Getting multiple values of checkbox from a loop - php

Question

while($row = mysql_fetch_array($result)){
echo '<tr>
<td>'.$row[0].'</td>
<td>'.$row[1].'</td>
<td>'.$row[2].'</td>';
$price=$row['price'];
echo "<td><input type='checkbox' name='er' value='$price'></td>";
echo "</tr>";
PHP file
<?php
$ercharge=$_POST['er'];
echo $ercharge;
?>
I have a list of charges that was from a mysql table and it has a checkbox for each item so it would compute the sum. The above code works and it outputs the price of the checked item. The problem is, it's only one item. When multiple items are checked, only one is outputted.

Answer 1

Try this:-
echo "<td><input type='checkbox' name='er[]' value='$price'></td>";

Answer 2

Try this it may help you
echo "<td><input type='checkbox' name='er[]' value='$price'></td>";
echo "</tr>";
$recharge=$_POST['er'];
foreach($recharge as $val)
{
echo $val;
}
Or
you can just do this without using foreach
$arra_val=array_sum($recharge);
you just need to put the value in to some variable and echo it.

Answer 3

If you want to pass a number of elements in an array append the name with square brackets, so it would be:
echo "<td><input type='checkbox' name='er[]' value='$price'></td>";
And the result of $_POST['er'] would be an array of all of the checkbox values.

Answer 4

The input box name should reflect that it's an array by adding the [] suffix:
echo '<td><input type="checkbox" name="er[]" value=" . htmlspecialchars($row['price']) . "></td>';
Then, to process the sum after making sure the input validates as proper values:
if ($ers = filter_input(INPUT_POST, 'er', FILTER_VALIDATE_FLOAT, FILTER_FORCE_ARRAY)) {
$ercharge = array_sum($ers);
}