Regexp tip request - php

I have a string like
"first,second[,b],third[a,b[1,2,3]],fourth[a[1,2]],sixth"
I want to explode it to array
Array (
0 => "first",
1 => "second[,b]",
2 => "third[a,b[1,2,3]]",
3 => "fourth[a[1,2]]",
4 => "sixth"
}
I tried to remove brackets:
preg_replace("/[ ( (?>[^[]]+) | (?R) )* ]/xis",
"",
"first,second[,b],third[a,b[1,2,3]],fourth[a[1,2]],sixth"
);
But got stuck one the next step

PHP's regex flavor supports recursive patterns, so something like this would work:
$text = "first,second[,b],third[a,b[1,2,3]],fourth[a[1,2]],sixth";
preg_match_all('/[^,\[\]]+(\[([^\[\]]|(?1))*])?/', $text, $matches);
print_r($matches[0]);
which will print:
Array
(
[0] => first
[1] => second[,b]
[2] => third[a,b[1,2,3]]
[3] => fourth[a[1,2]]
[4] => sixth
)
The key here is not to split, but match.
Whether you want to add such a cryptic regex to your code base, is up to you :)
EDIT
I just realized that my suggestion above will not match entries starting with [. To do that, do it like this:
$text = "first,second[,b],third[a,b[1,2,3]],fourth[a[1,2]],sixth,[s,[,e,[,v,],e,],n]";
preg_match_all("/
( # start match group 1
[^,\[\]] # any char other than a comma or square bracket
| # OR
\[ # an opening square bracket
( # start match group 2
[^\[\]] # any char other than a square bracket
| # OR
(?R) # recursively match the entire pattern
)* # end match group 2, and repeat it zero or more times
] # an closing square bracket
)+ # end match group 1, and repeat it once or more times
/x",
$text,
$matches
);
print_r($matches[0]);
which prints:
Array
(
[0] => first
[1] => second[,b]
[2] => third[a,b[1,2,3]]
[3] => fourth[a[1,2]]
[4] => sixth
[5] => [s,[,e,[,v,],e,],n]
)

Related

Finding sentences between characters

I am trying to find sentences between pipe | and dot ., e.g.
| This is one. This is two.
The regex pattern I use :
preg_match_all('/(:\s|\|+)(.*?)(\.|!|\?)/s', $file0, $matches);
So far I could not manage to capture both sentences. The regex I use captures only the first sentence.
How can I solve this problem?
EDIT: as it may seen from the regex, I am trying to find the sentences BETWEEN (: or |) AND (. or ! or ?)
Column or pipe indicates starting point for sentences.
The sentences might be:
: Sentence one. Sentence two. Sentence three.
| Sentence one. Sentence two?
| Sentence one. Sentence two! Sentence three?
I would keep it simple and just match on:
\s*[^.|]+\s*
This says to match any content not consisting of pipes or full stops, and it also trims optional whitespace before/after each sentence.
$input = "| This is one. This is two.";
preg_match_all('/\s*[^.|]+\s*/s', $input, $matches);
print_r($matches[0]);
This prints:
Array
(
[0] => This is one
[1] => This is two
)
This does the job:
$str = '| This is one. This is two.';
preg_match_all('/(?:\s|\|)+(.*?)(?=[.!?])/', $str, $m);
print_r($m)
Output:
Array
(
[0] => Array
(
[0] => | This is one
[1] => This is two
)
[1] => Array
(
[0] => This is one
[1] => This is two
)
)
Demo & explanation
Another option is to make use of \G to get iterative matches asserting the position at the end of the previous match and capture the values in a capturing group matching a dot and 0+ horizontal whitespace chars after.
(?:\|\h*|\G(?!^))([^.\r\n]+)\.\h*
In parts
(?: Non capturing group
\|\h* Match | and 0+ horizontal whitespace chars
| Or
\G(?!^) Assert position at the end of previous match
) Close group
( Capture group 1
- [^.\r\n]+ Match 1+ times any char other than . or a newline
) Close group
\.\h* Match 1 . and 0+ horizontal whitespace chars
Regex demo | Php demo
For example
$re = '/(?:\|\h*|\G(?!^))([^.\r\n]+)\.\h*/';
$str = '| This is one. This is two.
John loves Mary.| This is one. This is two.';
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
print_r($matches);
Output
Array
(
[0] => Array
(
[0] => | This is one.
[1] => This is one
)
[1] => Array
(
[0] => This is two
[1] => This is tw
)
)
To keep it simple, find everything between | and . and then split:
$input = "John loves Mary. | This is one. This is two. | Sentence 1. Sentence 2.";
preg_match_all('/\|\s*([^|]+)\./', $input, $matches);
if ($matches) {
foreach($matches[1] as $match) {
print_r(preg_split('/\.\s*/', $match));
}
}
Prints:
Array
(
[0] => This is one
[1] => This is two
)
Array
(
[0] => Sentence 1
[1] => Sentence 2
)

Validate url parameters with preg_match

Valid example
12[red,green],13[xs,xl,xxl,some other text with chars like _&-##%]
number[anythingBut ()[]{},anythingBut ()[]{}](,number[anythingBut ()[]{},anythingBut ()[]{}]) or nothing
Full match 12[red,green]
Group 1 12
Group 2 red,green
Full match 13[xs,xl,xxl,some other text with chars like _&-##%]
Group 1 13
Group 2 xs,xl,xxl,some other text with chars like _&-##%
Not valid example
13[xs,xl,xxl 9974-?ds12[dfgd,dfgd]]
What I tried is this: (\d+(?=\[))\[([^\(\[\{\}\]\)]+)\], regex101 link with what I tried, but this also matches wrong input like given in the example.
If you just need to validate the input, you can add some anchors:
^(?:\d+\[[^\(\[\{\}\]\)]+\](?:,|$))+$
Regex101
If you also need to get all the matching parts, you can use another regex. Using only one will not work well.
$in = '12[red,green],13[xs,xl,xxl,some other text with chars like _&-##%],13[xs,xl,xxl 9974-?ds12[dfgd,dfgd]]';
preg_match_all('/(\d+)\[([^][{}()]+)(?=\](?:,|$))/', $in, $matches);
print_r($matches);
Output:
Array
(
[0] => Array
(
[0] => 12[red,green
[1] => 13[xs,xl,xxl,some other text with chars like _&-##%
)
[1] => Array
(
[0] => 12
[1] => 13
)
[2] => Array
(
[0] => red,green
[1] => xs,xl,xxl,some other text with chars like _&-##%
)
)
Explanation:
/ : regex delimiter
(\d+) : group 1, 1 or more digits
\[ : open square bracket
( : start group 2
[^][{}()]+ : 1 or more any character that is not open or close parenthesis, brackets or square brackets
) : end group 2
(?= : positive lookahead, make sure we have after
\] : a close square bracket
(?:,|$) : non capture group, a comma or end of string
) : end group 2
/ : regex delimiter

regexp monetary strings with decimals and thousands separator

https://www.tehplayground.com/KWmxySzbC9VoDvP9
Why is the first string matched?
$list = [
'3928.3939392', // Should not be matched
'4.239,99',
'39',
'3929',
'2993.39',
'393993.999'
];
foreach($list as $str){
preg_match('/^(?<![\d.,])-?\d{1,3}(?:[,. ]?\d{3})*(?:[^.,%]|[.,]\d{1,2})-?(?![\d.,%]|(?: %))$/', $str, $matches);
print_r($matches);
}
output
Array
(
[0] => 3928.3939392
)
Array
(
[0] => 4.239,99
)
Array
(
[0] => 39
)
Array
(
[0] => 3929
)
Array
(
[0] => 2993.39
)
Array
(
)
You seem to want to match the numbers as standalone strings, and thus, you do not need the lookarounds, you only need to use anchors.
You may use
^-?(?:\d{1,3}(?:[,. ]\d{3})*|\d*)(?:[.,]\d{1,2})?$
See the regex demo
Details
^ - start of string
-? - an optional -
(?: - start of a non-capturing alternation group:
\d{1,3}(?:[,. ]\d{3})* - 1 to 3 digits, followed with 0+ sequences of ,, . or space and then 3 digits
| - or
\d* - 0+ digits
) - end of the group
(?:[.,]\d{1,2})? - an optional sequence of . or , followed with 1 or 2 digits
$ - end of string.

split string by spaces and colon but not if inside quotes

having a string like this:
$str = "dateto:'2015-10-07 15:05' xxxx datefrom:'2015-10-09 15:05' yyyy asdf"
the desired result is:
[0] => Array (
[0] => dateto:'2015-10-07 15:05'
[1] => xxxx
[2] => datefrom:'2015-10-09 15:05'
[3] => yyyy
[4] => asdf
)
what I get with:
preg_match_all("/\'(?:[^()]|(?R))+\'|'[^']*'|[^(),\s]+/", $str, $m);
is:
[0] => Array (
[0] => dateto:'2015-10-07
[1] => 15:05'
[2] => xxxx
[3] => datefrom:'2015-10-09
[4] => 15:05'
[5] => yyyy
[6] => asdf
)
Also tried with preg_split("/[\s]+/", $str) but no clue how to escape if value is between quotes. Can anyone show me how and also please explain the regex. Thank you!
I would use PCRE verb (*SKIP)(*F),
preg_split("~'[^']*'(*SKIP)(*F)|\s+~", $str);
DEMO
Often, when you are looking to split a string, using preg_split isn't the best approach (that seems a little counter intuitive, but that's true most of the time). A more efficient way consists to find all items (with preg_match_all) using a pattern that describes all that is not the delimiter (white-spaces here):
$pattern = <<<'EOD'
~(?=\S)[^'"\s]*(?:'[^']*'[^'"\s]*|"[^"]*"[^'"\s]*)*~
EOD;
if (preg_match_all($pattern, $str, $m))
$result = $m[0];
pattern details:
~ # pattern delimiter
(?=\S) # the lookahead assertion only succeeds if there is a non-
# white-space character at the current position.
# (This lookahead is useful for two reasons:
# - it allows the regex engine to quickly find the start of
# the next item without to have to test each branch of the
# following alternation at each position in the strings
# until one succeeds.
# - it ensures that there's at least one non-white-space.
# Without it, the pattern may match an empty string.
# )
[^'"\s]* #"'# all that is not a quote or a white-space
(?: # eventual quoted parts
'[^']*' [^'"\s]* #"# single quotes
|
"[^"]*" [^'"\s]* # double quotes
)*
~
demo
Note that with this a little long pattern, the five items of your example string are found in only 60 steps. You can use this shorter/more simple pattern too:
~(?:[^'"\s]+|'[^']*'|"[^"]*")+~
but it's a little less efficient.
For your example, you can use preg_split with negative lookbehind (?<!\d), i.e.:
<?php
$str = "dateto:'2015-10-07 15:05' xxxx datefrom:'2015-10-09 15:05' yyyy asdf";
$matches = preg_split('/(?<!\d)(\s)/', $str);
print_r($matches);
Output:
Array
(
[0] => dateto:'2015-10-07 15:05'
[1] => xxxx
[2] => datefrom:'2015-10-09 15:05'
[3] => yyyy
[4] => asdf
)
Demo:
http://ideone.com/EP06Nt
Regex Explanation:
(?<!\d)(\s)
Assert that it is impossible to match the regex below with the match ending at this position (negative lookbehind) «(?<!\d)»
Match a single character that is a “digit” «\d»
Match the regex below and capture its match into backreference number 1 «(\s)»
Match a single character that is a “whitespace character” «\s»

preg_match_all for words in and outside of brackets

I have been sitting for hours to figure out a regExp for a preg_match_all function in php.
My problem is that i whant two different things from the string.
Say you have the string "Code is fun [and good for the brain.] But the [brain is] tired."
What i need from this an array of all the word outside of the brackets and the text in the brackets together as one string.
Something like this
[0] => Code
[1] => is
[2] => fun
[3] => and good for the brain.
[4] => But
[5] => the
[6] => brain is
[7] => tired.
Help much appreciated.
You could try the below regex also,
(?<=\[)[^\]]*|[.\w]+
DEMO
Code:
<?php
$data = "Code is fun [and good for the brain.] But the [brain is] tired.";
$regex = '~(?<=\[)[^\]]*|[.\w]+~';
preg_match_all($regex, $data, $matches);
print_r($matches);
?>
Output:
Array
(
[0] => Array
(
[0] => Code
[1] => is
[2] => fun
[3] => and good for the brain.
[4] => But
[5] => the
[6] => brain is
[7] => tired.
)
)
The first lookbind (?<=\[)[^\]]* matches all the characters which are present inside the braces [] and the second [.\w]+ matches one or more word characters or dot from the remaining string.
You can use the following regex:
(?:\[([\w .!?]+)\]+|(\w+))
The regex contains two alternations: one to match everything inside the two square brackets, and one to capture every other word.
This assumes that the part inside the square brackets doesn't contain any characters other than alphabets, digits, _, !, ., and ?. In case you need to add more punctuation, it should be easy enough to add them to the character class.
If you don't want to be that specific about what should be captured, then you can use a negated character class instead — specify what not to match instead of specifying what to match. The expression then becomes: (?:\[([^\[\]]+)\]|(\w+))
Visualization:
Explanation:
(?: # Begin non-capturing group
\[ # Match a literal '['
( # Start capturing group 1
[\w .!?]+ # Match everything in between '[' and ']'
) # End capturing group 1
\] # Match literal ']'
| # OR
( # Begin capturing group 2
\w+ # Match rest of the words
) # End capturing group 2
) # End non-capturing group
Demo

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