Use PHP if() to match item in array - php

Question

I am working on an admin panel in which the code will display different if the PDO query returns all the admins from the admin table and the userid matches 1 of the admin id results. Only there can be an unlimited amount of admins and I don't want to be editing the code for each of them.
Would it be possible to do this (pseudo code):
if($userid isfoundin $result['admin_user_id']{
-- admin code here
}
I haven't yet written the admin table as I want more info on it first but if I cycle through the user table and look for id $query->fetchAll() then I get this:
array(30) { [0]=> array(2) { ["id"]=> string(1) "7" [0]=> string(1) "7" } [1]=> array(2) { ["id"]=> string(1) "6" [0]=> string(1) "6" } [2]=> array(2) { ["id"]=> string(1) "8" [0]=> string(1) "8" } [3]=> array(2) { ["id"]=> string(2) "31" [0]=> string(2) "31" } [4]=> array(2) { ["id"]=> string(2) "26" [0]=> string(2) "26" } [5]=> array(2) { ["id"]=> string(1) "4" [0]=> string(1) "4" } [6]=> array(2) { ["id"]=> string(2) "35" [0]=> string(2) "35" } [7]=> array(2) { ["id"]=> string(2) "21" [0]=> string(2) "21" } [8]=> array(2) { ["id"]=> string(2) "38" [0]=> string(2) "38" } [9]=> array(2) { ["id"]=> string(2) "24" [0]=> string(2) "24" } [10]=> array(2) { ["id"]=> string(2) "34" [0]=> string(2) "34" } [11]=> array(2) { ["id"]=> string(2) "20" [0]=> string(2) "20" } [12]=> array(2) { ["id"]=> string(2) "19" [0]=> string(2) "19" } [13]=> array(2) { ["id"]=> string(2) "23" [0]=> string(2) "23" } [14]=> array(2) { ["id"]=> string(2) "33" [0]=> string(2) "33" } [15]=> array(2) { ["id"]=> string(2) "28" [0]=> string(2) "28" } [16]=> array(2) { ["id"]=> string(1) "3" [0]=> string(1) "3" } [17]=> array(2) { ["id"]=> string(2) "15" [0]=> string(2) "15" } [18]=> array(2) { ["id"]=> string(1) "9" [0]=> string(1) "9" } [19]=> array(2) { ["id"]=> string(2) "25" [0]=> string(2) "25" } [20]=> array(2) { ["id"]=> string(1) "1" [0]=> string(1) "1" } [21]=> array(2) { ["id"]=> string(2) "32" [0]=> string(2) "32" } [22]=> array(2) { ["id"]=> string(1) "5" [0]=> string(1) "5" } [23]=> array(2) { ["id"]=> string(2) "18" [0]=> string(2) "18" } [24]=> array(2) { ["id"]=> string(2) "29" [0]=> string(2) "29" } [25]=> array(2) { ["id"]=> string(2) "27" [0]=> string(2) "27" } [26]=> array(2) { ["id"]=> string(2) "30" [0]=> string(2) "30" } [27]=> array(2) { ["id"]=> string(2) "22" [0]=> string(2) "22" } [28]=> array(2) { ["id"]=> string(2) "10" [0]=> string(2) "10" } [29]=> array(2) { ["id"]=> string(2) "36" [0]=> string(2) "36" } }
this si what I am trying to use right now
require_once $_SERVER['DOCUMENT_ROOT']."/resources/settings.php";
$query = $pdo->prepare("SELECT id FROM users");
$query->execute();
var_dump($query->fetchAll());
if (in_array($user['id'], $query->fetchAll())){
echo $user['id'];
}

Answer 1

Yes, you can use in_array() for this.
I assume that you have a set of users for admin. Say, it is:
$adminUsers = array("admin", "administrator");
# Or by your code
$adminUsers = $result['admin_user_id'];
Now the code part is like:
if (in_array($userid, $adminUsers))
// Admin code here

Answer 2

I think you're looking for in_array() to see if a given item is in an array.

Answer 3

You should use in_array() if all you need to know is that the user ID exists in your array.
But if you actually need a reference to the item, take a look at array_search() http://au1.php.net/manual/en/function.array-search.php

Answer 4

Instead of going through all the users in your admins table and then having another loop in order to find if a specific user exists , why not doing this check in the query itself?
For instance:
$stmt = $mysqli->prepare("SELECT name,email FROM admins WHERE id=?");
$stmt->bind_param("d", $user_id);
$stmt->execute();
$stmt->bind_result($name, $email);
if ($stmt->fetch()) {
//The user with user_id exists in the admins table , show him the admin panel.
//You can use $name and $email.
}
$stmt->close();