Call a function outside of a dynamic jquery slider - php

Question

I am dynamically creating my sliders and in the "Slide" event and "Stop" event I would like to call a function that is defined in the non dynamic content. I can get the functions to work if I create them each time with the slider, but that seems like a lot of redundant code?
Non Dynamic function
$(document).ready(function() {
var converSecondsToMinutes;
convertSecondsToMinutes = function(secondsEntered){
var secondsEntered = secondsEntered;
var time = parseInt(secondsEntered,10);
time = time < 0 ? 0 : time;
var minutes = Math.floor(time / 60);
var seconds = time % 60;
minutes = minutes < 9 ? "0"+minutes : minutes;
seconds = seconds < 9 ? "0"+seconds : seconds;
var newTime = minutes+":"+seconds
console.log(newTime);
return newTime
}
});
Dynamic jQuery slider
<?php
query...
result...
for(...){
?>
<Script>
$( "#slider"+<?php echo $id; ?> ).slider({
animate: true ,
value: 0,
min: 0,
//dynamic grab this
max: <?php echo $playtime_seconds; ?>,
step: 0.01,
start: function( event, ui ) {
....
},
slide: function( event, ui ) {
audio = ....
audio.currentTime = ui.value;
progress_seconds = parseFloat(audio.currentTime.toFixed(2));
progress_seconds = $(function(){convertSecondsToMinutes(progress_seconds);});
$('#progress_seconds'+<?php echo $id; ?>).html(progress_seconds);
},
stop: function( event, ui ) {
....
}
}
});
});
}
I cut and paste the parts of the code that were important to the question.
This is the line that is not working: $('#progress_seconds'+).html(progress_seconds);

Answer 1

You edited just after I commented, so my comment no longer made sense, the $(function(){ part of your code is not necessary, try just using:
progress_seconds = converSecondsToMinutes(progress_seconds);
And spelling errors in code are a real issue with me, conver has a t at the end.
There is also no need to wrap your function in $(document).ready(), declare it like this:
function convertSecondsToMinutes(secondsEntered)
{
var time = ...
...
}