How use datas in same column - php

Screenshot mysql:
If I want to use the data in column “sender name” or "subject" then i use code
include ("connect.php");
$model = mysql_query("SELECT * FROM entries WHERE entries_id='3' limit 1");
$profil = mysql_fetch_array($model);
echo $profil[sender_name];
echo $profil[subject];
but how to use other data that users enter and are located in the column “data”?
for example
in the column “data” there are fields City, Address, Phone,…
What code to use to insert just name of the city (in example: Berlin) ?

The value in the data column is serialized. To use it you must first unserialize it (see php.net - unserialize).
For example (using your logic, I'm pretty sure you don't need the limit part of this query.)
include ("connect.php");
$model = mysql_query("SELECT * FROM entries WHERE entries_id='3' limit 1");
$profile = mysql_fetch_array($model);
$data = unserialize($profile['data']); //This is now an array of the data
To see what the unserialized data looks like you can then do this
print_r($data);
And to use the unserialized data to get, say the value, you would do
echo $data[0]['value']; //This will print "Berlin" for entries_id = 3.

Related

PHP function issues with array

I have a postgres table with four columns labelled dstart which is date data type,
dend which is also a date data type, dcontract which is a date data type and id which is a integer. I am trying to run a php code to get the data using an array and use it in the body of my application. But when I test the array and try to echo some values... My browser just displays the word array... Is there anyway I can be able to retrieve the data or fix this code? Please see code below
<?php
function getLiveDate($campid)
{
global $conn,$agencies;
$return=array(
'livedate'=>'',
'campid'=>'',
'enddate'=>'',
'dateContract'=>'',
);
$sql = "SELECT id, dcontract, dstart, dend
FROM campaigns
WHERE id = '".$campid."' ORDER BY dstart DESC LIMIT 1";
$r = pg_query($conn,$sql);
if ($r)
{
$d = pg_fetch_array($r);
if (!empty($d))
{
$return['livedate'] = $d['dstart'];
$return['campid'] = $d['id'];
$return['enddate'] = $d['dend'];
$return['dateContract'] = $d['dcontract'];
}
}
#pg_free_result($r);
return $return;
}
I am pretty sure, your array $d is "multi-dimensional" and pg_fetch_array() returns an array of arrays, because the result of SQL queries in general may contain multiple rows. You limited it to one row, but you certainly get the correct values by assinging $return['livedata'] = $d[0]['dstart']; or $return['livedata'] = $d['dstart'][0]; and so on (I am not familiar with that particularly function for I usually use MySQL instead of Postgre).
Besides, try echoing your data by means of print_r() instead of echo.
The $return variable is an array, if you want shows the content, you must use print_r or var_dump not echo.

PHP Retrieve Database Value Error

So i have this so far..
if(isset($_POST['Decrypt']))
{
$dbinary = strtoupper($_POST['user2']);
$sqlvalue = "SELECT `value` FROM `license` WHERE `binary` = '$dbinary'";
$dvalue = mysql_query($sqlvalue) or die(mysql_error());
$dvalue = mysql_fetch_array($dvalue);
$dvalue['value'];
}
I have a field where the user enters a binary code which was encrypted. (The encrypt part works). This is supposed to retrieve the value from the database. When ever i do it, instead of the value showing up, it says "Array".
Please help me out.
This is because you can't just echo an array. You need to use functions like var_dump(); or print_r();
looks like you have more than one row in your table matching criteria. Try using while loop to retrieve data.
while($row = mysql_fetch_assoc($dvalue)){
//$row['value'];
}

Obtain Column name(s) of database via PHP

I have a postgresql database and I am connecting to and reading from it via php. Ive put in php codes that give me back the result to the query i pass from my code.
Ex- My code :(Note - My HTML page uses a form which asks for input and searches for the given input in the database)
<?php
$result = pg_prepare($dbh, "Query1", 'SELECT * FROM test.bact WHERE disease = $1');
$result = pg_execute($dbh, "Query1", array($disease));
if (!$result) {
die("Error in SQL query: " . pg_last_error());
}
//$rows = pg_fetch_all($result)
/*// iterate over result set
// print each row*/
while ($row = pg_fetch_array($result)) {
echo $row[0]." ".$row[1]. "<br />";
}
From the above piece of code I get my information as strings separated by a space ( echo $row[0]." ".$row[1])
example: Information at row[0]<space>Information at row[1]
What I want - I want the retrieved data in a more organised form i.e. with the column name.
How it should look like -
Name of Column : Data
Name of column : Data ...and so on.
I know there is way in mysql using the mysql_fetch_field, but I wanted something for postgresql. Since I am new to php n databases I am not really sure as to how will I use this.
Any help would be appreciated.
You can use pg_field_name or pg_fetch_assoc

php function save result at array

hello i want to create function with returning data, for example when i have the function advert i want to make it every time show what i need, i have the table id, sub_id, name, date, and i want to create the function that i can print every time what i need advert(id), advert(name), i want to make it to show every time what i need exactly and i want to save all my result in array, and every time grab the exactly row that i want
<?php
function advert($data){
$id = $_GET['id'];
$query = mysql_query("SELECT *FROM advertisement WHERE id = $id");
while($row = mysql_fetch_assoc($query)){
$data = array(
'id' => $row['id']
);
}
return $data;
}
echo advert($data['id']);
?>
but my result every time is empty, can you help me please?
There are so many flaws in this short piece of code that the only good advice would be to get some beginners tutorial. But i'll put some effort into explaining a few things. Hopefully it will help.
First step would be the line function advert($data), you are passing a parameter $data to the method. Now later on you are using the same variable $data in the return field. I guess that you attempted to let the function know what variable you wanted to fill, but that is not needed.
If I understand correctly what you are trying to do, I would pass in the $id parameter. Then you can use this function to get the array based on the ID you supplied and it doesnt always have to come from the querystring (although it could).
function advert($id) {
}
Now we have the basics setup, we want to get the information from the database. Your code would work, but it is also vulnerable for SQL injection. Since thats a topic on its own, I suggest you use google to find information on the subject. For now I'll just say that you need to verify user input. In this case you want an ID, which I assume is numeric, so make sure its numeric. I'll also asume you have an integer ID, so that would make.
function advert($id) {
if (!is_int($id))
return "possible SQL injection.";
}
Then I'll make another assumption, and that is that the ID is unique and that you only expect 1 result to be returned. Because there is only one result, we can use the LIMIT option in the query and dont need the while loop.
Also keep in mind that mysql_ functions are deprecated and should no longer be used. Try to switch to mysqli or PDO. But for now, i'll just use your code.
Adding just the ID to the $data array seems useless, but I guess you understand how to add the other columns from the SQL table.
function advert($id) {
if (!is_int($id))
return "possible SQL injection.";
$query = mysql_query("SELECT * FROM advertisement WHERE id = $id LIMIT 1");
$row = mysql_fetch_assoc($query);
$data = array(
'id' => $row['id']
);
return $data;
}
Not to call this method we can use the GET parameter like so. Please be advised that echoing an array will most likely not give you the desired result. I would store the result in a variable and then continue using it.
$ad = advert($_GET['id']);
if (!is_array($ad)) {
echo $ad; //for sql injection message
} else {
print_r($ad) //to show array content
}
Do you want to show the specific column value in the return result , like if you pass as as Id , you want to return only Id column data.
Loop through all the key of the row array and on matching with the incoming Column name you can get the value and break the loop.
Check this link : php & mysql - loop through columns of a single row and passing values into array
You are already passing ID as function argument. Also put space between * and FROM.
So use it as below.
$query = mysql_query("SELECT * FROM advertisement WHERE id = '".$data."'");
OR
function advert($id)
{
$query = mysql_query("SELECT * FROM advertisement WHERE id = '".$id."'");
$data = array();
while($row = mysql_fetch_assoc($query))
{
$data[] = $row;
}
return $data;
}
Do not use mysql_* as that is deprecated instead use PDO or MYSQLI_*
try this:
<?php
function advert($id){
$data= array();
//$id = $_GET['id'];
$query = mysql_query("SELECT *FROM advertisement WHERE id = $id");
while($row = mysql_fetch_assoc($query)){
array_push($data,$row['id']);
}
return $data;
}
var_dump($data);
//echo advert($data['id']);
?>

echo fitered data in table on another page?

Still green in php but I'm liking it. Anyways...
I have a table that retrieves information from my db which gets its data from a date search, so I want it to be retrieved in another table after being filtered.
I tried a couple of things including passing the variable that is being used in filtering it (date) into another window so that the table retrieves this information there with id as date from previous page.
On my search page i have this:
<?php
$tester = $_POST['Date'];
mysql_select_db($database_dbconnkk, $dbconnkk);
$query_equ = "SELECT * FROM daily_reports WHERE Date = '$tester' ORDER BY id ASC";
?>
And a table that repeats the same which is working.
I have a link that opens window to this page with an attempt to retrieve data from previous test.
<?php
$tester2 = $_Get['Date'];
Also tried passing Date as id:
(id=<?php echo $row_equ['Date']; ?>)
Suppose problem is here:
$tester2 = $_Get['Date'];
Variable names are case sensitive in PHP, so this line should look like:
$tester2 = $_GET['Date'];
instead. Everything else looks like it should work.
i got it. passed the date i was using on the filter in the same variable i was using to filter the records
?Date=<?php echo $tester; ?>
then on my new window i get the same into another variable(tester2)
$tester2 = $_GET['Date'];
select then echo in columns
$query_equ = "SELECT * FROM daily_reports WHERE Date = '$tester2' ORDER BY id ASC";

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