How to assign the value to JSON by giving INDEX also - php

Question

How to assign the value to the JSON by providing the index for it..
see the following code,
var jsonVariable = [];
jsonVariable[10] = {1:10};
alert(jsonVariable.toSource());
For the above code the output is,
[,,,,,,,,,{1:10}]
The output i expect and i need is [10 : {1:10}]
How to code to bring the output as i expect... please help me briefly..

Answer 1

You used index-operators ([]), which instanciate a new array and set the element at index 10 to {1: 10}. You actually wanted to use curly braces operators ({}) which instanciate a new object and ad a property 10: {1:10} like that:
var jsonVariable = {};
jsonVariable[10] = {1:10};
alert(jsonVariable.toSource());
Setting members to an array, you can't simply skip some indices (begin at 10). All uninstaciated indices until yours will forcible be created.

Answer 2

When you specify an array index that doesn't yet exist like [10], all previously unfilled indices are created. Just .push() it on.
var jsonVariable = [];
// A numeric property should be a string "1", though the browser will probably forgive you
// Just push the new object onto the array
jsonVariable.push({"1":10});
alert(JSON.stringify(jsonVariable));
// [{1:10}] exactly as you describe
If you need this particular object {1:10} to be present at jsonVariable[10], make it an object {} rather than an array.
var jsonVariable = {};
jsonVariable["10"] = {"1": 10};
alert(JSON.stringify(jsonVariable));
// {"10":{"1":10}}

Answer 3

I guess what you need is:
var jsonVariable = [];
for(var i=0;i<10;i++){
var temp = {};
temp[i] = {'Property' : "Data"}
jsonVariable.push(temp);
}
console.log( JSON.stringify(jsonVariable));

Answer 4

try this:
var jsonVariable = [];
jsonVariable[10] = {1:10};
function isNotEmpty(element, index, array) {
return array[index];
};
jsonVariable = jsonVariable.filter(isNotEmpty);
alert(jsonVariable.toSource());