htm code :
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
Movie :<br />
<input name="fileField" type="file" size="30" /><br />
<input name="submit" type="submit" class="submit" value="Send" />
</form>
php code :
if ($_FILES['fileField']['tmp_name'] !=""){
$fileName = $_FILES["fileField"]["name"];
$fileType = $_FILES["fileField"]["type"];
$fileTmpLoc = $_FILES["fileField"]["tmp_name"];
$fileName = preg_replace('#[^a-z.0-9]#i', '', $fileName);
move_uploaded_file($fileTmpLoc, '../upload/video.flv');
}
this code not work for VIDEO file but work correct for other file ( jpeg , mp3 , png and ,,, )
Perhaps change your directory to
move_uploaded_file($fileTmpLoc, '../upload/ ');
this problem from php setting
php set to Max 2MB size for upload
You have absolutely no error handling on the code, meaning you have no way of telling when an upload failed. Add:
if ($_FILES['fileField']['error'] !== UPLOAD_ERR_OK) {
die("Upload failed with error " . $_FILES['fileField']['error']);
}
as some bare-minimum error handling. The error codes are defined here: http://php.net/manual/en/features.file-upload.errors.php. Checking for the absence of a 'tmp_name' is NOT a proper check.
Related
Well pretty simple question.. But can't get it right for some reason.
What would be the html code to send a file to this?
move_uploaded_file($FILES["upload"]["tmpname"], $_POST["name"]);
Here's mine but when I used it and echo/vardump everything, I only have 'name' and not the file
<form action="uploader.php" method="post" id="myForm" enctype="multipart/form-data">
Select file to upload:
<input type="file" name="upload" id="upload">
<input type="text" name="name" id="name">
<button name="submit" class="btn btn-primary" type="submit" value="submit">Upload File</button>
</form>
Thank you
i try to add a comment but i can't
first check if upload permission is on in php.ini
file_uploads = On
If it set to on check your upload directory which you added in uploader.php file and use if to check $_FILES['upload'] is empty
this is a simple code to uploader.php file
<?php
if(!empty($_FILES['upload']))
{
$path = "upload/"; /// directory to upload
$path = $path . basename( $_FILES['upload']['name']);
if(move_uploaded_file($_FILES['upload']['tmp_name'], $path)) {
echo "The file ". basename( $_FILES['upload']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
}else {
echo 'No file selected to upload ';
}
So I'm trying to set up an image upload from a form via php on my localhost and after running the code and connecting to the database okay, I'm getting the error for the upload. Since all of the other parts of the form are working after a section by section check, I'll just add the html for the upload input and its relevant php script.
<input type="file" name="image" id="image-select" />
And the portion of the php that has to deal with the image upload and verification after upload:
$image = $_FILES ['image']['name'];
$type = #getimagesize ($_FILES ['image']['tmp_name']);
//Never assume image will upload okay
if ($_FILES['image']['error'] !== UPLOAD_ERR_OK) {
die("Upload failed with error code " . $_FILES['image']['error']);
}
//Where the file will be placed
$target_path = "uploads/";
// Add the original filename to target path
$path= $target_path . basename($image);
// Check if the image is invalid before continuing
if($type === FALSE || !($type[2] === IMAGETYPE_TIFF || $type[2] === IMAGETYPE_JPEG || $type[2] === IMAGETYPE_PNG)) {
echo '<script "text/javascript">alert("This is not a valid image file!")</script>';
die("This is not a valid image file!");
} else {
move_uploaded_file($_FILES['image']['tmp_name'], $path);
}
So error appears once the code hits the upload process. I was attempting to upload a small PNG file The relevant code I added is also in their respective orders when they appear in the script.
can you please put error here. If error means that after submit page file is not being upload. then please check your form enctype. see below an example
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="image" id="image-select" />
<input type="submit" value="Submit">
</form>
Just a wild stab in the dark here as you haven't provided your form tag but you have remembered the enctype attribute haven't you?
Sorry I don't have 50 reputation otherwise I would ask this as a comment.
<form enctype='multipart/form-data' action=''>
<input type="file" name="image" id="image-select" />
</form>
Also you should check if the file uploaded OK before calling getimagesize() (not that this would be the source of your issue)
if you are using PHP5 and Imagick, then you can try to use something like the following:
$image->readImageFile($f);
I am writing an app from which user will upload files on the server. I have found a php script from internet but I don't know how am I going to tell the script where to upload the data. This might be a silly question but I am no PHP programmer. I am using this php script in my java code.
Here is the script.
<?php
$filename="abc.xyz";
$fileData=file_get_contents('php://input');
echo("Done uploading");
?>
Regards
This is a terrible way of uploading files, you are much better off using a form and the $_FILES superglobal.
Take a look at the W3Schools PHP File Upload Tutorial; please read all of it. For further reading take a look at the PHP Manual pages on file upload.
The file input type will create the upload box in the html form:
<form action="upload_file.php" method="post"
enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" id="file"><br>
<input type="submit" name="submit" value="Submit">
</form>
After error checking and validating that the file is what you are expecting (very important: allowing users to upload anything to your server is a huge security risk), you can move the uploaded file to your final destination on the server in PHP.
move_uploaded_file($_FILES["file"]["tmp_name"], "upload/abc.xyz");
The filename is actualy the file path along with the name of the new file, set the path there and a file will be created with write permissions.
Make sure you give the servers full path not the relative one and that you have the required permission to create a file there.
Always refer to the PHP Manual
Here's a basic example to get you started:
HTML:
<html>
<body>
<form enctype="multipart/form-data" action="upload.php" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
Choose a file to upload: <input name="uploaded_file" type="file" />
<input type="submit" value="Upload" />
</form>
</body>
</html>
PHP:
<?php
//Сheck that we have a file
if((!empty($_FILES["uploaded_file"])) && ($_FILES['uploaded_file']['error'] == 0)) {
//Check if the file is JPEG image and it's size is less than 350Kb
$filename = basename($_FILES['uploaded_file']['name']);
$ext = substr($filename, strrpos($filename, '.') + 1);
if (($ext == "jpg") && ($_FILES["uploaded_file"]["type"] == "image/jpeg") &&
($_FILES["uploaded_file"]["size"] < 350000)) {
//Determine the path to which we want to save this file
$newname = dirname(__FILE__).'/upload/'.$filename;
//Check if the file with the same name is already exists on the server
if (!file_exists($newname)) {
//Attempt to move the uploaded file to it's new place
if ((move_uploaded_file($_FILES['uploaded_file']['tmp_name'],$newname))) {
echo "It's done! The file has been saved as: ".$newname;
} else {
echo "Error: A problem occurred during file upload!";
}
} else {
echo "Error: File ".$_FILES["uploaded_file"]["name"]." already exists";
}
} else {
echo "Error: Only .jpg images under 350Kb are accepted for upload";
}
} else {
echo "Error: No file uploaded";
}
?>
Refer to the documention for more information.
Hope this helps!
Below is my code where the user can upload a file. What I want to know is that is there a way so that via server side is there a way to first of all restrict the file formats of the files to jpeg and png only and then when the user clicks on the submit button, if the file format is correct then display an alert on the same page stating "File is correct" else display an alert stating "File is incorrect".
Can somebody please provide coding if they know how to do this. Thank you and any help will be much appreciated :)
<form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post"
enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" id="file" />
<br />
<input type="submit" name="submit" value="Submit" />
</form>
</body>
</html>
A code for a total check of file uploads, you'll have to change $allowedtypes though. (Copied instead of linking because it was from a non-English site)
<?php
if(isset($_POST["submit"])){
$allowedtypes=array("jpg"=>true,"png"=>true,"gif"=>true,"txt"=>true);
$filename = $_FILES['file1']['name'];
$source = $_FILES['file1']['tmp_name'];
$file_size=$_FILES['file1']['size'];
$saveloc = "uploads/" . $filename;
$maxfilesize=1024*1024*10;
$nameext=explode(".",$filename);
if(preg_match('/^[A-Za-z0-9\-\_]{1,}\.[a-zA-Z0-9]{0,4}$/',$filename)){
if(!empty($allowedtypes[strtolower($nameext[1])]) && $allowedtypes[strtolower($nameext[1])]===true){
if($file_size<=$maxfilesize){
if(!file_exists($saveloc)){
if(move_uploaded_file($source, $saveloc)) {
chmod($saveloc,644);
echo "Successful upload. <a href='".$saveloc."'>Fájl megtekintése</a>";
}
else echo "Cannot move";
}
else echo "Existing file";
}
else echo "Too big file";
}
else echo "Not allowed extension";
}
else echo "Only alphanumeric files allowed";
}
else echo "<form method='post' enctype='multipart/form-data' action='secureupload.php'> File: <input type='file' name='file1' /><br /><input
name='MAX_FILE_SIZE' type='hidden' value='10485760' /> <input type='submit' value='Upload' name='submit' /></form>";
?>
You are talking about server side handler and write 'alert'...khm...
If u want to do stuff via server-side, then use php handler
http://php.net/manual/en/features.file-upload.post-method.php
If u want to do stuff via client-side, use javascript events, e.g on change event
<script>
function check() {
var file = document.getElementById('file').value;
var temp = file.split(/\.+/).pop();
alert(temp);
}
</script>
<input type="file" name="file" id="file" onchange="check();" />
You have file extension in temp var.
There are PHP functions to do this. You want to look at mime_content_type and finfo_file. These are built-in PHP commands that allow you to interpret that actual file type of a file being uploaded. You can then filter the mime types to only .gif/.jpg/etc. You want to check the mime types over the file name because the file name can be changed to mask the actual file type. If you want code samples, there are plenty on those pages as well as some excellent user-provided alternatives.
Something like this at the top of your file should work:
<?php
foreach ($_FILES as $file)
{
$tmp = explode(".", $file["tmp_name"]);
if (!in_array($tmp[count($tmp)-1], array("jpeg", "png"), true))
die("<script>alert('File is incorrect');</script>");
}
echo "<script>alert('File is correct');</script>";
?>
I am building a php application.
I can easily upload an image or any other type of data, but not a .jar. Below my code:
Upload.php
<form action="getfile.php" method="post" name="uploadForm" id="uploadForm" enctype="multipart/form-data" ><br>
<?php echo gettext("Image "); ?>
<input name="imagen" value="" type="file" id="imagen" />
<?php echo gettext("Jar "); ?>
<input name="jarFile" value="" type="file" id="jarFile" />
</form>
getfile.php
$fileName = $_FILES['jar']['name'];
$fileType = $_FILES['jar']['type'];
//Check the extension
if (!strpos($fileType, "jar") ) {
echo gettext("The simulation must be jar extension. Try again.");
}else{
if (move_uploaded_file($_FILES['jar']['tmp_name'], $path)){
echo gettext("Simulation stored succesfully.");
}else{
echo gettext("Something happened. Try again. ");
}
}
For images I am following the same aproach, but when I try to upload a jar file, I am always getting the error
The simulation must be jar extension. Try again
and $fileType is empty. Is there some restriction at this point? Am I missing something??
Thanks in advance
The type property is unreliable (and populated by the browser). Your best bet is to retrieve the MIME file type:
$fhandle = finfo_open(FILEINFO_MIME);
$mime_type = finfo_file($fhandle, $_FILES['jar']['tmp_name']);
The $mime_type should be application/java-archive.
PHP >= 5.3.0