][0]; // Just for testing
var_dump($task_takers); // Just for testing
}
if(isset($_POST['task_takers_pre'])){
$task_takers2 = $_POST['task_takers_pre']; // Just for testing
var_dump($task_takers2); // Just for testing
}
What you are attempting to do is use the same PHP code to handle the Button Press from the Form AND the AJAX Call. Don't!
(note: This answer is Only based upon the code that has been provided and what is trying to achieved with this code.)
So your current PHP is, which I am guessing is what you call when you click the submit button... In that case $_POST['task_takers_pre'] will not exist as you are generating that from the JS and sending it in the AJAX Call.
Write a separate AJAX Call.
You need to create a separate file to handle your AJAX calls and have it perform what duties it needs to perform.
// This is just for testing my AJAX Call
public function ajax_post(){
if(isset($_POST['task_takers_pre'])){
$task_takers = $_POST['task_takers_pre'][0]; // Just for testing
var_dump($task_takers); // Just for testing
die();
}
else {
// Illegal access/entry do something...
echo 'Error - I had better check what I am posting.';
die();
}
}
If you juse want to send some data in the AJAX Call when you click the submit button,you could return false to prevent form submission in the submit event.
$("#new-task").on("submit", function(){
$.ajax({
type: "POST",
url: "",
cache: false,
data: {task_submit:1, task_takers_pre: task_takers_pre},
success: function(data){
console.log(data);
}
});
return false;
});
I am new in laravel and need help.
These are the values I'm getting via ajax, all values are to be stored in db, but how do I validate[check] if there are existing values or not before submitting a form using ajax?
$("#submit").click(function(e){
e.preventDefault();
var url = "{!! URL::to('/') !!}";
var id="{!! #$department->id !!}";
var token = "{!! csrf_token() !!}";
var customer_id = $("#customer_id").val();
var visiting_address1 = $("#visiting_address1").val();
var department_id = $("#department_id").val();
// AJAX Code To Submit Form.
$.ajax({
type: "POST",
url: url+"/customer/"+customer_id+"/popup_store",
data: { '_token':token, 'rest':'true', 'customer_id':$("#customer_id").val(), 'main_address':$("#main_address").val(),'visiting_city':$("#visiting_city").val(),'visiting_address':$("#visiting_address1").val(),'visiting_zip':$("#visiting_zip").val()},
async : false,
success : function(data) {
if(data == "success")
{
$("#addrecords").modal('hide');
}
else
alert(data);
}
});
});
First of all define you Jquery validation for you form like this:
$("#myForm").validate({
// Specify the validation rules
rules: {
name: "required",
},
// Specify the validation error messages
messages: {
name: "Please enter name",
},
submitHandler: function (form) {
// leave it blank here.
}
});
And then in your click button of submit button, write if condition to check validations:
$("#submit").click(function (e) {
if ($('#myForm').valid()) {
// your Ajax Call Code
} else {
return false;
}
});
I created a PHP page that Insert into the database the value in the textbox, when someone click on the button it's redirect to the php page, But I want it to make the PHP action without redirecting, So how can I do it in ajax?
Thank you
woz and dragoste are right. Use jQuery to make it happen. you can use this function, it will fit to your requirement.
Here i used jQuery validation library http://jqueryvalidation.org/ to validate the form .
$(function()
{
var form = $("#booking_form").validate();
$('#success').hide();
$('#failure').hide();
$("form#your_form").submit(function() {
if(form.valid())
{
var name = $("#txtName").val();
var email = $("#txtEmail").val();
var phone = $("#txtPhone").val();
$.ajax({
url: "process_form.php",
type: "POST",
data: {
'name': name,
'email': email,
'phone': phone
},
dataType: "json",
success: function(data) {
if(data.status == 'success')
{
$('#your_form').hide();
$('#success').show();
}
else if(data.status == 'error')
{
$('#failure').show();
}
}
});
return false;
}
});
});
i use this script
<script type="text/javascript">
$(function () {
$(".comment_button").click(function () {
var element = $(this);
var boxval = $("#content").val();
var dataString = 'content=' + boxval;
if (boxval == '') {
alert("Please Enter Some Text");
} else {
$("#flash").show();
$("#flash").fadeIn(400).html('<img src="ajax.gif" align="absmiddle"> <span class="loading">Loading Update...</span>');
$.ajax({
type: "POST",
url: "update_data.php",
data: dataString,
cache: false,
success: function (html) {
$("ol#update").prepend(html);
$("ol#update li:first").slideDown("slow");
document.getElementById('content').value = '';
$("#flash").hide();
}
});
}
return false;
});
$('.delete_update').live("click", function () {
var ID = $(this).attr("id");
var dataString = 'msg_id=' + ID;
if (confirm("Sure you want to delete this update? There is NO undo!")) {
$.ajax({
type: "POST",
url: "delete_data.php",
data: dataString,
cache: false,
success: function (html) {
$(".bar" + ID).slideUp('slow', function () {
$(this).remove();
});
}
});
}
return false;
});
});
</script>
this script combine live update and delete record using jquery and ajax
the problem is when I refresh the page, the record will disappear .. how to keep records that show up are not dissapear when the page is reloaded?
First Check the comment list. Did you put any limit in query, if so then use Order by Primary ID desc.So it would display latest records first.
When you delete any record, check whether it is actually deleted from database or not. Because you are not checking whether record actually deleted or not as per the code you given.
Assuming you are using update_data.php and delete_data.php to manipulate some database, you could use PHP to render the page initially using the data that is currently on the database.
If that is not the case, and you don't have access to that database (it could be a third party web service, right?), or you don't want to do that for any reason, you could use cookie like Saeed answered.
I'm kinda new to jQuery but understand it for the most part. My problem is that when my ajax call which refreshes the entire div is done, all my dynamically created forms don't work. If you try and submit them, the event doens't work properly and just tries to do a normal form submit. I have all the other items such as links bound using the .live() which seem to work great. Just the form dies.
How do I rebind the dynamically created forms after the ajax call? They all have id of formname_id. I tried to use bind but it doesn't work as below. Any help is appreciated.
Here is the code
jQuery(document).ready(function(){
jQuery("form[id^='commentform_']").each(function(){
var id = parseInt(this.id.replace("commentform_", ""));
jQuery(this).bind('submit', function(e) {
var action = jQuery('#action_' + id).attr('value');
var act_id = ('1');
jQuery.ajax({
type: "POST",
url: "ajax/modify.php",
data: "action="+ action +"& act_id="+ act_id,
success: function(response){
jQuery('#CommentsContainer_' + id).html(response);
jQuery('#commentform_' + id)[0].reset();
}
});
return false;
});
});
});
Try doing something like this:
jQuery("form[id^='commentform_']").live('submit',function(){
var id = parseInt(this.id.replace("commentform_", ""));
var action = jQuery('#action_' + id).attr('value');
var act_id = ('1');
jQuery.ajax({
type: "POST",
url: "ajax/modify.php",
data: {"action": action, "act_id": act_id},
success: function(response){
jQuery('#CommentsContainer_' + id).html(response);
jQuery('#commentform_' + id)[0].reset();
}
});
return false;
});
No need to loop over the forms to bind to them. If you can use delegate instead of live do so.
Why don't you over-ride the normal form submit:
function addNewitem() {
$('#new_item_form').submit(function() {
$.get("includes/ItemEdit.php", {
newItem: true
},
function(msg) {
isNewItem = true;
$("#new_item").hide();
$('#item_list').hide();
$("#item_edit").html( msg );
$("#item_edit").show();
editActiveEvent();
});
return false;
});
}
Don't forget to return false. or do a .preventDefault
I have gotten this to work adding the event in the function call and using event.preventDefault(); BUT of course only in FF. Doesn't work in IE7..
jQuery("form[id^='commentform_']").live('submit',function(event){
var id = parseInt(this.id.replace("commentform_", ""));
var action = jQuery('#action_' + id).attr('value');
var act_id = ('1');
jQuery.ajax({
type: "POST",
url: "ajax/modify.php",
data: {"action": action, "act_id": act_id},
success: function(response){
jQuery('#CommentsContainer_' + id).html(response);
jQuery('#commentform_' + id)[0].reset();
}
});
event.preventDefault();});
But IE7 still tries to sumbit the action. arrgggh.. Anything I'm doing wrong??