Filling php array that has missing values - php

Question

I've a series of arrays with values that goes from 1 to 5. Almost every array has missing values, some even dont have any values. My objective is to fill the missing values with 0. All those arrays are stored into a multidimensional array.
My array looks like:
Array
(
[1] => Array
(
[0] => 1
[1] => 2
[2] => 3
)
[2] => Array
(
[0] => 1
[1] => 5
)
[3] => Array
(
[0] => (this array has no values)
)
[4] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
)
etc...
)
How it should be:
Array
(
[1] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 0
[4] => 0
)
[2] => Array
(
[0] => 1
[1] => 0
[2] => 0
[3] => 0
[4] => 5
)
[3] => Array
(
[0] => 0
[1] => 0
[2] => 0
[3] => 0
[4] => 0
)
[4] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
)
etc...
)
Any help would be appriciated!

Answer 1

For each of your subarrays loop through the numbers 1 to 5, and if that value exists set its key to be one less than its value:
$newarray = array();
foreach($arr as $key => $subarr) {
for ($i = 1; $i <= 5; $i++) {
if (in_array($i, $subarr)) $newarray[$key][$i - 1] = $i;
else $newarray[$key][$i - 1] = 0;
}
}
Where $newarray is your output and $arr is your input array.

Answer 2

You may want to note that PHP does not truly do multidimensional arrays. It only allows you to relate 2 flat arrays together which is not true multidimensionality.
This does not work and will produce results described above.
$menu[1] = "My Training"; //not $menu[1][0]
$menu[1][1] = "To Do List";
$menu[1][2] = "Catalog";
$menu[1][3] = "Self-Report";
$menu[1][4] = "Completions";
$menu[2] = "Manager";
$menu[2][1] = "Direct Reports";
$menu[2][2] = "Incompletes";
$menu[2][3] = "Completions";
$menu[3] = "Instructor";
$menu[3][1] = "My Classes";
$menu[3][2] = "Printables";
$menu[3][3] = "Qualifications";
This does work.
$menu[1] = "My Training"; //not $menu[1][0]
$submenu[1][1] = "To Do List";
$submenu[1][2] = "Catalog";
$submenu[1][3] = "Self-Report";
$submenu[1][4] = "Completions";
$menu[2] = "Manager";
$submenu[2][1] = "Direct Reports";
$submenu[2][2] = "Incompletes";
$submenu[2][3] = "Completions";
$menu[3] = "Instructor";
$submenu[3][1] = "My Classes";
$submenu[3][2] = "Printables";
$submenu[3][3] = "Qualifications";
$submenu is only related to $menu through the first key number as there are no first dimension values to $submenu.

Answer 3

Something like this (array_pad() won't do the trick). $myArray is your source array. Completed array is returned in $result:
$result = array();
foreach( $myArray as $subKey=>$subArray ) {
for( $i=0; $i<5; $i++ ) {
if( isset( $subArray[$i] )) {
$result[$subKey][$i] = $subArray[$i];
} else {
$result[$subKey][$i] = 0;
}
}
}
Note, we do copy of the array. You cannot fill array in-place.

Answer 4

It's been many years since I wrote any PHP but something like this might do the trick I guess?
for($i = 0; $i < 5; $i++)
{
if(empty($myArray[$i])
{
$myArray[$i] = 0;
}
}