I want a code for multiple ajax request. What happens actually is my first ajax request give me the response and in that responce function i m calling another function which having another website url. I want to send data to this new website using multiple ajax request.
Please help me out...
Thanks,
Prafulla
use global variables and manipulate your data in each request.
like:
var a;
$.ajax({
url:url_one;
success: function(data){ a =data; }
});
$.ajax({
url:url_two;
data: a //sends the data from the 1st request
success: function(data){
//do something with the data from the 2nd url
}
});
You can encapsulate your ajax call in function or event handlers as you need.
You can also manuipulate the data returned in variable a before sending it to the 2nd url.
Seems sloppy to me, but sould work.
Related
I've read all the articles but cant seem to get my ajax response into a PHP variable. Please can you advice. I want to assign rowid to a PHP variable.
$(document).on('click', '#updateid', function() {
var vallab = $('#idval').val();
var rowid;
$.ajax({
url:'a.php',
type: 'POST',
async: false,
data: {labid: vallab},
success: function(data){
// console.log(data);
rowid = data;
}
});
console.log(rowid);
return rowid;
});
my a.php code is below
<?php
# Fetch the variable if it's set.
$lab_id = (isset($_POST["labid"])) ? $_POST["labid"] : null;
echo $lab_id;
?>
I am getting the response back with the id, and want to use it on that page
I want to pass rowid into a PHP function so I need to get the value of rowid.
Please can you advice?
I cant seem to get my ajax response into a PHP variable
Well, the AJAX response came FROM a PHP file, right? So why don't you do whatever you need to do with the response right in that PHP file?
$.ajax({
url:'THIS IS YOUR PHP FILE',
type: 'POST',
data: {THIS IS THE DATA YOU SEND TO PHP},
success: function(data){
console.log(data); //THIS IS THE RESPONSE YOU GET BACK
}
});
You can't use it. Javascript is a scripting language which run in browser when the dom is loaded and elements are visible.
PHP is a serverside language and run on server before the page is loaded.
You need to understand the lifecycle of your application. Your php code executes once, it runs the full script from top to bottom when the page loads. At the point the script starts if can only access the post that came with the request (e.g if you clicked submit on a form then the 'action' of the form receives the post). Any number of things can happen in your script, but once it's finished the php is gone, and so is the post (in basic terms). So you no longer have any access to the php which created this page.
Ajax allows you to update a section of your page - it sends a request to your sever and runs some php code - you must understand that this is a new and separate request, so the new post submission only exists in the lifecycle of this new execution and is in now way linked to the page that has already finished loading. Now you could ask Ajax to call your original script, but that wouldn't affect your page at all because the page does not reload. What you would get is a strange looking response which you (probably) couldn't do anything useful with.
Ajax allows small specific changes to the page, so when you get your response (which I assume you get in a format you want since you don't ask about it and you have a console.log) you then need to do something with jQuery/javascript. Instead of returning rowid write a javascript function like :
function printRowId(rowid) {
$('#your html div id here').text('Row id is ' + rowid);
}
and then call it in your response:
$.ajax({
url:'a.php',
type: 'POST',
async: false,
data: {labid: vallab},
success: function(data){
// console.log(data);
rowid = data;
}
});
printRowId(rowid);
return rowid;
You can use Ajax to update your data, update your database and then reflect the changes on the current page, but you cannot use it to pass directly to the php that has already finished executing
I am trying to get a hold on sending data to MySql via ajax and have been watching online tutorials. In the examples, the controller method always seems to end with an echo statement which is returned to the js script. Under other circumstances, if I put an echo statement in a controller method it would be output to the view so why does this not happen after an ajax request?
ajax works with js, and the response by ajax request can only be handle through js.
Reason => after generating ajax response on server, it bounce back to client/browser, where server side language doesn't work, so you need to manage your code/logic through client side language JS in your ajax success block.
$.ajax({
url: 'content/get.php',
type: 'post', // performing a POST request
data : {
data1 : 'value' // will be accessible in $_POST['data1']
},
dataType: 'json',
success: function(data)
{
// success block
}
});
I have a link, delete, that removes an item from an array, and then removes a row from a table on my html page.
It runs the ajax request first to amend the array, then removes the row. If for some reason the ajax request was to fail then the html table row would still be deleted I think.
Is there a way to make sure subsequent code afer the ajax request only runs if it is successful? I tried moving it into the success function but then it didn't run at all..
This is how I have it set up at the moment...
$(document).ready(function () { //delete
$(document).on("click", "a[class='del']", function () {
var ID = $(this).attr("id"); //<----- get the ID of the column
$.ajax({
//contentType: "text",
url: 'proDel.php', //the url you are sending datas to which will again send the result
type: 'GET', //type of request, GET or POST
dataType: 'json', // jQuery will parse the response as JSON
data: 'val1=' + ID, //Data you are sending
success: function (data) {
// do nothing, array was amended in php file
}
})
//Code here that deletes the table row(runs whether the array was changed or not!!
})
})
The problem might be that you are not returning valid JSON.
You were correct in thinking that you should move the code that deletes the table row into the success callback. You say you tried that, but the success callback was not executed.
Since you specify dataType: 'json', jQuery will attempt to parse the response body into a JavaScript object (or array or null). If the response body cannot be parsed (because it is not valid JSON), jQuery will call the error callback, rather than the success callback.
An empty response body is not valid JSON. You must at least return "null". Or if you do not plan on returning any data, just change to dataType: 'text'.
Move the code that deletes row to success callback.
$.ajax({
//contentType: "text",
url : 'proDel.php', //the url you are sending datas to which will again send the result
type : 'GET', //type of request, GET or POST
dataType: 'json', // jQuery will parse the response as JSON
data : 'val1='+ID, //Data you are sending
success : function (data){
// Code here that deletes the table row
}
});
Try you ajax with success parameter as well as an error to see if there is a problem, hope this helps..
$(document).ready(function (){
$(document).on("click", "a[class='del']", function(){
var elem = $(this); //to make $(this) accessible in you success callback
var ID= elem.attr("id"); // get ID of the column
$.ajax({
url : 'proDel.php', //the url you are sending datas to
type : 'GET', //type of request, GET or POST
dataType: 'json', // jQuery will parse the response as JSON
data : 'val1='+ID, //Data you are sending
success : function (data){
// success, Code here that deletes the table row , do something with 'elem'
},
error: function(x,e) {
//log error if any
console.log("failed with: "+x.status+", e="+e+", response="+x.responseText);
}
});
});
});
Since jQuery 1.5 you may use chainable methods of object returning by jQuery.ajax(). In your case (ensure executing code on ajax request completion) you have to use deferred.always() method. Somehow like this:
$.ajax({
...
})
.always({
//Code here that deletes the table row
})
In earlier jQuery versions you have to use complete option (handler) in jQuery.ajax() for your purpose.
First thing is that when looking at the ajax request success does not mean that the request returned a correct/true value. That just means that there was a response from the other end.
That tripped me up during my first couple times working with and debugging ajax calls.
I don't know if that's part of what is not working for you here, but something to consider.
Secondly, and to answer your real question, you'll have to put a function call in the success branch, else it might never get called, or be called at a non-deterministic time (the whole nature of an asynchronous call).
var a = function(){
$.ajax({
success : function (){
// code here fires if there is a response to your ajax request
// you should put in an function callback here to check the response for
// your success conditions.
// if your conditions are met, make the changes that you need to
b();
}
failure: function() {
// code here fires if the ajax request receives no response
}
})
// any code here will fire immediately after the ajax call is fired.
// it will not wait for the ajax response.
}
var b = function(){
// stuff you want to do according to the ajax response parameters
}
I'm building an AJAX form and I'm trying to send 3 fields by JSON.
Client-side, the form is serialised and entered into JSON format:
$('#form-signin').live('submit', function(event) {
var target = $('#ajax');
var url = '/ajax/user/authenticateLevel2';
$.ajax({
type: "POST",
url: url,
data: $.base64.encode($('#form-signin').serialize()),
dataType: 'json',
success: function(data, status) {
$.getJSON(url, function(data) {
$('#ajax').html($.base64.decode(data.html));
$('#ajax').modal();
});
}
});
event.preventDefault();
});
Server side, my router splits the URL request up, sees that the first part contains 'ajax' then proceeds to specially pass the routing request to an AJAX handler.
my problem is that even inside the router, checking $_REQUEST, which is what is used to get the information about the post, the post data is not there. The same goes with $_POST.
Even the first page where the request hits (index.php), $_REQUEST does not have the data.
What am I doing wrong?
Server Side,
The request is sent to an index.php which includes the Autoloader and init script.
The init script initialises the database connection, sets the error, exception and session handling, then passes the request onto the router.
The router, in its construction method: sets the URL as an array (exploded $_SERVER['REQUEST_URI']), and then sets the relevant controller, method and additional parameters.
In this case, as we are doing an ajax request, special processing happens before we dispatch the request.
The method parameters are set to:
$requestParams = $_REQUEST;
unset($requestParams['url']);
This request parameter(s) along with additional information (url, controller, method and database object) are passed for dispatch.
In all cases, we are primarily dispatching using this method:
$dispatchedController = new $this->controller($this->database);
$method = $this->method;
return $dispatchedController->$method($this->params);
If I remember right from using a plugin a long time ago, the method $.base64.encode() returns a single string so what you are probably sending to the server is something like a single parameter with no value.
I believe you should be doing something like
data: "foo=" + $.base64.encode($('#form-signin').serialize()),
You are not sending json to the server just a base64 encoded string. Also you are expecting key/pair values. To send key/pair values just pass the serialized form data to the $.ajax function.
$('#form-signin').live('submit', function(event) {
var target = $('#ajax');
var url = '/ajax/user/authenticateLevel2';
$.ajax({
type: "POST",
url: url,
data: $('#form-signin').serialize(),
dataType: 'json',
success: function(data, status) {
$.getJSON(url, function(data) {
$('#ajax').html($.base64.decode(data.html));
$('#ajax').modal();
});
}
});
event.preventDefault();
});
The code should work (assuming your HTML is not the problem here, e.g., '#form-signin' is the right selector for the right form).
You mentioned you are not able to get the data on the server side. However, are you absolutely sure you are even sending the data you need from the client? For example, have you analyzed the request using a tool such as Firebug?
I'm looking to display data from a table in a mysql database using PHP, however, I want the data to automatically update itself and retrieve current values every 5 seconds.. WITHOUT having to refresh the page. Is this possible? Maybe with JQuery/ AJAX? If so, please explain how it can be done / point me to a resource where I can find such information
Thanks
If you use window.setInterval() and jQuery's .load() you should be able to do what you want. The PHP script should return the HTML that needs to replace the previous one.
Javascript:
function refreshData()
{
// Load the content of "path/to/script.php" into an element with ID "#container".
$('#container').load('path/to/script.php');
}
// Execute every 5 seconds
window.setInterval(refreshData, 5000);
A really basic example:
function poll(){
$.ajax({
type: "GET",
url: "your/php/script/",
success: function(data){
// do something with data
}
});
};
setInterval(poll, 5000);
jQuery is a good option. Here are the docs for ajax.
You will want to make this call with setInterval
Something like this might get your started.
setIntervla(updateFromDb,5000);
function updateFromDb(){
$.ajax({
url: "getUpdates.php",
success: function(){
$(this).addClass("done");
}
});
};
What you are describing is exactly the type of the AJAX is used for, AJAX allows for asynchronous requests to be made to your server.
For learning I would suggest using a framework like Jquery and look into the AJAX api.
Basicly you will need a PHP script that query the database and responds the results the way you want them. A suggestion would be to JSON encode them.
In JavaScript on the client you will need to you things like:
var poll = setInterval(function(){
$.ajax({
type:"GET",
url: "yourpage.php",
success: function(data){
//HANDLE DATA
// use JSON.parse(data); if your JSON encoding your data
}
});
},5000)
Just go to the documentation of jQuery:
http://api.jquery.com/category/ajax/
Use the command "jQuery.get()" or better "jQuery.getJson()" to make a http request to the server. Use JSON to get a better communication between server and client. Return from server side a json string and convert this on the client to an javascript object. (the function jQuery.getJson already do this for you) so you can easily access the key and values in the data array.
Just an example:
SERVER Part with PHP:
<?
$data = array('key'=>'value');
return json_encode($data, true);
CLIENT Part:
$.getJSON('myurl.php', function(data) {
// THIS ONE IS CALLED with your PHP data
alert(data.key);
});
$(function(){
window.setInterval(function(){
$.post("filename.php",{'field1':field1,'field2':field2,'field3':field3},function(data){
//callbackfunction(data)
})
},30000);//millisecs
});
And have your php file do all your sql