Echoing the elements of a shuffled array with PHP - php

I have an array of elements in PHP called...
$completeArray
...and I'm trying to store a randomized version of this array in my session called...
$_SESSION['videoArray']
...so I'm trying something like this...
$_SESSION['videoArray'] = shuffle($completeArray);
...but when I try to echo the first element of this randomized array like this...
$videoid = $_SESSION['videoArray'];
echo $videoid[0];
...all it's returning is the 'key' of the element. How do I randomize the array and be able to echo the actual elements of the new array?


shuffle take a reference of an array and Returns TRUE on success or FALSE on failure.
You should do:
shuffle($completeArray);
$_SESSION['videoArray'] = $completeArray;


You can try somethin like this:
$_SESSION['videoArray'] = $completeArray;
shuffle($_SESSION['videoArray']);

Related

Php access variable

In PHP i have array variable from another function like this
$v->params:
(
[{"username":"myusername","email":"myemail#gmail_com","phone":"0123456789","password":"abc123","fullname":"myfullname","register_ip":"127_0_0_1","country":"Qu\u1ed1c_Gia","birthday":"N\u0103m_sinh","gender":"male","bank_code":"Ng\u00e2n_h\u00e0ng","ip":"127_0_0_1","os":"Windows_10","device":"Computer","browser":"Mozilla_Firefox_77_0"}] =>
)
Now i want to access to it item, how can i code to access item value like this:
$password = $v->params->password; //myemail#gmail_com
I new with PHP thank you all

The data seems the wrong way round as it's the key of the array rather than a value.
So using array_keys()[0] to get the first key and then json_decode this...
$data = json_decode(array_keys($v->params)[0]);
you can then use the $data object to get at the values...
echo $data->username;

PHP JSON Arrays within an Array

I have a script that loops through and retrieves some specified values and adds them to a php array. I then have it return the value to this script:
//Returns the php array to loop through
$test_list= $db->DatabaseRequest($testing);
//Loops through the $test_list array and retrieves a row for each value
foreach ($test_list as $id => $test) {
$getList = $db->getTest($test['id']);
$id_export[] = $getList ;
}
print(json_encode($id_export));
This returns a JSON value of:
[[{"id":1,"amount":2,"type":"0"}], [{"id":2,"amount":25,"type":"0"}]]
This is causing problems when I try to parse the data onto my android App. The result needs to be something like this:
[{"id":1,"amount":2,"type":"0"}, {"id":2,"amount":25,"type":"0"}]
I realize that the loop is adding the array into another array. My question is how can I loop through a php array and put or keep all of those values into an array and output them in the JSON format above?

of course I think $getList contains an array you database's columns,
use
$id_export[] = $getList[0]
Maybe can do some checks to verify if your $getList array is effectively 1 size

$db->getTest() seems to be returning an array of a single object, maybe more, which you are then adding to a new array. Try one of the following:
If there will only ever be one row, just get the 0 index (the simplest):
$id_export[] = $db->getTest($test['id'])[0];
Or get the current array item:
$getList = $db->getTest($test['id']);
$id_export[] = current($getList); //optionally reset()
If there may be more than one row, merge them (probably a better and safer idea regardless):
$getList = $db->getTest($test['id']);
$id_export = array_merge((array)$id_export, $getList);

PHP adressing the first key in an array that changes

For example, lets say I have an array that looks liked
$stuff = array('random_string_1' => 'random_value_1','random_string_2' => 'random_value_2');
and then I call the asort() function and it changes the array around. How do I get the new first string without knowing what it actually is?

If you want to get the first value of the array you can use reset
reset($stuff);
If you want to also get the key use key
key($stuff);

If you need to get the first value, do it like this:
$stuff = array('random_string_1' => 'random_value_1','random_string_2' => 'random_value_2');
$values = array_values($stuff); // this is a consequential array with values in the order of the original array
var_dump($values[0]); // get first value..
var_dump($values[1]); // get second value..

Unable to assign value to php array

I am creating an array in php by assigning values retrieved from database. When I print the array it is displaying array as output and not its contents. However it does retrieve values from mysql.
$resultset=mysql_query("select isbn from tbl_book where publisherid='$publisherid'");
/***Retrieve Books*****/
while($resultISBNArray = mysql_fetch_assoc($resultset))
{
$isbn = $resultISBNArray["isbn"];
$myArr[]=$isbn;
}
echo $myArr

echoing any array always prints "Array". You need to pick individual values in the array (echo $myArr[0]) or use something like print_r().

You can not print an array. You have todo something like var_dump($myArr);

how to check if the second array key is an array?

i have an array which could look like this:
$config[$name][$array]['key'] = 'value'; // here it's an array
or
$config[$name][$array] = 'value'; // here it's not an array
i want to check if the second array key ('array') is an array or not.
could someone help me?

use the function is_array http://php.net/manual/en/function.is-array.php
if(is_array($config[$name][$array])) echo "Yup I'm an array";

PHP has a built in function, is_array. That should let you know whether or not you have an array, or a plain string.

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