PHP display error on another page - php

Question

I'm having issues to send an occuring error to another page.
I have already created the page the error will be sent to, and I've tried a header function. But that doesn't seem to work. Here is the php code that I am using for the page.
<?php
if(isset($_POST['username'], $_POST['password'])){
//login the user here
$connect = mysql_connect("","","")or die(mysql_error());
mysql_select_db("")or die(mysql_error());
$errors = array();
$username = strip_tags(mysql_real_escape_string($_POST['username']));
$password = strip_tags(mysql_real_escape_string($_POST['password']));
if (empty($Regi_Username) || empty($Regi_password)) {
$errors[] = 'All fields are requerid';
} else {
if (strlen($Regi_Username) > 25) {
$errors[] = 'Username is to long';
}
if (strlen($password) > 25) {
$errors[] = 'Password is to long';
}
}
$password = md5($_POST['password']);
$loginquery = "SELECT * FROM regi WHERE username='$username' and password='$password'" or die(mysql_error());
$result = mysql_query($loginquery);
$count = mysql_num_rows($result);
mysql_close();
if($count==1){
$seconds = 2000 + time();
setcookie(loggedin, date("F jS - g:i a"), $seconds);
header("location:member.php");
} else {
echo 'Wrong username and password please try agian.';
}
}
?>

Answer 1

Pass the GET variable in your URL like..
header('Location:page.php?err=1');
exit;
On the other page use this
if(isset($_GET['err'] && $_GET['err'] == 1) {
echo 'Error Occured';
}

Answer 2

Here is a session based approach. This is the best way to pass messages from one page to another as they are stored in the user's session (a piece of data related to each user and stored in the server side) and not in the browser (like cookies or URL GET parameters, which can be easily corrupted), so it is really quite harder to manipulate the messages from 3rd parties.
Page process.php:
<?php
// Very top of your page
session_start();
$_SESSION['errors'] = array();
// Do stuff now...
// ...
// Hey it's a X error!
$_SESSION['errors']['X'] = 'Message for X error';
// Continue doing stuff...
// ...
// OMG! It's a Y error now!
$_SESSION['errors']['Y'] = 'Message for Y error';
// Keep doing stuff till you're done...
// All right, process is finished. Any Errors?
if (count($_SESSION['errors']) > 0) {
// It seems there's been any errors
// time to redirect to error-displaying page
header('Location: error-page.php');
exit;
}
Page error-page.php:
<?php
// Very top of your page
session_start();
// Let's check if there is any error stored in the session.
// In the case no errors found, it is better to redirect to another page...
// ...why anybody would end in this page if no errors were thrown?
if (!isset($_SESSION['errors']) || !is_array($_SESSION['errors']) || empty($_SESSION['errors'])) {
header('Location: home.php');
exit;
}
// If we reach this point it means there's at least an error
foreach ($_SESSION['errors'] as $errorCode => $errorMessage) {
// Here we can display the errors...
echo '<p>Error ', $errorCode, ': ', $errorMessage, '</p>', PHP_EOL;
}
// You can also do stuff only if a certain error is received
if (array_key_exists('X', $_SESSION['errors'])) {
// Error `X` was thrown
echo '<p>Oh no! It seems you suffered a X error!!</p>', PHP_EOL;
echo 'Click here to go back home.', PHP_EOL;
}
// At the end you should to remove errors from the session
$_SESSION['errors'] = array();
// or
unset($_SESSION['errors']);

Answer 3

You could use Alien's method, but it'd better if you use Session:
// Assume you init the session already; Use json_encode since you use array for $errors
$_SESSION['errors_msg'] = json_encode($errors);
header("location:member.php");
// Remember to exit here after we call header-redirect
exit;
Besides, there are a lot of problems is your currently code:
Use salt for hashing password
Use mysqli over mysql
Filtering input, escaping output
.. Read other recommendations here in this topic ..
Please read http://www.phptherightway.com/. There is a lot of right recommendation (of course not all) for PHP.