mysql select where in array (php, mysql) - php

Question

Lets say i have an array in my mysql row:
a:3:{i:1;a:3:{i:0;s:1:"1";i:1;s:1:"3";i:2;s:1:"5";}i:4;a:3:{i:0;s:2:"21";i:1;s:2:"25";i:2;s:2:"29";}i:5;a:1:{i:0;s:2:"33";}}
It looks like this:
Array
(
[1] => Array
(
[0] => 1
[1] => 3
[2] => 5
)
[4] => Array
(
[0] => 21
[1] => 25
[2] => 29
)
[5] => Array
(
[0] => 33
)
)
Now, i am passing an array through _GET and i want to print out all rows that contain same values both in my mysql and passed array. For example, if i pass this array:
Array
(
[1] => Array
(
[0] => 5
)
)
A result should be shown, because my passed array contains option 5. I tried to do it like this:
$pecul = serialize($array);
$q=mysql_query("SELECT id from table WHERE options like '%$pecul%'")or die(mysql_error());
but it only prints out results with identical arrays.

Answer 1

You probably want to unserialize the data that's in your database first. Once it's in a PHP array you can perform a check for those options, so say:
if(in_array("5",$array)) {
$q=mysql_query("SELECT id from table WHERE options=5")or die(mysql_error());
}
If you need to do a query for all of the options, you can do a loop like so:
foreach($array as $option) {
$q=mysql_query("SELECT id from table WHERE options='$option'")or die(mysql_error());
}
But like mario said, you may want to think the options mechanism over and perhaps serialized data isn't what you need. This should hopefully work for you the way it is though.

Answer 2

the like operator match only match same it does not understand for example you have dem in like than it will also show the demolish so
i think for that you need first unserlize and than find by php by either loop or in_array() function
what %like% do suppose this is table Persons and you used the query
SELECT * FROM Persons WHERE City LIKE '%tav%'
+-------------+-------------+
| id | city |
+-------------+-------------+
| 1 | Sandnes |
+-------------+-------------+
| 2 | Stavanger |
+-------------+-------------+
so the result will be
+-------------+-------------+
| id | city |
+-------------+-------------+
| 2 | Stavanger | <----it has tav (s-tav-anger)
+-------------+-------------+

Answer 3

IN() Check whether a value is within a set of values
mysql> SELECT 2 IN (0,3,5,7);
-> 0
mysql> SELECT 'wefwf' IN ('wee','wefwf','weg');
-> 1
SELECT val1 FROM tbl1 WHERE val1 IN (1,2,'a');
View: IN MySql