Find All images on a Page using preg_replace - php

Question

How can i find all image links using "preg_replace"? I've hard time understanding how to implement regex
what I've tried so far:
$pattern = '~(http://pics.-[^0-9]*.jpg)(http://pics.-[^0-9]*.jpg)(</a>)~';
$result = preg_replace($pattern, '$2', $content);

Answer 1

preg_replace(), as the name suggests, replaces something. You want to use preg_match_all().
<?php
// The \\2 is an example of backreferencing. This tells pcre that
// it must match the second set of parentheses in the regular expression
// itself, which would be the ([\w]+) in this case. The extra backslash is
// required because the string is in double quotes.
$html = "<b>bold text</b><a href=howdy.html>click me</a>";
preg_match_all("/(<([\w]+)[^>]*>)(.*?)(<\/\\2>)/", $html, $matches, PREG_SET_ORDER);
foreach ($matches as $val) {
echo "matched: " . $val[0] . "\n";
echo "part 1: " . $val[1] . "\n";
echo "part 2: " . $val[2] . "\n";
echo "part 3: " . $val[3] . "\n";
echo "part 4: " . $val[4] . "\n\n";
}

Answer 2

another easy way to find all images link from web page, use simple html dom parser
// Create DOM from URL or file
$html = file_get_html('http://www.google.com/');
// Find all images
foreach($html->find('img') as $element)
echo $element->src . '<br>';
this is so simple way to get all image link from any webpage.