Confused by the title? hehe. Not sure how to explain this one, but I think my snippet of code should explain things a little easier.
This is what I'm trying to pass through the $data variable. div is displayed as it should be, but the echo statement inside (which I need) is NOT displayed.
Where am I messing up?
$data['packagename'] = '<div class="somedoodoo"> echo $row->subscription </div>';
You can just use string concatenation:
$data['packagename'] = '<div class="something">' . $row->subscription . '</div>';
you can't execute code inside a string like that, plus, it's the wrong quotes:
$data['packagename'] = <<<EOL
<div class="somedoodoo">{$row->subscription}</div>
EOL;
relevant docs on heredocs: http://php.net/heredoc
Related
Hello dear programmers,
I have a problem with the echoing of a html phrase with an onclick function that executes a javascript function. I want to build a tabpage, for a image gallery.
The echo:
echo "<div class='albumitem'><a class='tablinks' onclick='openAlbum(event, '".$album."')'><h1 class='galleryheader'>".$album."</h1></a><div id='".$album."' class='tabcontent'>";
Everything goes well, except the passing of the variable in the onclick function, as you can see here. What actually the HTML looks like:
<a class="tablinks" onclick="openAlbum(event, " aubing')'=""><h1 class="galleryheader">Aubing</h1></a>
But this onclick event has to look like this:
onclick="openAlbum(event, 'Aubing')"
Is there a way to actually realise this or do I have to find an other option?
I actually tried switching " with ', didnt go very well....
Thank you for everybody that tries to help
Try this:
echo "<div class='albumitem'><a class='tablinks' onclick='openAlbum(event, \"$album\")'><h1 class='galleryheader'>".$album."</h1></a><div id='".$album."' class='tabcontent'>";
see escaped double quotes in the onclick definition
addslashes is what you are looking exactly.And also you have to remove the single quotes in variable.Try to do the following way.
echo "<div class='albumitem'><a class='tablinks' onclick='openAlbum(event, '".addslashes($album)."')'><h1 class='galleryheader'>".$album."</h1></a><div id=".addslashes($album)." class='tabcontent'>";
Hope this help.
An alternative:
$escapedString = htmlspecialchars('This is a test string: < > & \' " end.', ENT_COMPAT);
echo "<div onclick='alert(this.dataset.name)' data-name=\"$escapedString\">Click Me</div>";
This approach avoid quotes inside function, no quotes nesting.
Im new to learning PHP as you might have guessed. I have the contents of a .txt file echoed but I would like it to stand out more, so I figured I would make it a different colour.
My code without colour:
<?php
$file = fopen("instructions.txt", "r") or exit("Unable to open file");
while(!feof($file))
{
echo fgets($file);
}
fclose($file);
?>
I have researched this and seen suggestions to others to use a div style, however this didn't work for me, it gave me red errors all the way down the page instead! I think its because I'm using 'fgets' not just a variable? Is there a way to colour the echo red?
The code I tried but doesn't work:
echo "<div style=\"color: red;\">fgets($file)</div>";
(In general) You need to separate the actual PHP code from the literal portions of your strings. One way is to use the string concatenation operator .. E.g.
echo "<div style=\"color: red;\">" . fgets($file) . "</div>";
String Operators
Other answer already told that you can't use a function call in a double quoted string. Let additionally mention that for formatting only tasks a <span> element is better suited than a <div> element.
Like this: https://developer.mozilla.org/en-US/docs/Web/HTML/Element/span
You should try:
<div style="color: red;"><?= fgets($file);?></div>
Note: <?= is an short hand method for <?php echo fgets($file);?>
This version does not need to escape double quotes:
echo '<div style="color:red;">' . fgets($file) . '</div>';
You can do this with the concatenate operator . as has already been mentioned but IMO it's cleaner to use sprintf like this:
echo sprintf("<div style='color: red;'>%s</div>", fgets($file));
This method comes into it's own if you have two sets of text that you want to insert a string in different places eg:
echo sprintf("<div style='color: red;'>%s</div><div style='color: blue;'>%s</div>", fgets($file), fgets($file2));
I am trying to create the necessary url from this code however it is working and I am struggling to find out why.
$linkere = $row['message'];
echo '<a href="me.php?message=<?php echo rawurlencode($linkere); ?>">'
Currently this code is producing the url: me.php?message= . But, I would like it to create the url: me.php?message=hello for example.
Thanks for helping!
You are passing $linkere to rawurlencode(). The variable is actually named $linker.
$linker = $row['message'];
echo '<a href="me.php?message=<?php echo rawurlencode($linker); ?>">'
You have alot of syntax problems here.
first, you need to use Concatenation message='.rawurlencode($linker).'"
second your variable do not exist, it should be $linker.
Second close the tag and insert the text, in this case i used Test.
$linker = $row['message'];
echo 'Test';
Can you try this,
$linker = $row['message'];
echo 'YOUR LINK TEXT HERE';
You don't need the <? ?> and echo in your echo, it should just be:
$linkere = $row['message'];
echo 'Test';
Otherwise you are turning php on and off again to echo something within an already open instance of php in which you are already echoing.
I am creating a hyperlink in foreach loop. It is working fine. When I am passing $id in URL parameter then it is not working. my link is showing http://****/test/index.php/test/view?id=**. i don't what i am doing wrong here.
foreach($list as $item)
{
$rs[]=$item['uname'];
$id=$item['uid'];
//var_dump($id); here it's printing $id value...
echo '<b> '.$item['uname'].'<br/>';
}
I want to pass $id value with hyperlink. Please suggest me.
It's of course getting printed -- your browser is just not displaying it to you since it's not being correctly parsed as HTML due to the extra " around the $id variable.
Set your header as follows:
header('Content-Type: text/plain');
and you'll see that it returns something like:
<b> FOOBAR<br/>
^ ? ^
As you can see, the issue is the extra double-quote before 55.
Change your code to:
echo '<b> <a href="/test/index.php/test/view?id=' . $id .'">'.
$item['uname'] . '</a><br/>';
Alternatively, you could also use double-quotes and enclose your variables inside {}, like so:
echo "<b> <a href=\"/test/index.php/test/view?id=$id\">{$item['uname']}
</a><br/>";
I'd use sprintf as it's cleaner.
echo sprintf('<b> %s<br/>', $id, $item['uname']);
You have another ".
Change this:
echo '<b> '.$item['uname'].'<br/>';
To this:
echo '<b> '.$item['uname'].'<br/>';
Try this:
echo "<b><a href='/test/index.php/test/view?id=$id'>$item</a></b><br/>";
This works!
And is the easiest and cleanest option. Inside of the double escaping, the simple is used for the html and through the double escaping all variables are written inside :) . Very simple.
I have been using the following to add a dynamic link on a page I am writing, it works ok and appears how it should on the page but I cant help but think that I am going a bit backwards with the way its written as it looks messy. What is the correct way to write it, as if I put it all in one line it doesn't work ?..
echo '<a href="./customer-files/';
echo $customerID;
echo '/';
echo $filename->getFilename();
echo '">';
echo $filename->getFilename();
echo '</a>';
Try with
echo "{$filename->getFilename()}";
Here there is the documentation with a lot of examples of how to concatenate output.
I'd approach it like this:
$safe_customer_id = htmlspecialchars(urlencode($customerID));
$safe_filename = htmlspecialchars(urlencode($filename->getFilename()));
$safe_label = htmlspecialchars($filename->getFilename());
echo "$safe_label";
I would go with this:
$fn = $filename->getFilename();
$link = $customerID . '/' . $fn;
echo ''.$fn.'';
If you're using a template layer, it is even better to break out into PHP only when you need to:
<a href="./customer-files/<?php
echo $customerID . '/' . $filename->getFilename()
?>">
<?php echo $filename->getFilename() ?>
</a>
This way, your IDE will correctly highlight your HTML as well as your PHP. I've also ensured that all PHP is in single-line blobs, which is the best approach for templates (lengthy statements should be banished to a controller/script).
Concatenation is your friend. Use a . to combine multiple string expression into one.
echo ''.$filename->getFilename()/'';
Even better way would be
$filename = $filename -> getFilename(); //cache the filename
echo "<a href='/$customerId/$filename'>$filename</a>";
// ^ On this echo NOTICE that variables can be DIRECTLY placed inside Double qoutes.