i made a function to replace a words in a string by putting new words from an array.
this is my code
function myseo($t){
$a = array('me','lord');
$b = array('Mine','TheLord');
$theseotext = $t;
$theseotext = str_replace($a,$b, $theseotext);
return $theseotext;
}
echo myseo('This is me Mrlord');
the output is
This is Mine MrTheLord
and it is wrong it should be print
This is Mine Mrlord
because word (Mrlord) is not included in the array.
i hope i explained my issue in good way. any help guys
regards
According to the code it is correct, but you want it to isolate by word. You could simply do this:
function myseo($t){
$a = array(' me ',' lord ');
$b = array(' Mine ',' TheLord ');
return str_replace($a,$b, ' '.$t.' ');
}
echo myseo('This is me Mrlord');
keep in mind this is kind of a cheap hack since I surround the replace string with empty spaces to ensure both sides get considered. This wouldn't work for punctuated strings. The alternate would be to break apart the string and replace each word individually.
str_replace doesn't look at full words only - it looks at any matching sequence of characters.
Thus, lord matches the latter part of Mrlord.
use str_ireplace instead, it's case insensitive.
Related
I have the following title formation on my website:
It's no use going back to yesterday, because at that time I was... Lewis Carroll
Always is: The phrase… (author).
I want to delete everything after the ellipsis (…), leaving only the sentence as the title. I thought of creating a function in php that would take the parts of the titles, throw them in an array and then I would work each part, identifying the only pattern I have in the title, which is the ellipsis… and then delete everything. But when I do that, in the X space of my array, it returns the following:
was...
In position 8 of the array comes the word and the ellipsis and I don't know how to find a pattern to delete the author of the title, my pattern was the ellipsis. Any idea?
<?php
$a = get_the_title(155571);
$search = '... ';
if(preg_match("/{$search}/i", $a)) {
echo 'true';
}
?>
I tried with the code above and found the ellipsis, but I needed to bring it into an array to delete the part I need. I tried something like this:
<?php
define('WP_USE_THEMES', false);
require('./wp-blog-header.php');
global $wpdb;
$title_array = explode(' ', get_the_title(155571));
$search = '... ';
if (array_key_exists("/{$search}/i",$title_array)) {
echo "true";
}
?>
I started doing it this way, but it doesn't work, any ideas?
Thanks,
If you use regex you need to escape the string as preg_quote() would do, because a dot belongs to the pattern.
But in your simple case, I would not use a regex and just search for the three dots from the end of the string.
Note: When the elipsis come from the browser, there's no way to detect in PHP.
$title = 'The phrase... (author).';
echo getPlainTitle($title);
function getPlainTitle(string $title) {
$rpos = strrpos($title, '...');
return ($rpos === false) ? $title : substr($title, 0, $rpos);
}
will output
The phrase
First of all, since you're working with regular expressions, you need to remember that . has a special meaning there: it means "any character". So /... / just means "any three characters followed by a space", which isn't what you want. To match a literal . you need to escape it as \.
Secondly, rather than searching or splitting, you could achieve what you want by replacing part of the string. For instance, you could find everything after the ellipsis, and replace it with an empty string. To do that you want a pattern of "dot dot dot followed by anything", where "anything" is spelled .*, so \.\.\..*
$title = preg_replace('/\.\.\..*/', '', $title);
I am trying to use a License PHP System…
I will like to show the status of their license to the users.
The license Server gives me this:
name=Service_Name;nextduedate=2013-02-25;status=Active
I need to have separated the data like this:
$name = “Service_Name”;
$nextduedate = “2013-02-25”;
$status = “Active”;
I have 2 days tring to resolve this problem with preg_match_all but i cant :(
This is basically a query string if you replace ; with &. You can try parse_str() like this:
$string = 'name=Service_Name;nextduedate=2013-02-25;status=Active';
parse_str(str_replace(';', '&', $string));
echo $name; // Service_Name
echo $nextduedate; // 2013-02-25
echo $status; // Active
This can rather simply be solved without regex. The use of explode() will help you.
$str = "name=Service_Name;nextduedate=2013-02-25;status=Active";
$split = explode(";", $str);
$structure = array();
foreach ($split as $element) {
$element = explode("=", $element);
$$element[0] = $element[1];
}
var_dump($name);
Though I urge you to use an array instead. Far more readable than inventing variables that didn't exist and are not explicitly declared.
It sounds like you just want to break the text down into separate lines along the semicolons, add a dollar sign at the front and then add spaces and quotes. I'm not sure you can do that in one step with a regular expression (or at least I don't want to think about what that regular expression would look like), but you can do it over multiple steps.
Use preg_split() to split the string into an array along the
semicolons.
Loop over the array.
Use str_replace to replace each '=' with ' = "'.
Use string concatenation to add a $ to the front and a "; to the end of each string.
That should work, assuming your data doesn't include quotes, equal signs, semicolons, etc. within the data. If it does, you'll have to figure out the parsing rules for that.
Hopefully, this is an easy one. I have an array with lines that contain output from a CSV file. What I need to do is simply remove any commas that appear between double-quotes.
I'm stumbling through regular expressions and having trouble. Here's my sad-looking code:
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '(?<=\")/\,/(?=\")'; //this doesn't work
$revised_input = preg_replace ( $pattern , '' , $csv_input);
echo $revised_input;
//would like revised input to echo: "herp","derp,"hey get rid of these commas man",1234
?>
Thanks VERY much, everyone.
Original Answer
You can use str_getcsv() for this as it is purposely designed for process CSV strings:
$out = array();
$array = str_getcsv($csv_input);
foreach($array as $item) {
$out[] = str_replace(',', '', $item);
}
$out is now an array of elements without any commas in them, which you can then just implode as the quotes will no longer be required once the commas are removed:
$revised_input = implode(',', $out);
Update for comments
If the quotes are important to you then you can just add them back in like so:
$revised_input = '"' . implode('","', $out) . '"';
Another option is to use one of the str_putcsv() (not a standard PHP function) implementations floating about out there on the web such as this one.
This is a very naive approach that will work only if 'valid' commas are those that are between quotes with nothing else but maybe whitespace between.
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '/([^"])\,([^"])/'; //this doesn't work
$revised_input = preg_replace ( $pattern , "$1$2" , $csv_input);
echo $revised_input;
//ouput for this is: "herp","derp","hey get rid of these commas man",1234
It should def be tested more but it works in this case.
Cases where it might not work is where you don't have quotes in the string.
one,two,three,four -> onetwothreefour
EDIT : Corrected the issues with deleting spaces and neighboring letters.
Well, I haven't been lazy and written a small function to do exactly what you need:
function clean_csv_commas($csv){
$len = strlen($csv);
$inside_block = FALSE;
$out='';
for($i=0;$i<$len;$i++){
if($csv[$i]=='"'){
if($inside_block){
$inside_block=FALSE;
}else{
$inside_block=TRUE;
}
}
if($csv[$i]==',' && $inside_block){
// do nothing
}else{
$out.=$csv[$i];
}
}
return $out;
}
You might be coming at this from the wrong angle.
Instead of removing the commas from the text (presumably so you can then split the string on the commas to get the separate elements), how about writing something that works on the quotes?
Once you've found an opening quote, you can check the rest of the string; anything before the next quote is part of this element. You can add some checking here to look for escaped quotes, too, so things like:
"this is a \"quote\""
will still be read properly.
Not exactly an answer you've been looking for - But I've used it for cleaning commas in numbers in CSV.
$csv = preg_replace('%\"([^\"]*)(,)([^\"]*)\"%i','$1$3',$csv);
"3,120", 123, 345, 567 ==> 3120, 123, 345, 567
When I've a string:
$string = 'word1="abc.3" word2="xyz.3"';
How can I replace the point with a comma after xyz in xyz.3 and keep him after abc in abc.3?
You've provided an example but not a description of when the content should be modified and when it should be kept the same. The solution might be simply:
str_replace("xyz.", "xyz", $input);
But if you explicitly want a more explicit match, say requiring a digit after the ful stop, then:
preg_replace("/xyz\.([0-9])+/", 'xyz\${1}', $input);
(not tested)
something like (sorry i did this with javascript and didn't see the PHP tag).
var stringWithPoint = 'word1="abc.3" word2="xyz.3"';
var nopoint = stringWithPoint.replace('xyz.3', 'xyz3');
in php
$str = 'word1="abc.3" word2="xyz.3"';
echo str_replace('xyz.3', 'xyz3', $str);
You can use PHP's string functions to remove the point (.).
str_replace(".", "", $word2);
It depends what are the criteria for replace or not.
You could split string into parts (use explode or preg_split), then replace dot in some parts (eg. str_replace), next join them together (implode).
how about:
$string = 'word1="abc.3" word2="xyz.3"';
echo preg_replace('/\.([^.]+)$/', ',$1', $string);
output:
word1="abc.3" word2="xyz,3"
sorry but i cant solve my problem, you know , Im a noob.
I need to find something in string with preg_match.. then replace it with new word using preg_replace, that's ok, but I don't understand how to put replaced word back to that string.
This is what I got
$text ='zda i "zda"';
preg_match('/"(\w*)"/', $text);
$najit = '/zda/';
$nahradit = 'zda';
$o = '/zda/';
$a = 'if';
$ahoj = preg_replace($najit, $nahradit, $match[1]);
Please, can you help me once again?
You can use e.g. the following code utilizing negative lookarounds to accomplish what you want:
$newtext = preg_replace('/(?<!")zda|zda(?!")/', 'if', $text)
It will replace any occurence of zda which is not enclosed in quotes on both sides (i.e. in U"Vzda"W the zda will be replaced because it is not enclosed directly into quotes).