mysql_fetch_row() not a valid result resource - php

Question

I am confused, I don't know what's wrong. I'm about to transfer all data from my first table to the other. Here is my code:
$getdata = mysql_query("SELECT Quantity, Description, Total FROM ordercart");
while($row = mysql_fetch_row($getdata))
{
foreach($row as $cell){
$query1 = mysql_query("INSERT INTO ordermem (Quantity, Description, Total) VALUES
($cell)",$connect);
}
mysql_free_result($getdata);
}
I get the error: Warning: mysql_fetch_row(): 5 is not a valid MySQL result resource.

Answer 1

You only pass one value in the INSERT, which expects three values to be passed to the fields Quantity, Description, Total:
INSERT INTO ordermem (Quantity, Description, Total) VALUES
($cell);
Change it to:
INSERT INTO ordermem (Quantity, Description, Total) VALUES
($cell, $descriptionParam, $totalParam);
You may also try to use INSERT INTO SELECT directly instead of two distinct statements like so:
INSERT INTO ordermem (Quantity, Description, Total)
SELECT Quantity, Description, Total FROM ordercart;

Answer 2

You are trying to insert 1 value into 3 fields. You need to have 1 value for each field. For example:
$quantity="$_GET['qty']";
$description="$_GET['desc']";
$total="$_GET['total']";
$query = mysql_query("INSERT INTO ordermem (Quantity, Description, Total)
VALUES ('$quantity','$description','$total'))

Answer 3

Use debugging to find out the source of your problem.
mysql_query() returns a boolean value that tells you whether the operation succeeded or not. If it did not succeed, the mysql_error() function give you mySQL's error message.
Example:
$query1 = mysql_query("INSERT INTO ordermem (Quantity, Description, Total) VALUES ($cell)",$connect);
if (!$query1)
trigger_error("mySQL Error: mySQL returned ".mysql_error(), E_USER_ERROR);
This will give you a message something like "Number of values does not match the number of columns", which gives you a hint about what's wrong.

Answer 4

Try this :
$query = "INSERT INTO ordermem (Quantity, Description, Total) SELECT Quantity, Description, Total FROM ordercart";
mysql_query($query);