mysql_query(INSERT ...) function not working in my code - php

Question

I've create database, which basically accept name and Id and answer string of
length 47,and my php code will grade the incoming results against the answer key I provided and number containing the count of correct answers will stored in database. this is information of my database.
database name is marking
and table called 'answer', which has 5 fields as follow
1) answer_id :int , not null, auto increament.
2) name: text
3)id : text
4)answers : text
5)correct : int
my question and problem is the function is working
// setup query
$q = mysql_query("INSERT INTO `answer` VALUES
(NULL,'$name', '$id','$answers','$correct')");
// run query
$result = mysql_query($q);
or in another way , nothing storing in my database ???
Thanks in advance.
this is the whole program.
<?php
error_reporting(E_ALL ^ E_STRICT);
// to turn error reporting off
error_reporting(0);
$name =$_POST['name'];
$id = $_POST['id'];
$answers = $_POST['answers'];
// check the length of string
if(strlen($answers) !=10)
{
print'your answer string must be 10';
return;
}
mysql_connect("localhost","root","");
mysql_select_db("marking");
$name = addslashes($name);
$id = addslashes($id);
$answers = addslashes($answers);
$answer_key = "abcfdbbjca";
$correct = 0;
for($i=0;$i<strlen($answer_key);$i++)
{
if($answer_key[$i] == $answers[$i])
$correct++;
}
// Setup query
$q = mysql_query("INSERT INTO `answer` VALUES ('$name', '$id','$answers','$correct')");
$result = mysql_query($q);
print 'Thnak you. You got' + $correct + 'of 10 answers correct';
?>

Answer 1

Try this:
// setup query
$q = "INSERT INTO `answer` (`name`, `id`, `answers`, `correct`) VALUES
('$name', '$id','$answers','$correct')";
//Run Query
$result = mysql_query($q) or die(mysql_error());
Also, you should avoid using mysql_ functions as they are in the process of being deprecated. Instead, I recommend you familiarize yourself with PDO.
Also, note, the or die(mysql_error()) portion should not be used in production code, only for debugging purposes.

Answer 2

Two things.
You are actually executing the query twice. mysql_query executes the query and returns the result resource. http://php.net/manual/en/function.mysql-query.php
And also, you are quoting the int column correct in your query, as far as I know, you can't do that (I could be wrong there).
$result = mysql_query("INSERT INTO `answer` VALUES (NULL,'$name', '$id','$answers',$correct)");
EDIT: Turns out I'm actually wrong, you may disregard my answer.