I ma pretty sure I need something like a preg_replace in this situation but I am not sure and if so where to put it. I have a page that allows people to search an employee directory (PHP and MSSQL). They can search by last name, building or by department. the last name and building are fine but I have the problem with three of our departments, two have an & in them (ie. Grants & Planning) and when you click on that department it doesn't return any results and I think it is because it is not recognizing the "& planning" as part of a whole string. The other problem I have is that I have one department that has a ' in it and it throws an error
PHP Warning: mssql_query() [function.mssql-query]: message: Line 1: Incorrect syntax near 's'. (severity 15) in C:\Inetpub\wwwroot\DACC\directory\dept.php on line 179
*PHP Warning: mssql_query() [function.mssql-query]: message: Unclosed quotation mark before the character string ' ORDER BY Lastname'. (severity 15) in C:\Inetpub\wwwroot\DACC\directory\dept.php on line 179*
Line 179 is this...
$query = mssql_query("SELECT * FROM directory WHERE Displayname = '$department' ORDER BY Lastname");
Here is the rest of the code for the query page for by department.... if anyone can help me I would greatly appreciate it!
`
$department = $_GET['dept'];
// This will evaluate to TRUE so the text will be printed.
if (isset($department)) {
$query = mssql_query("SELECT * FROM directory WHERE Displayname = '$department' ORDER BY Lastname");//$query = mssql_query("SELECT * FROM directory WHERE department IN (SELECT id FROM departments WHERE name='$department') ORDER BY Lastname");
$query2 = mssql_query(
"SELECT TOP 1 directory.FirstName, directory.Lastname, directory.email,
directory.phone, directory.office, directory.title, directory.displayname, departments.id AS dept_id, departments.name AS dept_name, departments.url AS dept_url
FROM directory
INNER JOIN departments on directory.displayname = departments.name
WHERE directory.displayname = '$department'
ORDER BY directory.LastName");
$numofrows = #mssql_num_rows($query);
// Check if there were any records
if (!mssql_num_rows($query)) {
echo 'No records found';
echo '<br />Go Back';
} else {
while($row1 = mssql_fetch_array($query2))
{
$dept_var = $row1['dept_name'];
$dept_id = $row1['dept_id'];
$dept_url = $row1['dept_url'];
print "<h3>$dept_var</h3>";
}
print "<table id=\"directory_table\" width=\"480\">
<tr>
<th>Name</th>
<th>Email</th>
<th>Phone</th>
<th>Office</th>
<th>Title</th>
</tr>";
for($i = 0; $i < $numofrows; $i++)
{
$row = mssql_fetch_array($query);
if($i % 2)
{
print '<tr bgcolor="#ffffff">';
}
else
{
print '<tr bgcolor="#eeeeee">';
}
print "<td>" . $row['Firstname'] . " " . $row['Lastname'] . " </td>";
print "<td>" . $row['email']. " </td>";
print "<td>" . $row['phone'] . " </td>";
print "<td>" . $row['Office'] . " </td>";
print "<td>" . $row['Title'] . " </td>";
print "</tr>";
}
print "</table>";
}
// Free the query result
mssql_free_result($query);
}
else
print "No Search Defined";
?>
EDITED to show changes
ok tried this:
$serverName = "localhost"; //serverName\instanceName
$connectionInfo = array( "Database"=>"DACC", "UID"=>"daccweb", "PWD"=>"go");
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn ) {
echo "Connection established.<br />";
}else{
echo "Connection could not be established.<br />";
die( print_r( sqlsrv_errors(), true));
}
//$conn = sqlsrv_connect("connection string here");
$queryParams = array($department);
//Selector links
print "Go back to main search<br />";
print "<u>Search for Employees:</u><br /><br />\n";
print "<br />";
//$officeloc = $_GET['building'];
$department = $_GET['dept'];
// This will evaluate to TRUE so the text will be printed.
if (isset($department)) {
$query = sqlsrv_query($conn, "SELECT * FROM directory WHERE Displayname = ? ORDER BY Lastname", $params);
$query2 = sqlsrv_query($conn, "SELECT TOP 1 directory.FirstName, directory.Lastname, directory.email,
directory.phone, directory.office, directory.title, directory.displayname,
departments.id AS dept_id, departments.name AS dept_name, departments.url AS dept_url
FROM directory
INNER JOIN departments on directory.displayname = departments.name
WHERE directory.displayname = ?
ORDER BY directory.LastName", $params);
NEW EDIT
query runs but doesn't echo/print results
$query = sqlsrv_query($conn, "SELECT * FROM directory WHERE Displayname = ? ORDER BY Lastname", $params);
$query2 = sqlsrv_query($conn, "SELECT TOP 1 directory.FirstName, directory.Lastname, directory.email,
directory.phone, directory.office, directory.title, directory.displayname,
departments.id AS dept_id, departments.name AS dept_name, departments.url AS dept_url
FROM directory
INNER JOIN departments on directory.displayname = departments.name
WHERE directory.displayname = ?
ORDER BY directory.LastName", $params);
$numofrows = ##sqlsrv_has_rows($query);
// Check if there were any records
if (!#sqlsrv_has_rows($query)) {
echo 'No records found';
echo '<br />Go Back';
} else {
while($row1 = sqlsrv_fetch_array($query2))
{
$dept_var = $row1['dept_name'];
$dept_id = $row1['dept_id'];
$dept_url = $row1['dept_url'];
print "<h3>$dept_var</h3>";
//echo "</h3><br />";
}
print "<table id=\"directory_table\" width=\"480\">
<tr>
<th>Name</th>
<th>Email</th>
<th>Phone</th>
<th>Office</th>
<th>Title</th>
</tr>";
for($i = 0; $i < $numofrows; $i++)
{
$row = sqlsrv_fetch_array($query);
if($i % 2)
{
print '<tr bgcolor="#ffffff">';
}
else
{
print '<tr bgcolor="#eeeeee">';
}
print "<td>" . $row['Firstname'] . " " . $row['Lastname'] . " </td>";
print "<td>" . $row['email']. " </td>";
print "<td>" . $row['phone'] . " </td>";
print "<td>" . $row['Office'] . " </td>";
print "<td>" . $row['Title'] . " </td>";
print "</tr>";
}
print "</table>";
}
// Free the query result
sqlsrv_free_stmt($query);
}
else
print "No Search Defined";
You can use SQL parameters in PHP and MSSQL, have a look at this:
http://blogs.msdn.com/b/sqlphp/archive/2008/09/30/how-and-why-to-use-parameterized-queries.aspx
Your parameter values will automatically be escaped without any work on your part.
You'll need to use the sqlsrv driver, see: http://www.php.net/manual/en/sqlsrv.setup.php
In order to get the number of rows we need to specify some query options as well. (Take a look at http://www.php.net/manual/en/function.sqlsrv-num-rows.php and http://msdn.microsoft.com/en-us/library/hh487160.aspx)
$conn = sqlsrv_connect("connection string here");
$queryParams = array($department);
$queryOptions = array( "Scrollable" => "buffered" );
$query = sqlsrv_query($conn, "SELECT * FROM directory WHERE Displayname = ? ORDER BY Lastname", $queryParams, $queryOptions);
$query2 = sqlsrv_query($conn, "SELECT TOP 1 directory.FirstName, directory.Lastname, directory.email,
directory.phone, directory.office, directory.title, directory.displayname,
departments.id AS dept_id, departments.name AS dept_name, departments.url AS dept_url
FROM directory
INNER JOIN departments on directory.displayname = departments.name
WHERE directory.displayname = ?
ORDER BY directory.LastName", $queryParams, $queryOptions);
$numofrows = sqlsrv_num_rows($query);
Note that the order you build your array in must match the order in which the ? symbols appear in the query. As you only use one parameter in each query and they are the same, you only need to build one array.
You would then substitute all your mssql functions with sqlsrv functions, for a list of the functions and their usage, see the docs: http://www.php.net/manual/en/ref.sqlsrv.php
Related
I'm trying to compare products and I'm already finished. I just have a problem that my product features are not under the right product names because I need to fill the gaps between with empty <td></td>.
Here is my code from the function that fills the values.
function datatable($id)
{
$conn = connection();
$productPost = $_POST["product"];
$sqlSpecTitle = "Select title as title from product where uid = '$id'";
$resultTitle = mysqli_query($conn, sqlSpecTitle) or die("database error:" . mysqli_error($conn));
foreach ($productPost as $product)
{
$sqlSpecValue = "Select productname, title, value from text join product on uid = uid join feature on uid = uid where productname = '$product" and uid = '$id';
$resultValue = mysqli_query($conn, $sqlSpecValue or die("database error:" . mysqli_error($conn));
if(mysqli_num_row($resultValue) > 0
{
while($row = mysqli_fetch_assoc($resultTitle))
{
echo "<td>" . $row['title'] . "<td>";
}
while ($row = mysqli_fetch_assoc($resultValue))
{
if($row['value'] == null)
{
echo "<td>" . "empty" . "<td>";
}
else
{
echo "<td> . $row['value'] . "</td>";
}
}
}
}
}
The productnames are getting filled in another function that is as much the same.
function headerTable()
{
$conn = connection();
$productPost = $_POST["product"];
foreach ($productPost as $product) {
$sqlSpecValue = "SELECT productname, title, value from text
join product on uid = uid
join feature on uid = uid
where productname = '$product';
$resultValue = mysqli_query($conn, $sqlSpecValue) or die("database error:" . mysqli_error($conn));
$row = mysqli_fetch_assoc($resultValue);
echo "<td id='product'>" . $row['productname'] . "</td>";
}
}
You make a "join" over between your tables, so you only get data if you have something in "text" table.
Just switch to "right join" and it should work.
Iam trying to fetch the random data from mysql database, but it only fetches the same row on page refresh
I tried to run the query to get the random single row data from mysql and display on the webpage using php, but it only retrieving only the same row every time
$sql = "SELECT * FROM identity_explorer_demographics ORDER BY RAND() LIMIT 1
<?php
$link = mysqli_connect("host", "username", "password", "db_name");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
$sql = "SELECT * FROM identity_explorer_demographics ORDER BY RAND() LIMIT 1";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table>";
echo "<tr>";
echo "<th>email_md5</th>";
echo "<th>age_group </th>";
echo "<th>age</th>";
echo "<th>income</th>";
echo "<th>Income_group </th>";
echo "<th>gender</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['email_md5'] . "</td>";
echo "<td>" . $row['age_group'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['income'] . "</td>";
echo "<td>" . $row['Income_group'] . "</td>";
echo "<td>" . $row['gender'] . "</td>";
echo "</tr>";
}
echo "</table>";
// Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($link);
?>
I need the random row data to be displayed everytime the page is refreshed. Will really be helpful if anyone can suggest be the best solution.
$sql = "SELECT * FROM identity_explorer_demographics ORDER BY RAND()
LIMIT 1";
Change the line to
$randomv=rand(min,max);
$sql = "SELECT * FROM identity_explorer_demographics ORDER BY $randomv
LIMIT 1";
Here is my implementation in another case where I have to choose from a random id available - Yii 2 Framework
$prodcutids= \app\models\TblProduct::find()->all();
$targetproduct= ArrayHelper::map($prodcutids, 'id','id');
$productdetails= \app\models\TblProduct::findOne(['id'=>array_rand($targetproduct)]);
$productseriesname= \app\models\TblSeries::findOne(['id'=>$productdetails['Serie']]);
Or if you have an id column
$sql = "SELECT * FROM identity_explorer_demographics WHERE id=$randomv
LIMIT 1";
rand(min,max)
min specifies the lowest value that will be returned.
max specifies the highest value to be returned.
You mix it with PHP
$sql = 'SELECT * FROM `identity_explorer_demographics`';
//Perform query and parse result, E.G $sql = db::query($sql);
function getRandomRow($sql) {
$random_row = count(0, count($sql));
foreach($sql as $row => $result) {
if ($row == $random_row) {
return $row;
}
}
}
I have this code in my program:
<?php
session_start();
$_SESSION['user_id']=201102887;
$con = mysqli_connect('localhost', 'root', '');
if(!$con)
{
die("not ok");
}
mysqli_select_db($con,"uoh");
$q = "SELECT * FROM courses
INNER JOIN transfer_student_courses
ON transfer_student_courses.course_number = courses.course_number
INNER JOIN transfered_courses
ON transfer_student_courses.sn = transfered_courses.sn
AND transfer_student_courses.student_ID = " . $_SESSION['user_id'];
$result = mysqli_query($con , $q);
if($result){
echo "<table>";
echo "<tr>";
echo "<th>equivalent</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row["equivalent"]. "</td>";
echo "</tr>";
}
echo "</table>";
}
mysqli_select_db($con,"uoh");
$q = "SELECT * FROM courses
LEFT JOIN degree_plan
ON degree_plan.course_number = courses.course_number
LEFT JOIN student_record
ON courses.course_number = student_record.course_number
AND student_record.id = ". $_SESSION['user_id']."
WHERE degree_plan.major = 'COE'
ORDER BY term_no";
$result = mysqli_query($con , $q );
if($result){
echo "<table>";
echo "<tr>";
echo "<th>course</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row["code"]. "</td>";
echo "</tr>";
}
}
echo "</table>";
?>
I have two queries in this code, each of which give me a list of courses.
If a course appears in the first list, I do not want it to appear in the second list.
If you see the output of this code below, the first query gives me MATH 101, and the second query also gives me MATH 101.
I want MATH 101 to not appear in the second course list because it also appears in the first list.
How can I write a function in PHP language to do that?
Output:
equivalent
MATH 101
course
PHYS 101
CHEM 101
PE 101
IAS 101
MATH 101
ENGL 101
First of all, store all the equivalent courses in an array, say $equivalent array. And then in the second while loop use in_array() function to check if the course already got printed in the first table or not.
Here's the reference:
in_array()
So your code should be like this:
<?php
session_start();
$_SESSION['user_id']=201102887;
$con = mysqli_connect('localhost', 'root', '');
if(!$con){
die("not ok");
}
mysqli_select_db($con,"uoh");
$q = "SELECT * FROM courses INNER JOIN transfer_student_courses ON
transfer_student_courses.course_number=courses.course_number INNER
JOIN transfered_courses ON transfer_student_courses.sn=transfered_courses.sn
AND transfer_student_courses.student_ID = " . $_SESSION['user_id'];
$result = mysqli_query($con , $q) ;
$equivalent = array();
if($result){
echo "<table>";
echo "<tr>";
echo "<th>equivalent</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result)){
$equivalent[] = $row["equivalent"];
echo "<tr>";
echo "<td>" . $row["equivalent"]. "</td>";
echo "</tr>";
}
echo "</table>";
}
mysqli_select_db($con,"uoh");
$q = "SELECT * FROM courses
LEFT JOIN degree_plan ON degree_plan.course_number= courses.course_number
LEFT JOIN student_record ON courses.course_number= student_record.course_number
AND student_record.id= ". $_SESSION['user_id']."
WHERE degree_plan.major='COE' ORDER BY term_no";
$result = mysqli_query($con , $q ) ;
if($result){
echo "<table>";
echo "<tr>";
echo "<th>course</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result)){
if(in_array($row["code"], $equivalent)){
continue;
}
echo "<tr>";
echo "<td>" . $row["code"]. "</td>";
echo "</tr>";
}
}
echo "</table>";
?>
You could load the results of the first query into an array, then when you are displaying the results for the second query, before you display anything check if the result exists in your array, if it does, skip it.
So after your first query:
$equivalent = array(); // Setup a blank array to store the results
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row["equivalent"]. "</td>";
echo "</tr>";
$equivalent[] = $row['equivalent']; // Add the result into your array
}
Then in your courses portion of code:
while($row = mysqli_fetch_array($result))
{
if ( ! in_array($row['code'], $equivalent ) )
{
echo "<tr>";
echo "<td>" . $row["code"]. "</td>";
echo "</tr>";
}
}
This should stop the display of any entry that is in both result sets being displayed in the second.
HTH
Solution : in_array("word", $array)
Run a query get the result into an array :
while($row = mysqli_fetch_array($result))
{
arr1[]=$row["code"];
}
For the second query run the query and add reults as follows:
while($row = mysqli_fetch_array($result)){
if (in_array($row[code], $arr1))
{
//don't add to array2
}
else
{
arr2[] = $row["code"];
}
}
Then you may echo the elements as required.
I need to output a table based on two other tables as shown below:
case: there are two table "tbl_schedule" and "tbl_report"
this is my script:
$sql = mysql_query("SELECT*, count(*) as schedule_date FROM mst_schedule WHERE schedule_date LIKE '%$date' GROUP BY schedule_account") or die (mysql_error());
while ($data = mysql_fetch_array($sql)) {
$account = schAccount($data['schedule_account']);
$sql2 = mysql_query("SELECT * FROM trn_reportsch WHERE schedule_id='$data[schedule_id]' GROUP BY schedule_id");
echo "<tr>";
echo "<td>".ucfirst($account['admin_fullname'])."</td>";
while ($data2 = mysql_fetch_array($sql2)) {
echo "<td>".$data2['rating']."</td>";
}
echo "<td>".$data['schedule_date']."</td>";
echo "</tr>";
}
So far I don't get the desired output. How should I change the script?
Your code is almost correct.
Add following lines:
$sql = mysql_query("SELECT*, count(*) as schedule_date FROM mst_schedule WHERE schedule_date LIKE '%$date' GROUP BY schedule_account") or die(mysql_error());
while ($data = mysql_fetch_array($sql)) {
$account = schAccount($data['schedule_account']);
$sql2 = mysql_query("SELECT * FROM trn_reportsch WHERE schedule_id='$data[schedule_id]' GROUP BY schedule_id");
echo "<tr>";
echo "<td>" . ucfirst($account['admin_fullname']) . "</td>";
$bad = $good = $vGood = 0; // <-- ADD THIS LINE
while ($data2 = mysql_fetch_array($sql2)) {
if($data2['rating'] <=2){ // BAD
$bad++;
} else if($data2['rating'] <= 3){ // GOOD
$good++;
} else if($data2['rating'] > 3){ // VERY GOOD
$vGood++;
}
}
echo "<td>" . $bad . "</td>"; // Display the final value for bad
echo "<td>" . $good . "</td>"; // Display the final value for good
echo "<td>" . $vGood . "</td>"; // Display the final value for very good
echo "<td>" . $data['schedule_date'] . "</td>";
echo "</tr>";
}
I've got a CV database, you can see the fields below and they are pretty standard. Retrieval is done by a simple form sending the information into an SQL database.
I was happy with my simple system till I was flooded with over 500 applicants in my inbox. My previous system allowed me to view the applicants only one by one which would have taken forever...
What I'm trying to achieve is a simple backend page similar to the phpmyadmin of the table view. (no i don't want to just use phpmyadmin as i'd like to give the CV sifting task to other employees)
Basically the concept is to display the table like an excel, allow sorting by clicking on headers, pagination [20 rows per page] and a check box to delete row.
I'm ok with asking for some help as I have put alot of effort into trying to figure this out ;)
So far what i've got is:
The sorting works no problem, clicking on one of the headers spits out localhost/mena/new3.php?sort=fname to the address bar and parses the correct Sql query and sorts the page.
The pagination so far does not work. The page displays all 815 candidates. It is providing the numbered links 1-42 that when clicked on result in the address bar changing to localhost/new3.php?page=2 but 0 change.
Also for the life of me i can't see how to include the php delete into this..
9 yo pseudo code idea of it is :
//Input the rows from SQL
While($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $checkbox1
if checkbox1=true then mysqli_query($con,"DELETE FROM cv WHERE .$row[].");
echo "<td>" . $row['title'] .
My code so far:
<?php
$con=mysqli_connect("localhost","root","","test_db-jil");
// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Pagination
if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; };
$start_from = ($page-1) * 20;
// Sort, from headers.
if(isset($_REQUEST['sort'])){
if($_GET['sort'] == "title"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY title");
}
elseif($_GET['sort'] == "fname"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY fname");
}
elseif($_GET['sort'] == "lname"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY lname");
}
elseif($_GET['sort'] == "gender"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY gender");
}
elseif($_GET['sort'] == "dob"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY dob");
}
elseif($_GET['sort'] == "nationality"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY nationality");
}
elseif($_GET['sort'] == "language"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY language");
}
elseif($_GET['sort'] == "phone"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY phone");
}
elseif($_GET['sort'] == "email"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY email");
}
elseif($_GET['sort'] == "uni"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY uni");
}
elseif($_GET['sort'] == "prog"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY prog");
}
elseif($_GET['sort'] == "graddate"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY graddate");
}
elseif($_GET['sort'] == "startdate"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY startdate");
}
elseif($_GET['sort'] == "grad"){
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY grad");
}
else{
$result = mysqli_query($con,"SELECT * FROM cv ORDER BY fname");
}
}
else{ // Default if no parameters passed
$result = mysqli_query($con,"SELECT * FROM cv");
}
//Table of Content
echo "<table border='1'>
<tr>
<th><a href=new3.php?sort=title>Title</a></th>
<th><a href=new3.php?sort=fname>First Name</a></th>
<th><a href=new3.php?sort=lname>Last Name</a></th>
<th><a href=new3.php?sort=gender>Gender</a></th>
<th><a href=new3.php?sort=dob>Date Of Birth</a></th>
<th><a href=new3.php?sort=nationality>Nationality</a></th>
<th><a href=new3.php?sort=language>Language</a></th>
<th><a href=new3.php?sort=phone>Phone No</a></th>
<th><a href=new3.php?sort=email>Email</a></th>
<th><a href=new3.php?sort=uni>University</a></th>
<th><a href=new3.php?sort=prog>Program</a></th>
<th><a href=new3.php?sort=graddate>Graduated</a></th>
<th><a href=new3.php?sort=startdate>Start Date</a></th>
<th><a href=new3.php?sort=grad>Applying for</a></th>
<th>CV File</th>
</tr>";
//Input the rows from SQL
While($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['title'] . "</td>";
echo "<td>" . $row['fname'] . "</td>";
echo "<td>" . $row['lname'] . "</td>";
echo "<td>" . $row['gender'] . "</td>";
echo "<td>" . $row['dob'] . "</td>";
echo "<td>" . $row['nationality'] . "</td>";
echo "<td>" . $row['language'] . "</td>";
echo "<td>" . $row['phone'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['uni'] . "</td>";
echo "<td>" . $row['prog'] . "</td>";
echo "<td>" . $row['graddate'] . "</td>";
echo "<td>" . $row['startdate'] . "</td>";
echo "<td>" . $row['grad'] . "</td>";
echo "<td>" . $row['cvfilename'] ."</td>";
echo "</tr>";
}
echo "</table>";
//Get total count of rows then ceil divide by 20 as pages
$sql = "SELECT COUNT(*) as 'num' FROM cv";
$total_pages = $con->query($sql) or die(mysqli_error($connection));
$row = $total_pages->fetch_assoc();
$total_pages = ceil($row['num'] / 20);
for ($i=1; $i<=$total_pages; $i++) {
//Can I ?page= and ?sort= ??????
echo "<a href='new3.php?page=".$i."'>".$i."</a> ";
};
mysqli_close($con);
?>
Recap, please help me fix pagination, have it work with sort and finally add a delete check box to each row. :)
You know you can optimize that entire block of "else if" statements by just assigning the
$_GET to a variable:
$type = $_GET;
Then use that in your mysqli:
$result = mysqli_query($con, "SELECT * FROM cv ORDER BY $type");
To limit your results use LIMIT:
$result = mysqli_query($con, "SELECT * FROM cv ORDER BY $type LIMIT 20, $page");
20 = how many to return
$page = where you want the results to start from