Cant make text appear with php/ajax code :( - php

Question

First check this site: check this first plz
hi , Im from mexico and Im auto learning html, css, js and php, for personal purposes.
IM trying to add that code to my testing page, the example is Example 3 — Random Fact Generator (form). When you click the random generaton button, it makes random text appear the problem is..WHERE IS IT COMMING FROM? and xml? php server?...I dont know..I checked in ALL the code and nothing :(, I can add random text with other methods like JS with a case and a random.math but I prefer like that page, any sugestions? thx a lotssss

Answer 1

It comes from : http://juicystudio.com/experiments/ajax/form/fact.php
Go see http://juicystudio.com/experiments/ajax/form/script.js
So it comes from a PHP file. The PHP could be reading a XML file, a CSV file, a database, etc.
Let me know if you still have questions.
Edit:
If you don't want to overwrite the last fact you have to change this from script.js:
if (objCurrent)
objCurrent.parentNode.replaceChild(objReplacement, objCurrent);
else
{
var objContent = document.getElementById('content');
objContent.appendChild(objReplacement);
}
To
var objContent = document.getElementById('content');
objContent.appendChild(objReplacement);
Edit 2:
CSV file (test.csv)
1,test1
2,test2
3,test3
4,test4
5,test5
Here is the PHP adapt from the site you have supplied
<?php
$handle = fopen("test.csv", "r");
$array= array();
while (($data = fgetcsv($handle, 5000, ",")) !== FALSE) {
array_push($array,$data);
}
if(count($array) > 0){
$id = rand(0, count($array) -1);
echo $array[$id][1];
}
?>

Answer 2

It gets the text from http://juicystudio.com/experiments/ajax/form/fact.php
In this section, it opens a connection to that page:
if (objXMLRequest)
{
objXMLRequest.onreadystatechange = processResult;
objXMLRequest.open('GET', 'fact.php', true);
objXMLRequest.send(null);
}
When the connection's state change event fires, it calls the method processResult. That method checks that the readystate is 4 (completed) and the status is 200 (OK) and updates the text on the page.
You don't need a database or to read files to make that example page. The easiest way would be to create an array of facts and output one at random, like this:
<?php
$facts = array("fact 1", "fact 2", "fact 3", "fact 4", "fact 5", "fact 6");
$random_number = rand(0, count($facts)-1);
echo $facts[$random_number];
?>