so i have a php loop, i am using jquery slide toggle to hide/show a table with sql results. currently the table is loaded using php only, but as there is a lot going on its causing some loading problems i need to fire the ajax with the slide toggle btn, so it only requests the current items details when the button is pressed. i can get it to call the php file from the jquery but im having difficulty passing the value for each item across, so it can perform the request on the database. here is what the php foreach loop content looks like;
<span class="searchitem">
// some visible content here
<span value="item name" class="btn">button</span>
<span class="slide_area">
// hidden slide content ajax needs to populate with php result
</span>
</span>
this html is repeated i use jquery slidetoggle to hide the slide_area, what i need to do is populate the slide_area with results from php, the php file needs the name to return the results the name is passed via get with the url, so i only need append the url with the actual name from btn's value, im sure this cant be that difficult but here i am.
here's the jquery:
<script type="text/javascript">
//<![CDATA[
$(document).ready(function ()
{
$('.searchitem').each(function () {
$(this).find('.slide_area').hide();
$(this).find('.btn').click(function ()
{
var ajax_load = "<img src='images/spinner.gif' style='width:50px;' alt='loading...' />";
var loadUrl = "ajax/item.php?name=";
var loadName = $(".btn");
var Name = URLEncode(loadName);
var loadString = loadUrl + Name;
$(this).parent().find('.slide_area').slideToggle(1500).html(ajax_load).load(loadString);
});
});
});
//]]>
</script>
i need to get the value from btn and append the loadURL, im open to sending the data a different way like through post if needed, updated the jquery still not working what am i doing wrong here?
Thanks.
The easiest way would to use the Phery library http://phery-php-ajax.net/
the key here is the data-phery-remote="toggle" that will call the PHP function automatically on click, and can be reused everywhere
<span class="searchitem">
// some visible content here
<span value="item name" data-phery-remote="toggle" class="btn">button</span>
<span class="slide_area">
// hidden slide content ajax needs to populate with php result
</span>
</span>
The logic is reversed, the load will happen with only one AJAX call, instead of two.
Phery::instance()->set(array(
'toggle' => function($data){
$r = new PheryResponse;
/* do your code, fill $html_content */
$r->this()->siblings('.slide_area')->html($html_content)->toggle();
return $r;
}
))->process();
Related
I am failing hardcore with describing this but here it goes..
I have home.php, pretty much just:
<body>
<div id='leftColumn'>
<?php include ('includes/roomQuery.php')
</div>
</body>
Now,
roomQuery.php echos my sql column 'room_name' from table 'rooms' as follows:
echo "<td>$roomName</td>";
Any of the room links will take me to room.php and populate the page with more queries respective to $roomName via $_GET.
room.php is basically:
$get = $_GET['room'];
$query
while($row = $result->fetch_assoc()){
echo $query
This is working perfectly for what it is.
====================================
however, I am trying to make my site flow better, and have been trying out the jQuery .load function. So far I have changed roomQuery.php to:
echo "<td><button>$roomName</button></td>";
here is my jQuery to replace home.php #page with room.php #page:
$(document).ready(function(){
$("button").click(function(){
$("#page").load("room.php #page",function(responseTxt,statusTxt,xhr){
if(statusTxt=="success")
alert("Success");
if(statusTxt=="error")
alert("Error: "+xhr.status+": "+xhr.statusText);
});
});
});
When I click any of the buttons that roomQuery.php spits out, it replaces #page perfectly but I cannot grasp how/if I can send $_GET['room'] to room.php so that when #page is loaded, the information is still respective to the room I clicked on. If I change jQuery to
$("#page").load("room.php?room=CL%20124 #page"
Then #page is populated with the data specifically respective to room CL 124. Is it possible to post the button text that is output from roomsQuery.php to room.php #page when the button is clicked?
Yes, you can pass data into the .load() call as the second parameter.
Firstly, you need to work out how to get the room ID from the DOM into your jQuery call, maybe you could use a data attribute on the button element like this:
<button data-room-id="123">Click me</button>
Then use jQuery like this:
$("button").click(function(){
// define your room ID here, however you do it
var your_room = $(this).data('room-id');
$("#page").load(
"room.php #page",
{
room: your_room
},
function(responseTxt,statusTxt,xhr){
if(statusTxt=="success")
alert("Success");
if(statusTxt=="error")
alert("Error: "+xhr.status+": "+xhr.statusText);
}
);
});
Edit: just noticed that you might actually be using the button's value as your room ID, if so, use this definition:
var your_room = $(this).val();
If you're expecting spaces or non-alpha numeric characters in this value, you might want to consider URL encoding it before you send it.
I have very limited knowledge with scripts so I hope you guys can help me with a simple solution to a small problem that I have...
I'm using the following jquery function to refresh a div with new content when a link is clicked
<script>
$(function() {
$("#myButton").click(function() {
$("#loaddiv").fadeOut('slow').load("reload.php").fadeIn("slow");
});
});
</script>
My problem is, I need to send 2 variables to the reload.php page to use in a mysql query (I have no idea how to accomplish that), also I need to make multiple links work with this function, at the moment I have multiples links with the same id and only the first link works so I guess I must associate different ids to the function in order for this to work, how can I do that?
here's the page where i'm using this: http://www.emulegion.info/teste/games/game.php
You may want to use document ready instead of function on your first line as this will make sure the code is not executed until the full page (and all elements) have loaded.
You can then use the callback functions of the fade and load to perform actions in a timely manner.
additional variables you can add after the .php, these can then be read in your reload.php file as $var1 = $_GET['var1'];
Do make sure to sanitize these though for security.
<script type="text/javascript">
// execute when document is ready
$(document).ready(function() {
// add click handler to your button
$("#myButton").click(function() {
// fade div out
$("#loaddiv").fadeOut('slow',function(){
// load new content
$("#loaddiv").load("reload.php?var1=foo&var2=bar",function(){
// content has finished loading, fade div in.
$("#loaddiv").fadeIn('slow');
}); // end load content
}); // end fade div out
}); // end add click to button
}); // end document ready
</script>
For different variables you could add a HTML5 style variable to your button.
<input type="button" id="myButton" data-var1="foo" data-var2="bar" />
You can retrieve this when the button is clicked:
// add click handler to your button
$("#myButton").click(function() {
// get vars to use
var var1 = $(this).data('var1');
var var2 = $(this).data('var2');
...
load("reload.php?var1="+var1+"&var2="+var2
if you have multiple buttons/links I would use class instead of id "myButton". that way you can apply the function to all buttons with the above script. Just replace "#myButton" for ".myButton"
First, you should use .on('click', function() or .live('click', function() to resolve your one click issue.
You'll want to do something like:
<script>
$(function() {
$("#myButton").on('click', function() {
var a = 'somthing';
var b = 'something_else';
$.post('url.php', {param1: a, param2: b}, function(data) {
//data = url.php response
if(data != '') {
$("#loaddiv").fadeOut('slow').html(data).fadeIn("slow");
}
});
});
});
</script>
Then you can just put var_dump($_POST); in url.php to find out what data is being sent.
Try creating a function that would accept parameters that you want.
Like:
$(document).ready(function(){
$('.link').click(function(){
reload(p1,p2);
});
});
function reload(param1, param2){
$("#loaddiv").fadeOut('slow').load("reload.php?param1="+param1+"¶m2="+param2).fadeIn("slow");
}
But by doing the above code your reload.php should be using $GET. Also you need to use class names for your links instead of id.
<script type="text/javascript">
// execute when document is ready
**$(document).ready(function() {**
**$("#myButton").click(function() {**
**$("#loaddiv").fadeOut('slow',function(){**
**$("#loaddiv").load("reload.php?var1=foo&var2=bar",function(){**
// content has finished loading, fade div in.
$("#loaddiv").fadeIn('slow');
});
});
});
});
</script>
$("#myButton").click(function() {
// get vars to use
var var1 = $(this).data('var1');
var var2 = $(this).data('var2');
I had to ask this one again, sorry. So I am running this jQuery to slide toggle a span in my PHP loops output. I have some PHP that generates some calls to the db to get more detailed information back for each item.
I know so far I have got it making the call to the PHP script. I can see the packets returning with the HTML echoed from the PHP file. but I'm having difficulty getting jQuery to insert the returned data into the specified span.
This is a simplified version of what the loop items look like:
<span class="searchitem">
<span style="visibility:hidden;" class="name">some name</span>
<span class="btn">Details</span>
<span class="itemdetails" style="display: none;">
//hidden area to populate with returned ajax html from php script
</span>
</span>
<span class="searchitem">
<span style="visibility:hidden;" class="name">another name</span>
<span class="btn">Details</span>
<span class="itemdetails">
<div>
<p>
this is the area i need the html to populate
</p>
</div>
</span>
</span>.................
This is the jQuery that I'm trying to run. I know everything works up to success. I can't get the data from there.
<script type="text/javascript">
var ajax_load = "<img src='images/loading.gif' style='width:50px;' alt='loading...' />";
var loadUrl = "ajax/item_details.php";
$(document).ready(function ()
{
$('.searchitem').each(function () {
var itemname = $(this).find('.name').text();
var ename = encodeURI(itemname);
var requestUrl = loadUrl + ename;
$(this).find('.itemdetails').hide();
$(this).find('.btn').click(function ()
{
var returned = "";
$.ajax({
type: "GET",
url: loadUrl,
data: "name=" + ename,
dataType: "text",
error: function () { alert("error") },
success: function (data) { $(".ptavail").append(data); alert("successful") }
});
$(this).parent().find('.ptavail').html(ajax_load).slideToggle(1500).html(returned);
});
});
});
</script>
As you can see from the code I'm trying to get the click function the set everything off. I know the PHP file is receiving the call and returning the data but I'm stuck trying to get the jQuery to fill the .itemdetails with the returned data.
What is wrong with this? Would I need to put the AJAX into a separate function for it to behave like I need, or do I need to make it synchronous for it to work? I'm trying to basically replace everything between .itemdetails spans with first a loading symbol and then the data returned with AJAX.... As it is now I get error alert so there's something wrong with the ajax call I know it does the request properly and the PHP returns the results but getting AJAX to read them is proving problematic.
I can see that the content type in the headers is text, so how do I get the AJAX to do the call properly?
Put $(this).parent().find('.itemdetails').html(ajax_load).slideToggle(1500).html(data);
inside the "success" part of the Ajax request.
success: function(data) {
$(this).parent().find('.itemdetails').html(ajax_load).slideToggle(1500).html(data);
}
The success function is there to say "when the Ajax has worked, do this"
I have a web page that lists a number of companies from a MYSQL database, the listing just shows the name of the company. When user clicks on the company name a jquery accordion slider shows the rest of the information about that company.
When company name is clicked it also sends a request to a php script to log that a person has viewed that company's details.
My Problem
I want to send the ID for each record to the php script.
I have achieved this by including the accordion jquery code within the while loop that reads the output of the mysql query, but it generates a lot of unnecessary source code (i.e. for each company listed).
I need to include the jquery accordion code outside of the while statement.
How do I pass the id of each database record (i.e. company name) to the $.post in the jquery code, when it is outside of the while loop?
Accordion Jquery code
$(document).ready(function() { $('div.listing> div').hide(); $('div.listing> h4').click(function() {
$.post("/record.php", { id: "<?php echo $LM_row02[id]; ?>" } )
var $nextDiv = $(this).next();
var $visibleSiblings = $nextDiv.siblings('div:visible');
if ($visibleSiblings.length ) {
$visibleSiblings.slideUp('fast', function() {
$nextDiv.slideToggle('fast');
});
} else {
$nextDiv.slideToggle('fast');
} }); });
Any idea most welcome.
When you create the HTML (I assume you do that in the loop as well), add a data-* attribute with the ID as value to the element and read that value with jQuery when the element is clicked on.
E.g. your resulting HTML will look like:
<h4 data-id="123">Some title</h4>
and your JavaScript:
$('div.listing > h4').click(function() {
$.post("/record.php", { id: $(this).attr('data-id') }, function() {
// ...
});
});
When you create the h4 element in html add a html5 data attribute like
<h4 data-companyid="<?php echo $LM_row02[id]; ?>">Company Name</h4>
Then use that companyid in your ajax call like
$.post("/record.php", { id: $(this).data('companyid') } );
I list a lot of users on my page and I use a php function to pass the user's id and return a div pop up that displays their online status, avatar, stats etc. The problem is that the code is currently set to show the layer onmouseover and hide the layer onmouseout. I would like the code to be onclick show, and second click (either toggle on the same link or click anywhere else on the page) hide the layer but I'm not sure how to accomplish that.
The current code I'm using I got from Dynamic Drive. (sorry my tab key won't work in this text box, not sure how to fix that. feel free to edit)
SKIP TO BOTTOM
Original Method:
Javascript part
<div id="dhtmltooltip"></div>
<script type="text/javascript">
/***********************************************
* Cool DHTML tooltip script- Dynamic Drive DHTML code library (www.dynamicdrive.com)
* This notice MUST stay intact for legal use
* Visit Dynamic Drive at http://www.dynamicdrive.com/ for full source code
***********************************************/
var offsetxpoint=-60 //Customize x offset of tooltip
var offsetypoint=20 //Customize y offset of tooltip
var ie=document.all
var ns6=document.getElementById && !document.all
var enabletip=false
if (ie||ns6)
var tipobj=document.all? document.all["dhtmltooltip"] : document.getElementById? document.getElementById("dhtmltooltip") : ""
function ietruebody(){
return (document.compatMode && document.compatMode!="BackCompat")? document.documentElement : document.body
}
function ddrivetip(thetext, thecolor, thewidth){
if (ns6||ie){
if (typeof thewidth!="undefined") tipobj.style.width=thewidth+"px"
if (typeof thecolor!="undefined" && thecolor!="") tipobj.style.backgroundColor=thecolor
tipobj.innerHTML=thetext
enabletip=true
return false
}
}
function positiontip(e){
if (enabletip){
var curX=(ns6)?e.pageX : event.clientX+ietruebody().scrollLeft;
var curY=(ns6)?e.pageY : event.clientY+ietruebody().scrollTop;
//Find out how close the mouse is to the corner of the window
var rightedge=ie&&!window.opera? ietruebody().clientWidth-event.clientX-offsetxpoint : window.innerWidth-e.clientX-offsetxpoint-20
var bottomedge=ie&&!window.opera? ietruebody().clientHeight-event.clientY-offsetypoint : window.innerHeight-e.clientY-offsetypoint-20
var leftedge=(offsetxpoint<0)? offsetxpoint*(-1) : -1000
//if the horizontal distance isn't enough to accomodate the width of the context menu
if (rightedge<tipobj.offsetWidth)
//move the horizontal position of the menu to the left by it's width
tipobj.style.left=ie? ietruebody().scrollLeft+event.clientX-tipobj.offsetWidth+"px" : window.pageXOffset+e.clientX-tipobj.offsetWidth+"px"
else if (curX<leftedge)
tipobj.style.left="5px"
else
//position the horizontal position of the menu where the mouse is positioned
tipobj.style.left=curX+offsetxpoint+"px"
//same concept with the vertical position
if (bottomedge<tipobj.offsetHeight)
tipobj.style.top=ie? ietruebody().scrollTop+event.clientY-tipobj.offsetHeight-offsetypoint+"px" : window.pageYOffset+e.clientY-tipobj.offsetHeight-offsetypoint+"px"
else
tipobj.style.top=curY+offsetypoint+"px"
tipobj.style.visibility="visible"
}
}
function hideddrivetip(){
if (ns6||ie){
enabletip=false
tipobj.style.visibility="hidden"
tipobj.style.left="-1000px"
tipobj.style.backgroundColor=''
tipobj.style.width=''
}
}
document.onmousemove=positiontip
</script>
PHP part
$username = "<a onMouseover=\"ddrivetip('<Center><font class=f2>$username</font><BR>$avatarl</center>
<table align=center><Tr><Td><b>Points:</b> <font class=alttext>$user_points</font>
<BR><B>Posts:</b> <font class=alttext>$user_posts</font><BR>$user_status</td></tr></table>
<BR><img src=$icons/add-user.png height=12> <a href=$cs_url/friends/add/$user>Send Friend Request</a>
<BR><img src=$icons/user_message2.png height=12> <a href=$cs_url/messages/compose/$user>Send Message</a>
<BR><img src=$icons/user_im2.png height=12> Instant Message')\"
onMouseout=\"hideddrivetip()\">$username</a>";
My primary reason for wanting the toggle/blur as opposed to mouseout is so that users have the chance to actually click the links inside of the div layer.
The reason why I am trying to stick to this script as opposed to other ones out there I've found is because it doesn't rely on unique ids or alot of css styles. With other scripts, when I click on one username, they all of the hidden divs on the page pop up, or at least all of them for that user. This seemed to be the best for showing just one at a time.
I decided to scrap the method above. I have a script that I also got elsewhere that I use to toggle a twitter-like login in. I was wondering how I could use it to toggle the user information layer.
Second Method:
Javascript
$(".users").click(function(e) {
e.preventDefault();
$("fieldset#users_menu").toggle();
$(".users").toggleClass("menu-open");
});
$("fieldset#users_menu").mouseup(function() {
return false
});
$(document).mouseup(function(e) {
if($(e.target).parent("a.users").length==0) {
$(".users").removeClass("menu-open");
$("fieldset#users_menu").hide();
}
});
PHP part
<div id='container' class='users_container'>
<div id='usersnav' class='usersnav'> <a href='<?php echo $cs_url; ?>/users/all' class='users'><span>Fans</span></a> </div>
<fieldset id='users_menu'>
content
</fieldset>
</div>
The problem with this method as I mentioned before is that when I click on the username link, ALL of the layers for ALL of the users display on the page appear. How can I make it so that only the child layer of the parent link is displayed? Also, is there a way to toggle the layer hidden when anywhere else on the page is clicked?
Starting from your old code I assume you had something like:
elem.onmouseover = showCard;
elem.onmouseout = hideCard;
Well, from there you just need to do something along the lines of:
elem.isShown = false;
elem.onclick = function() {
if( elem.isShown) hideCard();
else showCard();
elem.isShown = !elem.isShown;
}
This ended up being the best solution though there is still one thing I wish was different about it.
This is built upon Dan's response. The reason why it wasn't working before Dan was because the user information was inside tags, I switcher username to span and the content display. The problem after that was when I clicked on one username the layer would popup but it would remain until I clicked on the same link again. So multiple layers would sometimes be on at once.
The following closes the layer when a user clicks on the layer, outside the layer or on the original link. The one little snag is that when clicking on the original link to close the layer you must click twice.
Javascript
<script type="text/javascript">
$(document).ready(function () {
$(".username").click(function () {
$(this).children().toggle();
$('.tooltip_container').hover(function(){
mouse_is_inside=true;
}, function(){
mouse_is_inside=false;
});
$(".username").click(function () {
$(this).children().toggle();
});
});
$("body").mouseup(function(){
if(! mouse_is_inside) $('.tooltip_container').hide();
});
});
</script>
PHP
<span class='username'>$username
<div class='tooltip_container'>
<div class='tooltip'>
Content goes here
</div>
</div>
</span>