I have a Jquery Function that basically retrieves a list of users from the data base and inserts the information into divs. The problem is that im getting double reults, this is my first time retrieving from the database, Ive only ever sent to the database.. Any Help will be Greatly appreciated.
Thanks :)
Heres the Jquery Code:
$(function () {
$.ajax({
url: 'data.php',
data: "",
dataType: 'json',
success: function(rows) {
for (var i in rows) {
var row = rows[i];
var id = row[0];
var name = row[1];
var mobile = row[2];
var address = row[3];
var email = row[4];
$.each(rows, function() {
$('#contain').append('<div id="name">' + '<span>' + name + '</span>' + '</div>' + '<div id="id">' + id + '</div>' + '<div id="mobile">' + mobile + '</div>' + '<div id="address">' + address + '</div>' + '<div id="email">' + email + '</div>');
});
}
}
});
});
and the PHP:
$result = mysql_query("SELECT * FROM $tableName");
$data = array();
while ( $row = mysql_fetch_row($result) )
{
$data[] = $row;
}
echo json_encode( $data );
I think the problem is here:
$.each(rows, function (){
$('#contain').append('<div id="name">'+'<span>'+name+'</span>'+'</div>'+'<div id="id">'+id+'</div>'+'<div id="mobile">'+mobile+'</div>'+'<div id="address">'+address+'</div>'+'<div id="email">'+email+'</div>');
});
you should do just
$('#contain').append('<div id="name"><span>'+name+'</span></div><div id="id">'+id+'</div><div id="mobile">'+mobile+'</div><div id="address">'+address+'</div><div id="email">'+email+'</div>');
Related
custom.js file:
$(document).ready(function() {
$("#company_name").keyup(function() {
$.ajax({
type: "POST",
url: "http://localhost/capms_v2/ca_autocomplete/getcompanyName",
data: {
keyword: $("#company_name").val()
},
dataType: "json",
success: function(data) {
//alert(data);
if (data.length > 0) {
$('#DropdownCompany').empty();
$('#company_name').attr("data-toggle", "dropdown");
$('#DropdownCompany').dropdown('toggle');
} else if (data.length == 0) {
$('#company_name').attr("data-toggle", "");
}
$.each(data, function(key, value) {
if (data.length >= 0)
$('#DropdownCompany').append('<li role="displayCountries" ><a role="menuitem DropdownCompany" id=' + value['company_id'] + ' Address1=' + value['company_address1'] + ' Address2=' + value['company_address2'] + ' city=' + value['company_city'] + ' state=' + value['company_state'] + ' pincode=' + value['company_zip'] + ' class="dropdownlivalue">' +
value['company_name'] + '</a></li>');
});
}
});
});
$('ul.txtcountry').on('click', 'li a', function() {
$('#company_name').val($(this).text());
$('#company_id').val($(this).attr("id"));
// $('#company_address1').val($(this).text());
$('#tableCityID').html($(this).attr("id"));
$('#tableCityName').html($(this).text());
$('#Address1').html($(this).attr("Address1"));
$('#Address2').html($(this).attr("Address2"));
$('#city').html($(this).attr("city"));
$('#state').html($(this).attr("state"));
$('#pincode').html($(this).attr("pincode"));
});
});
I was getting id in span id="tableCityID" but if I store the value and pass the value to mysql it was not fetching the value
$com = '<span id="tableCityID">';
and if I echo the select query
echo $sql="select * from ca_job WHERE job_status!='Closed' AND job_customer_name = '".$com."'";
I get the result with not completed single codes
select * from ca_job WHERE job_status!='Closed' AND job_customer_name = '15
If anybody faces this problem, please help me. Thanks in advance.
just use the </span>
like this
$com = '<span id="tableCityID"></span>';
I want to print all sql table and show them in html table. I am new in php, JSON and AJAX. I send username successfully and get result in php. I think there is a problem in JSON part or AJAX. Can anyone help me?
index.php
<div class="col-lg-6">
<p id="usr" style="color:gray; font-size: 48px;"></p>
<script type="text/javascript">
var usr = document.getElementById("dom-target");
var username = usr.textContent;
username = username.trim().replace(/ /g, '%20');
document.getElementById("usr").innerHTML = username;
var sendtophp = "username="+username;
$.ajax({
type: "POST",
url: "getcoursetable.php",
data: sendtophp,
dataType:"json",
success: function(response) {
console.log(response);
var trhtml ='';
document.getElementById("demo").innerHTML = response;
$.each(response, function (i, item) {
trHTML += '<tr><td>' + item.cname + '</td><td>' + item.subject + '</td><td>' + item.course + '</td><td>'+ item.grade + '</td></tr>';
});
$('#results').append(trHTML);
}
});
</script>
<table id="results"></table>
</div>
getcoursetable.php
<?php
include_once "connection.php";
if(isset($_POST["username"])){
$nick = $_POST["username"];
$prep = "SELECT * FROM `enrolledtable` WHERE nickname='$nick'";
$results = mysqli_query($con, $prep);
$jsonData = array();
while ($row = $results->fetch_row()) {
$jsonData[] = $row;
}
echo json_encode($jsonData);
}
?>
Now, I can print data but not like a table, like that
<p id="demo">denemee,CS,300,B,denemee,CS,301,B ,denemee,CS,305,B ,denemee,CS,307,B,denemee,CS,408,A-,denemee,IE,208,B ,denemee,MATH,306,B</p>
your ajax function is looking for data of type json so you need to declare this at the top of getcoursetable.php
header('Content-Type: application/json');
The problem might sit around here :
console.log(response);
var trhtml ='';
document.getElementById("demo").innerHTML = response;
$.each(response, function (i, item) {
trHTML += '<tr><td>' + item.cname + '</td><td>' + item.subject + '</td><td>' + item.course + '</td><td>'+ item.grade + '</td></tr>';
});
$('#results').append(trHTML);
First, JavaScript is a Case Sensitive language : trhtml and trHTML are not the same variables.
Second, if your sentence "output of php" means you reported the output of console.log(), then response look like a string to me, you must make it parsed as Json.
Moreover, I don't know what the beginning of the string denemee is but it breaks the Json notation.
I solve my problem. This can take table in php and create html table.
index.php
<div class="col-lg-6">
<p id="usr" style="color:gray; font-size: 48px;"></p>
<script type="text/javascript">
var usr = document.getElementById("dom-target");
var username = usr.textContent;
username = username.trim().replace(/ /g, '%20');
document.getElementById("usr").innerHTML = username;
var sendtophp = "username="+username;
$.ajax({
type: "POST",
url: "getcoursetable.php",
data: sendtophp,
dataType:"json",
success: function(response) {
var trhtml ='';
$.each(response, function (i, item) {
trhtml += '<tr><td>' + item[0] + '</td><td>' + item[1] + '</td><td>'+ item[2] + '</td></tr>';
});
$('.append').append(trhtml);
}
});
</script>
<table id="results">
<tr>
<th>Name</th>
<th>Subject</th>
<th>Course</th>
<th>Grade</th>
</tr>
<tbody class="append">
</tbody>
</table>
</div>
getcoursetable.php
<?php
header('Content-Type: application/json');
include_once "connection.php";
if(isset($_POST["username"])){
$nick = $_POST["username"];
$prep = "SELECT subject,course,grade FROM `enrolledtable` WHERE nickname='$nick'";
$results = mysqli_query($con, $prep);
$jsonData = array();
while ($row = $results->fetch_row()) {
$jsonData[] = $row;
}
echo json_encode($jsonData);
}
?>
I wrote a php script which accept POST request from ajax and give the response back. All working fine. But the receiving string split letter by letter I can't understand what is the reason.
Here is my AJAX code,
$("#btn").click(function(){
console.log($("#search_bar").val());
var dataV;
var htmlText = '';
var containerbootsrap = '';
var filename = '';
var index_no;
$.ajax({
type: "POST",
crossDomain: true,
url: "http://localhost:8090/ontology/setText",
data: $("#search_bar").val(),
contentType: 'text/plain',
// dataType: "json",
success: function( data, textStatus, jQxhr ){
console.log('data');
console.log(data);
for( var item in data) {
console.log ("item: " + item);
console.log ("data: " + data[item]);
index_no = data[item];
// htmlText += '<div class="div-conatiner">';
// htmlText += '<p class="p-name"> Name: ' + data[item] + '</p>';
// htmlText += '<img class="imageload" src="' + data[item] + '" />';
// htmlText += '</div>';
// filename = data[item].replace(/^.*[\\\/]/, '')
$.ajax({
data: 'index_no=' + index_no,
url: 'retrivedata.php',
method: 'POST', // or GET
dataType: 'json',
success: function(msg) {
console.log(msg);
for(var item in msg){
console.log ("item: " + item);
console.log ("data: " + msg[item]);
}
$('#home').hide();
containerbootsrap += '<div class = "container" id="search_container">';
containerbootsrap += '<div class = "row homepage">';
containerbootsrap += '<div class = "col-md-5 col-md-offset-3">';
containerbootsrap += '<a href="#" class="thumbnail">';
containerbootsrap += '<img class="imageload" src="' + msg + '" />';
containerbootsrap += '<h3 id="video_name"> ' + filename + ' </h3>'
containerbootsrap += '</a>';
containerbootsrap += '</div>';
containerbootsrap += '</div>';
containerbootsrap += '</div>';
$('body').append(containerbootsrap);
}
});
// $.post('retrivedata.php', { num: 5 }, function(result) {
// alert(result);
// });
// $('#home').hide();
}
// $('body').append(containerbootsrap);
},
error: function( jqXhr, textStatus, errorThrown ){
console.log( jqXhr );
alert(jqXhr)
}
});
});
php code is below
<?php
$index_no = $_POST["index_no"];
// echo $index_no * 2;
include('dbConnection.php');
$query = mysql_query("SELECT * FROM video_data WHERE index_no = $index_no");
while ($row = mysql_fetch_assoc($query)) {
$imagePath = $row['thumbnail_url'];
$videoPath = $row['video_url'];
// echo $imagePath;
// echo $videoPath;
echo json_encode($imagePath);
}
?>
I need the output as : 'imagepath'
but it is giving the output as split letter by letter.
here is the real output
Output
but i need the output in one line. like /video_frames/bb/frame136.jpg
please help me to figure out where I am going wrong.
Well, in the php code where you're returning the value you need to specify an array not an string. The variable there $imagePath seems to be a string. You can do something like this.
echo json_encode(array('result' => $imagePath));
This will give you your result in the 'result' key. You can parse it and use it.
You need to parse the returned JSON string into an array. One way to do it is by adding data = $.parseJSON(data) in the ajax success callback (highlighted below). I was able to recreate the same thing you're seeing and adding this line fixed it. Hope this helps. parseJSON()
...
success: function( data, textStatus, jQxhr ){
console.log('data');
console.log(data);
data = $.parseJSON(data);
for( var item in data) {
console.log ("item: " + item);
console.log ("data: " + data[item]);
index_no = data[item];
...
Better way to check the type of value in variable you are getting first like
data = '{"name": "Bhushan"}' //string value
data = {name: "Bhushan"} //object value
//for testing you can use either, this will make it unbreakable for this context
if(typeof(data) == 'string')
{
data = JSON.parse(data)
}
//rest of code
This will give your module good stability otherwise you may get json parse unexpected token o.
I am creating a form where the user selects check boxes of "services" that they might be interested in, then the form gets emailed to me. The problem is weather a box is checked or not, all of the results are being filled in. How do I properly do this?
There are about 25, but here is just a few:
$services = array();
if($_POST['master_planning']) {$services[] = "Master planning";}
if($_POST['snow_plowing']) {$services[] = "Snow plowing";}
if($_POST['fine_gardening']) {$services[] = "Fine Gardening";}
if($_POST['deer_protection']) {$services[] = "Deer Protection";}
$interested = implode(", ", $services);
I know it is a very basic thing, but I can't seem to solve it on my own
HTML is like:
<li><label for="planting"><input type="checkbox" name="planting" id="planting" value="x" /> Planting</label></li>
Ok, I figured (I think) out why all the values are returning true, even if the checkboxes arent clicked, now how do I solve it....
I guess I should of mentioned that this is page 2 of the form (process.php), the actual form is index.php, and I am using an ajax script to pass values.
<script type="text/javascript">
$(document).ready(function() {
$('#submit').click(function () {
var name = $('input[name=name]');
var phone = $('input[name=phone]');
var email = $('input[name=email]');
var master_plan = $('input[name=master_plan]');
var front_foundation = $('input[name=front_foundation]');
var backyard_plan = $('input[name=backyard_plan]');
var specialty_garden = $('input[name=specialty_garden]');
var lawn_cutting = $('input[name=lawn_cutting]');
var lawn_plant_health_care = $('input[name=lawn_plant_health_care]');
var organic_property_care = $('input[name=organic_property_care]');
var seasonal_clean_ups = $('input[name=seasonal_clean_ups]');
var pruning = $('input[name=pruning]');
var fine_gardening = $('input[name=fine_gardening]');
var deer_protection = $('input[name=deer_protection]');
var snow_plowing = $('input[name=snow_plowing]');
var planting = $('input[name=planting]');
var walk = $('input[name=walk]');
var terrace = $('input[name=terrace]');
var wall = $('input[name=wall]');
var outdoor_kitchen = $('input[name=outdoor_kitchen]');
var fireplace = $('input[name=fireplace]');
var driveway = $('input[name=driveway]');
var fencing = $('input[name=fencing]');
var pergola = $('input[name=pergola]');
var swimming_pool = $('input[name=swimming_pool]');
var irrigation = $('input[name=irrigation]');
var lighting = $('input[name=lighting]');
var grading_drainage = $('input[name=grading_drainage]');
var newsletter = $('input[name=newsletter]');
var comments = $('textarea[name=comments]');
if (name.val()=='') {
name.addClass('hightlight');
return false;
} else name.removeClass('hightlight');
if (email.val()=='') {
email.addClass('hightlight');
return false;
} else email.removeClass('hightlight');
var data =
'name=' + name.val() +
'&phone=' + phone.val() +
'&email=' + email.val() +
'&master_plan=' + master_plan.val()+
'&front_foundation=' + front_foundation.val()+
'&backyard_plan=' + backyard_plan.val()+
'&specialty_garden=' + specialty_garden.val()+
'&lawn_cutting=' + lawn_cutting.val()+
'&lawn_plant_health_care=' + lawn_plant_health_care.val()+
'&organic_property_care=' + organic_property_care.val()+
'&seasional_clean_ups=' + seasional_clean_ups.val()+
'&pruning=' + pruning.val()+
'&fine_gardening=' + fine_gardening.val()+
'&deer_protection=' + deer_protection.val()+
'&snow_plowing=' + snow_plowing.val()+
'&planting=' + planting.val()+
'&walk=' + walk.val()+
'&terrace=' + terrace.val()+
'&wall=' + wall.val()+
'&outdoor_kitchen=' + outdoor_kitchen.val()+
'&fireplace=' + fireplace.val()+
'&driveway=' + driveway.val()+
'&fencing=' + fencing.val()+
'&pergola=' + pergola.val()+
'&swimming_pool=' + swimming_pool.val()+
'&irrigation=' + irrigation.val()+
'&lighting=' + lighting.val()+
'&grading_drainage=' + grading_drainage.val()+
'&newsletter=' + newsletter.val() +
'&comments=' + encodeURIComponent(comments.val());
$('.text').attr('disabled','true');
$('.loading').show();
$.ajax({
url: "process.php",
type: "GET",
data: data,
cache: false,
success: function (html) {
if (html==1) {
$('.form').fadeOut('slow');
$('.done').fadeIn('slow');
} else alert('Sorry, unexpected error. Please try again later.');
}
});
return false;
});
});
</script>
Could this be why every result is displaying?
The check you have is incorrect. Lets assume you have this HTML code for the checkbox inside your form:
<input type="checkbox" name="master_planning" value="yes" />
Then on your PHP you want do the check like this:
if(isset($_POST['master_planning']) && $_POST['master_planning'] == 'yes'){
array_push($services, "Master planning"];
}
The function array_push adds the given element or elements at the end of the array, so that would be an easy way to "dynamically" populates an array.
I would like to make a bus seating plan. I have seating plan chart using javascript function.I have two radio button named Bus_1 and Bus_2 queried from databases. When I clicked one of radio button, I would like to get available seats to show on the seating plan. Problem is I can't write how to carry radio value and to show database result on seating plan. Please help me.
<SCRIPT type="text/javascript">
$(function () {
var settings = { rowCssPrefix: 'row-', colCssPrefix: 'col-', seatWidth: 35, seatHeight: 35, seatCss: 'seat', selectedSeatCss: 'selectedSeat', selectingSeatCss: 'selectingSeat' };
var init = function (reservedSeat) {
var str = [], seatNo, className;
var shaSeat = [1,5,9,13,17,21,25,29,33,37,41,'#',2,6,10,14,18,22,26,30,34,38,42,'#','$','$','$','$','$','$','$','$','$','$',43,'#',3,7,11,15,19,23,27,31,35,39,44,'#',4,8,12,16,20,24,28,32,36,40,45];
var spr=0;
var spc=0;
for (i = 0; i<shaSeat.length; i++) {
if(shaSeat[i]=='#') {
spr++;
spc=0;
}
else if(shaSeat[i]=='$') {
spc++;
}
else {
seatNo = shaSeat[i];
className = settings.seatCss + ' ' + settings.rowCssPrefix + spr.toString() + ' ' + settings.colCssPrefix + spc.toString();
if ($.isArray(reservedSeat) && $.inArray(seatNo, reservedSeat) != -1) { className += ' ' + settings.selectedSeatCss; }
str.push('<li class="' + className + '"' +'style="top:' + (spr * settings.seatHeight).toString() + 'px;left:' + (spc * settings.seatWidth).toString() + 'px">' +'<a title="' + seatNo + '">' + seatNo + '</a>' +'</li>');
spc++;
}
}
$('#place').html(str.join(''));
}; //case I: Show from starting //init();
//Case II: If already booked
var bookedSeats = [2,3,4,5]; //**I don't know how to get query result in this array.This is problem for me **
init(bookedSeats);
$('.' + settings.seatCss).click(function () {
// ---- kmh-----
var label = $('#busprice');
var sprice = label.attr('pi');
//---- kmh ----
// var sprice= $("form.ss pri");
if ($(this).hasClass(settings.selectedSeatCss)){ alert('This seat is already reserved'); }
else {
$(this).toggleClass(settings.selectingSeatCss);
//--- sha ---
var str = [], item;
$.each($('#place li.' + settings.selectingSeatCss + ' a'), function (index, value) { item = $(this).attr('title'); str.push(item); });
var selSeat = document.getElementById("selectedseat");
selSeat.value = str.join(',');
//var amount = document.getElementById("price");
// amount.value = sprice*str.length;
document.getElementById('price').innerHTML = sprice*str.length;
return true;
}
});
$('#btnShow').click(function () {
var str = [];
$.each($('#place li.' + settings.selectedSeatCss + ' a, #place li.'+ settings.selectingSeatCss + ' a'), function (index, value) {
str.push($(this).attr('title'));
});
alert(str.join(','));
})
$('#btnShowNew').click(function () { // selected seat
var str = [], item;
$.each($('#place li.' + settings.selectingSeatCss + ' a'), function (index, value) { item = $(this).attr('title'); str.push(item); });
alert(str.join(','));
})
});
</SCRIPT>
You can use the onclick to tell AJAX to get your information and then what to do with it using jQuery.
<input type="radio" name="radio" onclick="ajaxFunction()" />
function ajaxFunction()
{
$.ajax({
type: "POST",
url: "you_script_page.php",
data: "post_data=posted",
success: function(data) {
//YOUR JQUERY HERE
}
});
}
Data is not needed if you are not passing any variables.
I use jQuery's .load() function to grab in an external php page, with the output from the database on it.
//In your jQuery on the main page (better example below):
$('#divtoloadinto').load('ajax.php?bus=1');
// in the ajax.php page
<?php
if($_GET['bus']==1){
// query database here
$sql = "SELECT * FROM bus_seats WHERE bus = 1";
$qry = mysql_query($sql);
while ($row = mysql_fetch_assoc($qry)) {
// output the results in a div with echo
echo $row['seat_name_field'].'<br />';
// NOTE: .load() takes this HTML and loads it into the other page's div.
}
}
Then, just create a jQuery call like this for each time each radio button is clicked.
$('#radio1').click(
if($('#radio1').is(':checked')){
$('#divtoloadinto').load('ajax.php?bus=1');
}
);
$('#radio2').click(
if($('#radio1').is(':checked')){
$('#divtoloadinto').load('ajax.php?bus=2');
}
);