I have small question on mysql search query i need to make a search query php scripting with displaying all similar name , eg: if 100 similar names are found in the results the 100 results must show.
Here is my script of search query system.
$result = mysql_Query("SELECT user FROM `UserData` WHERE user LIKE '%$username%'") or die(mysql_error());
$fetch = mysql_num_rows($result);
if( $fetch > 0 )
{
$resultgg = mysql_Query("SELECT user FROM `theusers` WHERE user LIKE '%$username%' ORDER BY `user` ASC LIMIT 500") or die(mysql_error());
$row = mysql_fetch_row($resultgg);
$users = $row[0];
echo "$users";
}
}
else
{
echo "<br><b>Please Enter Valid Username!</b>";
}
Please Help me.
mysql_fetch_row()
returns only 1 column of the resultset (see PHP docs). You need to iterate through the rows.
Visit the PHP documentation for mysql_fetch_row
Related
I'm an SQL noob and learning how to use PDO. I'm doing a course which introduces basic user login functions. In an example of a login page, they check the username/password against a MySQL database. I edited their code slightly to be able to simultaneously check whether the user/pass combo exists and also grab the user's first name:
$sql = sprintf("SELECT firstname FROM users WHERE username='%s' AND password='%s'",
mysql_real_escape_string($_POST["username"]),
mysql_real_escape_string($_POST["password"]));
// execute query
$result = mysql_query($sql);
if (mysql_num_rows($result) == 1) {
$_SESSION["authenticated"] = true;
// get contents of "firstname" field from row 0 (our only row)
$firstname = mysql_result($result,0,"firstname");
if ($firstname != '')
$_SESSION["user"] = $firstname;
}
What I want to do is use SQLite instead and do the same thing. Searching around has only resulted in people saying you should use a SELECT COUNT(*) statement, but I don't want to have to use an extra query if it's possible. Since I'm SELECTing the firstname field, I should only get 1 row returned if the user exists and 0 if they don't. I want to be able to use that number to check if the login is correct.
So far I've got this:
$dsn = 'sqlite:../database/cs75.db';
$dbh = new PDO($dsn);
$sql = sprintf("SELECT firstname FROM users WHERE username='%s' AND password='%s'",
$_POST["username"],
$_POST["password"]);
// query the database and save the result in $result
$result = $dbh->query($sql);
// count number of rows
$rows = sqlite_num_rows($result);
if ($rows == 1) { ...
But this is returning Warning: sqlite_num_rows() expects parameter 1 to be resource, object given.
Is there a way I can do this efficiently like in MySQL, or do I have to use a second query?
EDIT:
I found this, not sure if it's the best way but it seems to work: How to get the number of rows grouped by column?
This code let me do it without the second query:
// query the database and save the result in $result
$result = $dbh->query($sql);
// count number of rows
$rows = $result->fetch(PDO::FETCH_NUM);
echo 'Found: ' . $rows[0];
$rows is an array so I can just count that to check if it's > 0.
Thanks to everyone who commented. I didn't know until now that there were 2 different approaches (procedural & object oriented) so that helped a lot.
Normally, you can use PDOStatement::rowCount(), however, SQLite v3 does not appear to provide rowcounts for queries.
You would need to seperately query the count(*), or create your own counting-query-function.
The documentation comments have an example of this
A bit late, but i tried this with SQLite3 successful:
$result = $db->query('SELECT * FROM table_xy');
$rows = $result->fetchAll();
echo count($rows);
I am having trouble with a function that checks if a set of user entered info (username and password) exists within either of the two possible tables where this information is stored.
The first table is the users table. It contains the first set of specific user information.
The last table is the listings table. It contains the second set of specific user information.
I have basically modified my original code to include the new listings table, and hence the trouble coming from within that task. The old code basically counted the number of results in the users table, if the result was greater than 0, then the function returned true, else false.
Now I have been stuck on the best way to go about adding another table to the query, and function. So I have been playing around with a union.
This was the original query:
SELECT COUNT(*) FROM users
WHERE id='$accNum' AND password='$password'
This returned a count of either 0 or 1 based on the info stored in the users table.
This is how I have reworked the query to include a count of the additional listings table:
SELECT count . *
FROM (
SELECT COUNT( * )
FROM users
WHERE id = '$accNum'
AND PASSWORD = '$password'
UNION (
SELECT COUNT( * )
FROM listings
WHERE id = '$accNum'
AND PASSWORD = '$password'
)
)count
This returned a result set of two rows, the first relating to the users table, and the second relating to the listings table. Then a column called COUNT (*) that contained the result count. This is the result set that I see within php myadmin.
Now this is the function:
function databaseContainsUser($accNum, $password)
{
include $_SERVER['DOCUMENT_ROOT'] . '/../../includes/db.inc.php';
$accNum = mysqli_real_escape_string($link, $accNum);
$password = mysqli_real_escape_string($link, $password);
$sql = "SELECT count . *
FROM (
SELECT COUNT( * )
FROM users
WHERE id = '$accNum'
AND PASSWORD = '$password'
UNION (
SELECT COUNT( * )
FROM listings
WHERE id = '$accNum'
AND PASSWORD = '$password'
)
)count
";
$result = mysqli_query($link, $sql);
if (!$result)
{
$error = 'Error searching for user.';
include 'error.html.php';
exit();
}
$row = mysqli_fetch_array($result);
if ($row[0] > 0)
{
return TRUE;
}
else
{
return FALSE;
}
}
The problem that I have, is trying to work out how exactly to check the results to ascertain if the given log in credentials are valid.
I tried this: if (($row[0] > 0) || ($row[0] > 0)) But a var dump on $row showed that only the first row (count of users table) was being added to the array.
So I decided that this was complicated, and a long way to the final result.
So I tried selecting only the id column of the result as in:
...
`COUNT( * )` to `id`
...
$data = mysql_query($sql);
$num_sql = mysql_num_rows($data);
if ($num_sql > 0)
...
But this did not work out for me either.
But in either instance, my hours of trial and error have provided me with no success... So I've decided to seek help from the knowledgeable members of Stack Overflow!
So my question is this, what would be a logical way of going about this task? I am looking for any suggestions, or positive input what so ever here.
As I am fairly new to dabbling with PHP and mysql, if you would like to provide some code to explain your suggestions or input on the matter, it would more than likely help me to better understand the answer.
If you are checking existence only try doing this that way:
select case when
exists (SELECT 1 FROM users WHERE id = '$accNum' AND PASSWORD = '$password') or
exists (SELECT 1 FROM listings WHERE id = '$accNum' AND PASSWORD = '$password')
then 1 else 0
end as itDoesExist
It returns always one row with one column with 1 when record exists in at last one table (else 0).
Do not use count to check whether some specific record/-s exist/-s in table, it's usually slower than simple exists.
Looks like you're going to get two rows in the result no matter what. Try this:
$sql = "SELECT id,password
FROM users
WHERE id = '$accNum' AND password = '$password'
UNION
SELECT id,password
FROM listings
WHERE id = '$accNum' AND password = '$password'
";
Now you can just check mysql_num_rows() to see if there's a match in either of the tables.
There are a couple of ways to go about this; if we are to stick with the approach you started with; you can simplify the query to:
$sql = "SELECT COUNT(1) FROM users
WHERE id = '$accNum'
AND PASSWORD = '$password'
UNION (SELECT COUNT(1) FROM listings
WHERE id = '$accNum'
AND PASSWORD = '$password')";
The reason you are only seeing one result, is because thats the way mysql_fetch_array() works, try doing this to get all results:
while ($row = mysql_fetch_array($result)) {
$data[] = $row;
}
var_dump($data);
Now you should have both values in there to validate with your conditional statements.
I'm working on a new search script for my website that contains multiple dictionaries. First let me show you the problem piece of code and then explain....
$sql = mysql_query("SELECT * FROM $tbl_name WHERE $field = '%$trimmed%' ORDER BY $field ".$sort." LIMIT ".$limits.", $max")or die(mysql_error());
$count = mysql_result(mysql_query("SELECT COUNT($field) FROM $tbl_name WHERE $field = '%$trimmed%'"),0);
if ($count < 1){
$sql = mysql_query("SELECT * FROM $tbl_name WHERE $field LIKE '%$trimmed%' ORDER BY $field ".$sort." LIMIT ".$limits.", $max")or die(mysql_error());
$count = mysql_result(mysql_query("SELECT COUNT($field) FROM $tbl_name WHERE $field LIKE '%$trimmed%'"),0);
}
Okay, in theory, the first query should select results that are exact and display them without displaying the "LIKE" results. However, it does not do that. It simply always shows the LIKE results.
And when I remove all of that, and leave the first query - no results are returned - even though they are in the database.
For example, with everything after "if ($count <1 ) {" included, I can search "SHE" or "I" and get results - however it includes words like "informal", "singular", etc. But when I remove this, I can search "SHE" and "I" and get no result at all, even though they're in the database.
Any help would be greatly appreciated.
Remove the '%' characters around "$trimmed" in the first query.
See if that fixes it.
MY SQL QUERY:
$q = mysql_query("SELECT * FROM `ads` WHERE keywords LIKE '%$key%' ORDER BY RAND()");
RESULTS: KEYWORD123
This query searches and results in one random row but i want to show 2 random rows.
How to do that?
any solution?
how??
im grabbing it using this
$row = mysql_fetch_array($q); if ($row
<= 0){ echo 'Not found'; }else{ echo
$row['tab']; }
That query (as-is) will return more than one row (assuming more than one row is LIKE %$key%). If you're only seeing one record, it's possible you're not cycling through the result set, but rather pulling the top response off the stack in your PHP code.
To limit the response to 2 records, you would append LIMIT 2 onto the end of the query. Otherwise, you'll get every row that matches the LIKE operator.
//Build Our Query
$sql = sprintf("SELECT tab
FROM ads
WHERE keyword LIKE '%s'
ORDER BY RAND()
LIMIT 2", ('%'.$key.'%'));
// Load results of query up into a variable
$results = mysql_query($sql);
// Cycle through each returned record
while ( $row = mysql_fetch_array($result) ) {
// do something with $row
echo $row['tab'];
}
The while-loop will run once per returned row. Each time it runs, the $row array inside will represent the current record being accessed. The above example will echo the values stored in your tab field within your db-table.
Remove your order by and add a LIMIT 2
That happens after the execution of the SQL.
Right now you must be doing something like
$res = mysql_query($q);
$r = mysql_fetch_array($res);
echo $r['keywords'];
what you need to do
$q = mysql_query("SELECT * FROM ads WHERE keywords LIKE '%$key%' ORDER BY RAND() LIMIT 2");
$res = mysql_query($q);
while($r = mysql_fetch_array($res)){
echo "<br>" . $r['keywords'];
}
Hope that helps
This query will return all rows containing $key; if it returns only one now this is simply by accident.
You want to add a LIMIT clause to your query, cf http://dev.mysql.com/doc/refman/5.0/en/select.html
Btw both LIKE '%... and ORDER BY RAND() are performance killers
I have this
$sql = "SELECT id FROM table";
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo $row['id'];
}
This echo's all id's found in the table.
How can I choose to echo only a selected id.
Say the second id found on the table?
EDIT
I think I have confused people and myself aswell.
Let me try to explain again.
Using the above query I can echo all results found in the table with echo $row['id'];
However I do not want echo all results, just selected ones.
You guys have suggested I use limit or a Where clause.
If I do this I will be limited to just one record. This is not what I want.
I want to echo a selection of records.
Something likes this
echo $row['id'][5], $row['id'][6], $row['id'][6]
But obviously this is incorrect syntax and will not work but hopefully you get what I am trying to do.
Thanks
If you only want the second row then you could change your query to use offset and limit e.g.
SELECT id FROM table LIMIT 1, 1
You could also use a for loop instead of the while loop and then put in a conditional.
UPDATE
Just noticed comments above - you also need to sort the PHP bug by changing mysql_fetch_array to mysql_fetch_assoc.
UPDATE 2
Ok based on your update above you are looking to get all of the rows into an array which you can then iterate over.
You can just use mysql_fetch_array and then use $array[0]. For example:
$sql = "SELECT id FROM table";
$result = mysql_query($sql) or die(mysql_error());
$ids = array();
while($row = mysql_fetch_array($result)) {
$ids[] = $row[0];
}
From what I can gather from your questions you should not be selecting all records in the table if you wish to just use the Nth value, use:
SELECT id FROM table LIMIT N, 1
That will select the Nth value that was returned. Note: The first result is 0 so if you wish to get the second value the Nth value should be 1.
mysql_data_seek() let's you jump to a specific data-set(e.g. the 2.nd)
Example:
$sql = "SELECT id FROM table";
$result = mysql_query($sql) or die(mysql_error());
//get the 2nd id(counting starts at 0)
if(mysql_data_seek($result,1))
{
$row=mysql_fetch_assoc($result);
echo $row['id'];
}
OR:
use mysqli_result::fetch_all
It returns an array instead of a resultset, so you can handle it like an array and select single items directly (requires PHP5.3)