When I execute this query it returns false, which means the query is wrong. Can you figure out why?
$string1 = 'wee';
$string2 = 'wee';
$string3 = 'wee';
$string4 = 'wee';
if (isset($_POST['submit'])) {
$query = "INSERT INTO data (book, title, content, author)
VALUES ($string1, $string2, $string3, $string4)";
mysql_query($query, $con);
}
However, when I put something that is like the following, it returns true and inserts correctly:
$query = "INSERT into data (book, title, content, author)
VALUES ('wee', 'wee', 'wee', 'wee')";
And another question: when I submit, it seems that the query is returning twice when executed which means two records with one query. Does anyone understand that?
If you need more information, just ask.
Thanks in advance.
Although this question seems answered, you should not be using user input directly in queries as this opens holes for vulnerabilities like SQL Injection (and that's bad mmmay)
If you look at the mysql page on php.net (mysql_query) the page says it is recommended you use an abstraction layer like PDO (pdo-mysql)
Using PDO will allow you to bind parameters to your sql queries to bypass the security implications of using user input in your queries.
If you don't bind parameters to your queries, you're gonna have a bad time.
Your field data type is string or varchar so you need to put '' or "" around them.
Change your query as below
$query = "INSERT into data (book, title, content, author)VALUES ('".$string1."', '".$string2."',
'".$string3."', '".$string4."')";
To resolve submit issue, please post your html code
Related
I apologise if I’m asking this question wrong I’m new to stackoverflow and to php.
I'm trying to update my database with new values being a title and contents. Each row has a ID. I want to update the info at only that ID row. This is the statement that i'm using. Which isnt working could anyone offer me some advice please ?`
$updateBlog = $c->query("UPDATE blog SET ( title, content) VALUES ('$updateTitle', $postContent ) WHERE id = $updateID");
You query syntax is not right for an UPDATE and you'rre missing the quotes around your second variable:
UPDATE blog
SET title = '$updateTitle',
content = '$postContent'
WHERE id = $updateID
This will make your statement look like this:
$updateBlog = $c->query("UPDATE blog SET title = '$updateTitle', content = '$postContent' WHERE id = $updateID);
Leaving your query like this opens you to risk for SQL Injection Attacks. You really should learn about prepared statements for PDO and MySQLi.
$updateBlog = $c->query("UPDATE blog SET ( title, content) VALUES ('{$updateTitle}', {$postContent} ) WHERE id = {$updateID}");
You should REALLY look into some input validation and cleaning for your values though. If this is coming straight from a user input it's highly susceptible to SQL Injection.
I'm getting the error: Column count doesn't match value count at row 1
I think, normally this error occurs if the count of the columns and the values aren't equal, but in my code they are...(3).
This is my php code:
$tempsongtitel = $_POST['songtitle'];
$tempinterpret = $_POST['interpret'];
$templink = $_POST['link'];
$query = mysql_query("insert into tMusic (Songtitel, Interpret, Link) values ('$tempsongtitel, $tempinterpret, $templink')") or die(mysql_error());
You missed some quotes. Should be:
$query = mysql_query("insert into tMusic (Songtitel, Interpret, Link) values ('$tempsongtitel', '$tempinterpret', '$templink')") or die(mysql_error());
Otherwise, you were trying to insert all three POST values into the first field.
Moreover, the mysql_ extension has been deprecated and is on the way out and is highly discouraged, especially if you are creating new software.
AND I'll presume you are first sanitizing your data? You're not really taking user input and placing it directly into the database, are you? Even if you don't do any data validation, you should escape your data in the query... easiest and most foolproof way to do that is by using parameterized queries.
The root cause is that your values are all in one set of quotes instead of quoted individually. I think this is a pretty common error, and in my experience it is an easy mistake to make, but not immediately obvious when scanning over your code. You can fix it like this (quick fix, still using deprecated mysql, but with post values escaped):
$tempsongtitel = mysql_escape_string($_POST['songtitle']);
$tempinterpret = mysql_escape_string($_POST['interpret']);
$templink = mysql_escape_string($_POST['link']);
$query = mysql_query("insert into tMusic (Songtitel, Interpret, Link)
values ('$tempsongtitel', '$tempinterpret', '$templink')") or die(mysql_error());
If you can, it would be much better to update your code to use PDO. You could use a prepared statement like this:
$stmt = $pdo->prepare("INSERT INTO tMusic (Songtitel, Interpret, Link) VALUES (?, ?, ?)");
$stmt->bindValue(1, $tempsongtitel);
$stmt->bindValue(2, $tempinterpret);
$stmt->bindValue(3, $templink);
$stmt->execute();
Among the many benefits of using this database extension rather than the old mysql functions it should not be possible to make an error like this in your code. In the prepared statement, there are no quotes around the parameter markers, so if you have VALUES ('?, ?, ?'), or even VALUES ('?', '?', '?') You would get bind errors when trying to bind the values, and the problem would become apparent pretty quickly.
I've found that, even though it's not 100% necessary and it's more time consuming, properly quoting and backticking EVERYTHING helps prevent this from happening.
$myQuery = "INSERT INTO `tMusic` (
`Songtitel`,
`Interpret`,
`Link`
) VALUES (
'$tempsongtitel',
'$tempinterpret',
'$templink'
);";
$runQuery = mysqi_query($DBi, $myQuery) or die(mysqli_error($DBi));
The formatting you use is up to you but this helps me make sure I have a one to one relationship and that I've quoted everything.
Of course that's using mysqli_* in place of the deprecated mysql_* functions AND that's assuming you've set $tempsongtitel, $tempinterpret and $templink properly.
Hi when ever I want to insert a comment into my database, I sanitize the data by using Mysql Escape String function this however inserts the following verbatim in field. I print the comment and it works fine and show me the text however when ever I sanitize it, it literally inserts the following into my db
mysql_real_escape_string(Comment)
This is my insert statement, The Id inserts correctly however the comment doesn't it just inserts the "mysql_real_escape_string(Comment)" into the field. what can be wrong?
foreach($html->find("div[class=comment]") as $content){
$comment = $content->plaintext;
$username = mysql_real_escape_string($comment);
$querytwo = "insert into Tchild(Tid,Tcomment)values('$id','$username')";
$resulttwo = $db -> Execute($querytwo);
}
If I'm reading the documentation correctly, you should make the call like this:
$db->Execute("insert into Tchild(Tid,Tcomment)values(?, ?)", array($id, $username));
That will account for proper escaping. Having unescaped values in your query string is dangerous and should be avoided whenever possible. As your database layer has support for SQL placeholders like ? you should make full use of those any time you're placing data in your query.
A call to mysql_real_escape_string will not work unless you're using mysql_query. It needs a connection to a MySQL database to function properly.
Since you're using ADODB, what you want is probably $db->qstr(). For example:
$username = $db->qstr($comment, get_magic_quotes_gpc());
See this page for more information: http://phplens.com/lens/adodb/docs-adodb.htm
I'm having problems with an INSERT statement, and the error only says:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
It's not helpful at all.
The version I have tried so far and failed is:
mysql_query("INSET INTO `cos` VALUES ('".$_GET['prod']."','".$_GET['page']."')");
[needless to say that the two variables when printed show the right values]
I've also tried versions with nothing around the table name, with ` or ', a million combinations really and nothing works. Not even with constants or into different tables. It just won't insert anything ever. I've checked the privileges (I'm logging into it with root), and it's all on.
I've tried similar stuff on two different machines with the same server (XAMPP 1.7.7) and it works. I'm completely baffled! What can it be?
Thank you for your time!
First and foremost, just type INSERT correctly.
Using _GET like that really opens you up to SQL INJECTIONS...
Do take a look into MySQL prepared statements.
It is also considered good practice to name the columns that you're inserting data into. That allows you to, latter on, insert extra-columns and keep application logic.
INSERT INTO cos(rowName1, rowName2) VALUES(?, ?)
Where ? would be prepared statements.
Correct:
mysql_query("INSERT INTO `cos` VALUES ('".$_GET['prod']."','".$_GET['page']."')");
Have you tried passing the $link to mysql_query ?
Like:
mysql_query("INSERT INTO `cos` VALUES ('".$_GET['prod']."','".$_GET['page']."')", $link);
EDIT:
And of course you must take some security measures before inserting anything into the database, maybe mysql_real_escape_string() or even prepared statements.
You are doing it wrong. Why aren't you escaping the values?
Php.net documentation is providing some good and safe working examples:
$query = sprintf("SELECT firstname, lastname, address, age FROM friends
WHERE firstname='%s' AND lastname='%s'",
mysql_real_escape_string($firstname),
mysql_real_escape_string($lastname));
// Perform Query
$result = mysql_query($query);
So adapted to your code:
$query = sprintf("INSERT INTO `cos` VALUES (%s, %s);",
mysql_real_escape_string($_GET['prod']),
mysql_real_escape_string($_GET['page']));
$result = mysql_query($query);
Please, always escape your values. And use INSERT, not INSET :)
first this is you are using INSET make it correct with INSERT like
$pro = mysql_real_escape_string($_GET['prod']);
$page = mysql_real_escape_string($_GET['page']);
mysql_query("INSERT INTO `cos` (column1, column2)
VALUES ('$pro', '$page')" );
you forget to set the column names...
Try this:
$prod = $_GET['prod'];
$page = $_GET['page'];
mysql_insert("INSERT INTO 'cos' VALUES('$prod','$page)");
This should very well do it :)
Before I put data into my database I pass it through mysql_real_escape_string.
If I want to copy that same data into another table, do I need to pass it through mysql_real_escape_string again before I copy it?
I wrote a small script to test the issue and it looks like the answer is yes:
$db = new AQLDatabase();
$db->connect();
$title = "imran's color";
$title = mysql_real_escape_string($title);
$sql = "insert into tags (title, color) values ('".$title."','#32324')";
$db->executeSQL($sql);
$sql = "select * from tags where color = '#32324' ";
$result = $db->executeSQL($sql);
while($row= mysql_fetch_array($result))
{
$new_title = $row['title'];
}
$new_title = mysql_real_escape_string($new_title);
$sql = "insert into tags (title, color) values ('".$new_title."','DDDDD')";
$db->executeSQL($sql);
NOTE: If I remove the second mysql_real_escape_string call, then the second insert won't take place
Are doing something like this?
save mysql_real_escape_string($bla) to database
fetch $bla from database
save $bla again (in another table..)
Fetching $bla from the database will "unescape" it so it could be a harmful string again. Always escape it again when saving it.
Before I put data into my database I always make it go the Mysql_real_Escape_String thing.
You are doing right. Just keep it as is. Not database though but query it is.
The only note: only strings should be escaped using this function. It shouldn't be used with any other query parts.
do I need to make it go through the Mysql_real_Escape_String again before I copy it?
Didn't you answer your question already? Before I put [string-type] data into my [query] I always make it go the Mysql_real_Escape_String thing. Is your data going to SQL query? So, here is an answer you have already.
Well, if you are sure this data is already properly escaped, there is no need to.
mysql_real_escape_string is for 1) escaping 2) security purposes. Since it's your own data base and as long as you pass data to another database outside a potential hacker reach - you are already safe
Its already scaped, just copy it as is, if you want to undo the mysql_real_escape_string you can use stripslashes($sting) to remove it
PD: This is false and now i understand why.