PHP require fails with no error - php

Here is the code I have been struggling for several hours:
if ((require $_SESSION['ROOT_PATH'] . '/templates/core/menu_js.php') == 'OK') {
echo 'OK';
} else {
echo 'KO';
}
If I understand the PHP documentation on the "require" directive correctly, the "KO" should never be written because, if the require doesn't work, an error is raised.
In my case, the "KO" is always displayed even with error tunning :
error_reporting(E_ERROR | E_WARNING | E_PARSE | E_COMPILE_ERROR);
Note that the same require (or include) works perfectly in other pages of the site.
EDIT
The if structure has been added after watching the documentation.
At first, I had a single line :
require $_SESSION['ROOT_PATH'] . '/templates/core/menu_js.php';
As I checked that this line was not working, I added the if.
By the way. Required page (when it works) adds a script tag to calling page that I never see on this unique page. On any other page where this require is used, the script appears on output.
So my question should be "if the output of the required php file is not displayed, why is there no error raised ?"

According to the documentation
Successful includes, unless overridden by the included file, return 1... Also, it's possible to return values from included files. You can take the value of the include call as you would for a normal function.
So your file isn't returning 'OK'. It's returning either 1 (for success) or a custom value.
require is a language construct, not a standard function. By using require you're already indicating the code should fail if the file isn't found. Most likely you do not need to check the return value.

This only works the way you expect if menu_js.php contains return 'OK';. Otherwise the require works just fine, but the returned value is not "OK", which is why your "KO" condition is triggered. require doesn't return 'OK'. If the require does not work, the program is halted immediately, your false condition will never be hit the way you think it will.

There are some mistakes here:
According to the PHP documentation:
require is identical to include except upon failure it will also produce a fatal E_COMPILE_ERROR level error.
A fatal error will stop your script execution.
require returns what the included file returns:
// a.php
return 'test';
// b.php
$result = require 'a.php';
echo $result; // will display 'test'
So, don't test the return value of require! Use is_file(), then if true, require that file!

You cannot use require in if
Use this
if(file_exists($_SESSION['ROOT_PATH'] . '/templates/core/menu_js.php'))
{
echo 'OK';
} else {
echo 'KO';
}

While it's true that the require will not return anything, making the conditional always return 'KO' since the left hand value in the parenthesis will never equal 'OK', you can check to see if the file has failed by setting the display_errors ini value in this script temporarily On.
Since you have your error reporting set to catch this, your display_errors is probably off, therefore not showing you this. Set it for this script like this:
ini_set('display_errors', 'on');

Related

importing files in php using require() not working

i tried the following code to import two files
<?php echo "php";
require('../globalvasr.php') or die("error");
require('../newcosn.php') or die("error2");
$config = new GlobalConfigs();
?>
It does not shows error and it just simply displays a blank page.Also i am unable to use the variable defined in those two files.
Like $config->DBNAME.
I dont know whats wrong in this.
Please help me find it.
Thank you.
require, in contrast to include, automatically dies and does not have a return value.
This means the or die() is bad. Better:
<?php echo "php";
require('./globalvasr.php');
require('./newcosn.php');
$config = new GlobalConfigs();
?>
Require generates a fatal error when require fails, causing the script execution to stop immediatly.
As you seem to be running in a web env, your output (all echo or print statements) is buffered until the end of the script.
So here the require fails, causing a fatal error (that should be available in the error log) before the output buffer is emptied, preventing your first "echo" to be sent to the browser. that's why you get a blank page.
Try replacing the require with an include, you will get a warning instead of the fatal error.
if you have blank page, set error_reporting: E_ALL and Display_errors: On in php.ini or put on start of your script these lines
error_reporting(E_ALL);
ini_set('Display_errors','On');
then you will see errors

How to make smarty output debug info when template fails to compile?

I'm already set its debugging option to true,but when there's error in smarty template(i.e. there is no corresponding plugin for a specific smarty_modifier),nothing is output for information.
UPDATE
For anyone that wants to have a try,this is the most simple template I can think of :
{$var|nosuch_modifier}
1- First, you can check if error_reporting is on. this is usually done in php.ini but you can place these statements on top of your php source.
ini_set('display_errors', 1);
ini_set('error_reporting', E_ALL);
and make sure it is not disabled elsewhere.
2- smarty may report errors as throwing an exception. You can define a global exception handler to catch them, here is an example;
try {
// place your code here
} catch (Exception $e) {
echo 'Caught exception: ', $e->getMessage(), "\n";
}
Update upon comments:
The only reason I can think of is that you've set compile_check to false.
$tpl->compile_check = false;
In this case, Smarty will show the latest compiled source, whatever you do to the tpl file. So, did you check and set compile_check to true?
$tpl->compile_check = true;
Try
ini_set('display_errors', true);
error_reporting(E_ALL);
in the PHP code.
Smarty error reporting can be set manually.
$smarty->error_reporting = E_ALL ^ E_NOTICE;
Some comments from the Smarty.class.php
error muting is done because some people implemented custom
error_handlers using http://php.net/set_error_handler and for some
reason did not understand the following paragraph:
It is important to remember that the standard PHP error handler is
completely bypassed for the error types specified by error_types
unless the callback function returns FALSE. error_reporting() settings
will have no effect and your error handler will be called regardless -
however you are still able to read the current value of
error_reporting and act appropriately. Of particular note is that this
value will be 0 if the statement that caused the error was prepended
by the # error-control operator.
Smarty deliberately uses #filemtime() over file_exists() and
filemtime() in some places. Reasons include
- #filemtime() is almost twice as fast as using an additional file_exists()
- between file_exists() and filemtime() a possible race condition is opened, which does not exist using the simple #filemtime() approach.

Difference between "include" and "require" in php

Is there any difference between them? Is using them a matter of preference? Does using one over the other produce any advantages? Which is better for security?
require will throw a PHP Fatal Error if the file cannot be loaded. (Execution stops)
include produces a Warning if the file cannot be loaded. (Execution continues)
Here is a nice illustration of include and require difference:
From: Difference require vs. include php (by Robert; Nov 2012)
You find the differences explained in the detailed PHP manual on the page of require:
require is identical to include except upon failure it will also produce a fatal E_COMPILE_ERROR level error. In other words, it will halt the script whereas include only emits a warning (E_WARNING) which allows the script to continue.
See #efritz's answer for an example
Use include if you don't mind your script continuing without loading the file (in case it doesn't exist etc) and you can (although you shouldn't) live with a Warning error message being displayed.
Using require means your script will halt if it can't load the specified file, and throw a Fatal error.
The difference between include() and require() arises when the file being included cannot be found: include() will release a warning (E_WARNING) and the script will continue, whereas require() will release a fatal error (E_COMPILE_ERROR) and terminate the script. If the file being included is critical to the rest of the script running correctly then you need to use require().
For more details : Difference between Include and Require in PHP
As others pointed out, the only difference is that require throws a fatal error, and include - a catchable warning. As for which one to use, my advice is to stick to include. Why? because you can catch a warning and produce a meaningful feedback to end users. Consider
// Example 1.
// users see a standard php error message or a blank screen
// depending on your display_errors setting
require 'not_there';
// Example 2.
// users see a meaningful error message
try {
include 'not_there';
} catch(Exception $e) {
echo "something strange happened!";
}
NB: for example 2 to work you need to install an errors-to-exceptions handler, as described here http://www.php.net/manual/en/class.errorexception.php
function exception_error_handler($errno, $errstr, $errfile, $errline ) {
throw new ErrorException($errstr, 0, $errno, $errfile, $errline);
}
set_error_handler("exception_error_handler");
<?PHP
echo "Firstline";
include('classes/connection.php');
echo "I will run if include but not on Require";
?>
A very simple Practical example with code.
The first echo will be displayed. No matter you use include or require because its runs before include or required.
To check the result, In second line of a code intentionally provide the wrong path to the file or make error in file name. Thus the second echo to be displayed or not will be totally dependent on whether you use require or include.
If you use require the second echo will not execute but if you use include not matter what error comes you will see the result of second echo too.
In case of Include Program will not terminate and display warning on browser,On the other hand Require program will terminate and display fatal error in case of file not found.

include or required

What should I use in the following statement? Include or required.
if(a ==b){
require 'requiredfile.php';
} else {
require 'requiredfile_2.php'
}
If in a function, I know that one, either include or require, only includes the file when called, the other one will include the file regardless. Am I correct?
The difference between include and require is that include will only emit a warning when the file is not found, and require will terminate with a fatal error.
If you are loading vital program parts, you probably want to go with require.
Manual
require() is identical to include() except upon failure it will also produce a fatal E_ERROR level error. In other words, it will halt the script whereas include() only emits a warning (E_WARNING) which allows the script to continue.

Php - check if an include or block of code has an error

How would I go about checking if and include or a require has an error in it. For example, and include would try to be included, if that page has an error the page isn't included and a message is throw?
Cheers.
You can't catch a parse error in PHP in the same language environment (for obvious reasons).
One approach might be to run php -l your_included_file.php using exec and then check the exit code. The -l (lint) argument checks that your code can be parsed correctly.
You can try using file_exist function, it check whether the file exist or not.
$filename = "/path/to/file.php";
if(file_exists($filename)){
include $filename;
}else{
include "errorpage.php";
}
You can't trap parser errors.
However, if the code executes something that causes an exception to be thrown, you could catch it with a try/catch block.

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